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Bai 2
-3,5.(2/7+5/7)+23/5
-3,5.1+23/5
-3,5+23/5
-35/10+23/5
-35/10+46/10
11/10
5. a, \(-\frac{3}{5}\cdot\frac{2}{7}+\left(-\frac{3}{5}\right)\cdot\frac{5}{7}+\frac{23}{5}\)
\(=-\frac{3}{5}\cdot\left(\frac{2}{7}+\frac{5}{7}\right)+\frac{23}{5}\)
\(=-\frac{3}{5}\cdot1+\frac{23}{5}\)
\(=\frac{23}{5}-\frac{3}{5}\)
\(=\frac{20}{5}\)
\(=4\)
b, \(1\frac{13}{15}\cdot0,75-\frac{\left(\frac{11}{20}+25\%\right)}{\frac{7}{5}}\)
\(=\frac{28}{15}\cdot\frac{3}{4}-\frac{\left(\frac{11}{20}+\frac{1}{4}\right)}{\frac{7}{5}}\)
\(=\frac{7}{5}-\frac{\left(\frac{11}{20}+\frac{5}{20}\right)}{\frac{7}{5}}\)
\(=\frac{7}{5}-\frac{\frac{4}{5}}{\frac{7}{5}}\)
\(=\frac{7}{5}-\frac{4}{7}\)
\(=\frac{49}{35}-\frac{20}{35}\)
\(=\frac{29}{35}\)
Bài 1 :
\(a)\frac{-17}{30}-\frac{11}{-15}+\left(-\frac{7}{12}\right)\)
\(=\frac{1}{6}+\left(-\frac{7}{12}\right)\)
\(=-\frac{5}{12}\)
\(b)-\frac{5}{9}+\frac{5}{9}:\left(1\frac{2}{3}-2\frac{1}{12}\right)\)
\(=-\frac{5}{9}+\frac{5}{9}:\left(\frac{5}{3}-\frac{25}{12}\right)\)
\(=-\frac{5}{9}+\frac{5}{9}:\left(-\frac{5}{12}\right)\)
\(=-\frac{5}{9}+\left(-\frac{2}{3}\right)\)
\(=-\frac{1}{9}\)
\(c)-\frac{7}{25}\times\frac{11}{13}+\left(-\frac{7}{25}\right)\times\frac{2}{13}-\frac{18}{25}\)
\(=-\frac{77}{325}+\left(-\frac{14}{325}\right)-\frac{18}{25}\)
\(=-\frac{7}{25}-\frac{18}{25}\)
\(=-1\)
Bài 1:
\(\frac{3}{5}+\frac{4}{15}=\frac{9}{15}+\frac{4}{15}=\frac{13}{15}\)
\(\frac{5}{6}:\frac{-7}{12}=\frac{5}{6}.\frac{-12}{7}=\frac{-60}{42}=\frac{-10}{7}\)
\(\frac{-21}{24}:\frac{-14}{8}=\frac{-21}{24}.\frac{-8}{14}=\frac{168}{336}=\frac{1}{2}\)
\(\frac{4}{5}:\frac{-8}{15}=\frac{4}{5}.\frac{-15}{8}=\frac{-60}{40}=\frac{-3}{2}\)
\(\frac{5}{12}-\frac{-7}{6}=\frac{5}{12}+\frac{7}{6}=\frac{5}{12}+\frac{14}{12}=\frac{19}{12}\)
\(\frac{-15}{16}.\frac{8}{25}=\frac{-120}{400}=\frac{-3}{10}\)
Bài 2 :
\(6\frac{4}{5}-\left(1\frac{2}{3}+3\frac{4}{5}\right)\)
\(=\frac{34}{5}-\left(\frac{5}{3}+\frac{19}{5}\right)\)
\(=\frac{34}{5}-\frac{5}{3}-\frac{19}{5}\)
\(=\left(\frac{34}{5}-\frac{19}{5}\right)-\frac{5}{3}\)
\(=3-\frac{5}{3}\)
\(=\frac{4}{3}\)
\(6\frac{5}{7}-\left(1\frac{2}{3}+2\frac{5}{7}\right)\)
\(=\frac{47}{7}-\left(\frac{5}{3}+\frac{19}{7}\right)\)
\(=\frac{47}{7}-\frac{5}{3}-\frac{19}{7}\)
\(=\left(\frac{47}{7}-\frac{19}{7}\right)-\frac{5}{3}\)
\(=4-\frac{5}{3}\)
\(=\frac{7}{3}\)
\(\frac{4}{19}.\frac{-3}{7}+\frac{-3}{7}.\frac{15}{19}+\frac{5}{7}\)
\(=\left(\frac{4}{19}+\frac{15}{19}\right).\frac{-3}{7}+\frac{5}{7}\)
\(=1.\frac{-3}{7}+\frac{5}{7}\)
\(=\frac{-3}{7}+\frac{5}{7}\)
\(=\frac{2}{7}\)
\(\frac{5}{9}.\frac{7}{13}+\frac{5}{9}.\frac{9}{13}-\frac{5}{9}.\frac{3}{13}\)
\(=\frac{5}{9}.\left(\frac{7}{13}+\frac{9}{13}-\frac{3}{13}\right)\)
\(=\frac{5}{9}.1\)
\(=\frac{5}{9}\)
a) 60-3(x-2)=51
3(x-2)=60-51
3(x-2)=9
x-2 = 9:3
x-2 = 3
x = 3+2
x 5
\(\text{A= 2+(-4)+(-6)+8+10+(-12)+(-14)+16+...+2010}\)
\(\text{A=[2+(-4)+(-6)+8] + [10+(-12)+(-14)+16] + ... + [2007+(-2008)+(-2009)+2010]}\)
\(\text{A= 0 + 0 + ... + 0}\)
\(\text{A= 0}\)
\(\text{B=1+(-3)+(-5)+7+9+(-11)+(-13)+15+...+2009}\)
\(\text{B=[1+(-3)+(-5)+7]+[9+(-11)+(-13)+15]+...+[2003+(-2005)+(-2007)+2009]}\)
\(\text{B=0 + 0 + ... + 0}\)
\(b=0\)
a) -5/7.7/10 - 3/11 : 6/5
= -1/2 - 5/22
= -8/11
b) 5/14.1/3.-4/15:5/7
= -2/63:5/7 = -2/45
c) 2 13/15.11/15 - 13/15 + 2 13/15.4/15
= 2 13/15.(11/15 + 4/15) - 13/15
= 2 13/15.1 - 13/15
= 2 13/15 - 13/15
= 2