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33.53-20.{300-[546-23.(78:76+70)]}
= 33.53-20.{300-[546-23.(72+1)]}
= 33.53-20.[300-(546-23.50)]
= 33.53-20.[300-(546-400)]
= 33.53-20.(300-146)
= 33.53-20.154
= 3375-3080
= 295.
\(3^3.5^3-20.\left\{300-\left[546-2^3.\left(7^8:7^6+7^0\right)\right]\right\}\)
= \(27.125-20.\left\{300-\left[546-8.50\right]\right\}\)
= \(3375-20.\left\{300-\left[546-400\right]\right\}\)
= \(3375-20.\left\{300-146\right\}\)
= \(3375-20.154=3375-3080=295\)
Đáp án hoàn toàn chính xác đấy.
Chúc bạn học tốt :))
33.53-20.{ 300-[ 546-23.(78:76+70)]}
=-98-20.{300- [546-8.50]}
=-98-20.{300-[546-400]}
=-98-20.{300-146}
=-98-20.154
=-3178
Chúc bạn học tốt Khanh Nhí
1
3\(^5\).5\(^3\)-20.{300-[546-2\(^3\).(7\(^8\):7\(^6\)+7\(^0\))]}
= 243.125-20.{300-[546-8.(49+1)
= 243.125-20.[300-(546-8.50)
= 243.125-20.[300-(546-400)
= 243.125-20.(300-146)
= 243.125-20.154
= 30375-3080
= 27295
32 . 53 - 20{300 - [540 - 23 (78 : 76 + 70)]}
= 9 . 125 - 20{300 - [540 - 8(72 + 70)]}
= 9 . 125 - 20{300 - [540 - 8(49 + 1)]
= 9 . 125 - 20{300 - [540 - 8.50]
= 9 . 125 - 20{300 - [540 - 400]}
= 9 . 125 - 20{300 - 140}
= 9 . 125 - 20. 160
= 1125 - 3200 = -2075
\(=9\cdot125-20\cdot\left\{300-\left[540-8\cdot\left(7^2+1\right)\right]\right\}\)
\(=1125-20\cdot\left\{300-\left[540-8\cdot\left(49+1\right)\right]\right\}\)
\(=1125-20\cdot\left[300-\left(540-8\cdot50\right)\right]\)
\(=1125-20\cdot\left[300-\left(540-400\right)\right]\)
\(=1125-20\cdot\left(300-140\right)\)
\(=1125-20\cdot160\)
\(=1125-3200\)
\(=-2075\)
\(b,2^3x5^3-3x\left\{400-\left[673-2^3x\left(7^8:7^6+7^0\right)\right]\right\}\)
\(=1000-3x\left\{400-\left[673-8x\left(7^2+1\right)\right]\right\}\)
\(=1000-3x\left\{400-\left[673-8x50\right]\right\}\)
\(=1000-3x\left\{400-\left[673-400\right]\right\}\)
\(=1000-3x\left\{400-273\right\}\)
\(=1000-3x127\)
\(=1000-381\)
\(=619\)
\(a,1968:16+5136:16-704:16\)
\(=\left(1968+5136-704\right):16\)
\(=6400:16\)
\(=400\)
\(\left(\frac{3}{7}+\frac{1}{2}\right)^2=\left(\frac{13}{14}\right)^2=\frac{169}{196}\)
\(\frac{5^4\cdot20^4}{25^5\cdot4^5}=\frac{5^4\cdot4^4\cdot5^4}{5^5\cdot5^5.4^5}=\frac{1}{100}\)
\(\left(\frac{3}{7}\right)^{21}:\left(\frac{9}{49}\right)^6=\left(\frac{3}{7}\right)^{21}:\left[\left(\frac{3}{7}\right)^2\right]^6=\left(\frac{3}{7}\right)^{21}:\left(\frac{3}{7}\right)^{12}=\left(\frac{3}{7}\right)^9\)
\(3-\left(-\frac{6}{7}\right)^0+\left(\frac{1}{2}\right)^2:2\)
\(=3-1+\frac{1}{4}:2=3-1+\frac{1}{8}=\frac{17}{8}\)
a,\(3^3.3^2-3^5+5^8.1-5^{12}:5^4\)
=\(3^5-3^5+5^8-5^8\)
=0
9!-8!-7! :\(8^2\)
=8!.9-8!-8!.8
=8!.(9-1-8)
=8!.0
=0
\(3^3\cdot5^3-20\cdot\left\{300-\left[546-2^3\cdot\left(7^8-7^6+7^0\right)\right]\right\}\)
\(=3^3\cdot5^3-20\cdot\left\{300-\left[546-2^3\cdot5647153\right]\right\}\)
\(=3^3\cdot5^3-20\cdot\left\{300-\left[546-45177224\right]\right\}\)
\(=3^3\cdot5^3-20\cdot\left\{300--45176678\right\}\)
\(=3^3\cdot5^3-20\cdot45176978\)
\(=3375-903539560\)
\(=-903536185\)
\(626500:\left\{50^2:\left[178-4\cdot\left(35-21:3\right)\right]\right\}\)
\(=626500:\left\{50^2:\left[178-4\cdot\left(35-7\right)\right]\right\}\)
\(=626500:\left\{50^2:\left[178-4\cdot28\right]\right\}\)
\(=626500:\left\{50^2:\left[178-112\right]\right\}\)
\(=626500:\left\{50^2:66\right\}\)
\(=626500:\frac{1250}{33}\)
\(=\frac{82698}{5}\)
CHUC BAN HOC TOT >.<