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e) \(\left(\sqrt{8}-3\sqrt{2}+\sqrt{10}\right).\left(\sqrt{2}-3\sqrt{0.4}\right)\)
\(a,\left(\frac{2\sqrt{3}-\sqrt{6}}{\sqrt{8}-2}-\frac{\sqrt{216}}{3}\right)\cdot\frac{1}{\sqrt{6}}\)
\(=\left(\frac{\sqrt{12}-\sqrt{6}}{2\left(\sqrt{2}-1\right)}-\frac{6\sqrt{6}}{3}\right)\cdot\frac{1}{\sqrt{6}}\)
\(=\left(\frac{\sqrt{6}\left(\sqrt{2}-1\right)}{2\left(\sqrt{2}-1\right)}-2\sqrt{6}\right)\cdot\frac{1}{\sqrt{6}}\)
\(=\left(\frac{\sqrt{6}}{2}-\frac{4\sqrt{6}}{2}\right)\cdot\frac{1}{\sqrt{6}}\)
\(=\frac{\sqrt{6}-4\sqrt{6}}{2}\cdot\frac{1}{\sqrt{6}}\)
\(=\frac{-3\sqrt{6}}{2}\cdot\frac{1}{\sqrt{6}}\)
\(=-\frac{3}{2}\)
a) ( \(\sqrt{12}\) + \(\sqrt{3}\) ) (\(\sqrt{27}\) - \(\sqrt{3}\) )
= (\(\sqrt{3}.\sqrt{4}\) + \(\sqrt{3}\) ) ( \(\sqrt{3}.\sqrt{9}\) - \(\sqrt{3}\) )
= \(\sqrt{3}\left(\sqrt{4}+1\right)\). \(\sqrt{3}\left(\sqrt{9}-1\right)\)
= \(\sqrt{3}.3.\sqrt{3}.2\)
= 3. 6 = 18
b) \(\left(5\sqrt{3}-2\sqrt{7}\right)\)\(\left(5\sqrt{3}+2\sqrt{7}\right)\)
=\(\left(5\sqrt{3}\right)^2\) \(-\left(2\sqrt{7}\right)^2\)
= 75 - 28 = 47
a) \(\sqrt{2}.\sqrt{98}=\sqrt{196}=14\)
b) \(\sqrt{75}:\sqrt{3}=\sqrt{25}=5\)
c) \(\sqrt{\left(3-\sqrt{11}\right)^2}=3-\sqrt{11}\)
d) \(\left(2\sqrt{7}+4\sqrt{3}\right).\sqrt{3}-\sqrt{84}=2\sqrt{21}+12-2\sqrt{21}=12\)
Nhớ tick
a/ \(\sqrt{2.98}=\sqrt{2.2.49}=\sqrt{2^2.7^2}=2.7=14\)
b/ \(\frac{\sqrt{75}}{\sqrt{3}}=\frac{\sqrt{25}.\sqrt{3}}{\sqrt{3}}=\sqrt{25}=5\)
c/ \(\sqrt{\left(3-\sqrt{11}\right)^2}=\left|3-\sqrt{11}\right|=\sqrt{11}-3\)
d/ \(\left(2\sqrt{7}+4\sqrt{3}\right)\sqrt{3}-\sqrt{84}\)
\(=2\sqrt{21}+4.3-2\sqrt{21}\)
\(=12\)
\(\sqrt{\left(\sqrt{3}-2\right)^2}+\sqrt{\left(3-\sqrt{3}\right)^2}\)
\(=\left|\sqrt{3}-2\right|+\left|3-\sqrt{3}\right|\)
\(=2-\sqrt{3}+3-\sqrt{3}\)
\(=5-2\sqrt{3}\)
\(-\sqrt{3}-\sqrt{3}=-2\sqrt{3}\)
Chứ cj