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a)\(1,5:2,16=15:216=5:72\)
b)\(4\dfrac{2}{7}:\dfrac{3}{5}=\dfrac{30}{7}:\dfrac{3}{5}=\dfrac{30}{7}.\dfrac{5}{3}=\dfrac{50}{7}=50:7\)
c)\(\dfrac{\dfrac{2}{9}}{0,31}=\dfrac{2}{9}:\dfrac{31}{100}=\dfrac{2}{9}.\dfrac{100}{31}=\dfrac{31}{450}=31:450\)
a) \(3,7:4,5=\dfrac{3,7}{4,5}=\dfrac{37}{45}\)
b) \(2\dfrac{1}{3}:4\dfrac{2}{3}=\dfrac{7}{3}:\dfrac{14}{3}=\dfrac{7}{3}\times\dfrac{3}{14}=\dfrac{1}{2}\)
c) \(\dfrac{3}{8}:0,7=\dfrac{3}{8}:\dfrac{7}{10}=\dfrac{3}{8}\times\dfrac{10}{7}=\dfrac{15}{28}\)
d) \(5\dfrac{1}{7}:2\dfrac{1}{3}=\dfrac{36}{7}:\dfrac{7}{3}=\dfrac{36}{7}\times\dfrac{3}{7}=\dfrac{108}{49}\)
a, Ta có : \(1,2=\dfrac{12}{10}=\dfrac{6}{5}\) ; \(3,36=\dfrac{84}{25}\)
=> \(1,2:3,36=\dfrac{6}{5}:\dfrac{84}{25}=\dfrac{5}{14}\)
b, Ta có : \(3\dfrac{1}{7}:2\dfrac{5}{14}=\dfrac{22}{7}:\dfrac{33}{14}=\dfrac{4}{3}\)
c,\(\dfrac{3}{8}:0,54=\dfrac{3}{8}:\dfrac{27}{50}=\dfrac{25}{36}\)
a) \(1,2:3,36=\dfrac{6}{5}:\dfrac{84}{25}=\dfrac{5}{14}\)
b)\(3\dfrac{1}{7}:2\dfrac{5}{14}=\dfrac{22}{7}:\dfrac{33}{14}=\dfrac{4}{3}\)
c)\(\dfrac{3}{8}:0,54=\dfrac{3}{8}:\dfrac{27}{50}=\dfrac{25}{36}\)
f, \(\dfrac{2^9.4^{10}}{8^8}=\dfrac{2^9.\left(2^2\right)^{10}}{\left(2^3\right)^8}=\dfrac{2^9.2^{20}}{2^{24}}=\dfrac{2^{29}}{2^{24}}=2^5=32\)
a: \(=\left(\dfrac{1}{3}-\dfrac{4}{3}\right)+\dfrac{14}{25}+\dfrac{11}{25}+\dfrac{2}{7}=\dfrac{2}{7}\)
b: \(=\dfrac{3}{7}-\dfrac{5}{2}-\dfrac{3}{5}+\dfrac{4}{7}+\dfrac{3}{2}-\dfrac{2}{5}=1-1-1=-1\)
c: \(=\dfrac{4}{25}+\dfrac{7}{5}\cdot\dfrac{5}{2}-2=\dfrac{4}{25}+\dfrac{7}{2}-2=\dfrac{83}{50}\)
a: \(\dfrac{3.7}{4.5}=\dfrac{37}{45}\)
b: \(=\dfrac{4}{35}\cdot\dfrac{5}{2}=\dfrac{10}{70}=\dfrac{1}{7}\)
c: \(=\dfrac{7}{3}\cdot\dfrac{4}{3}=\dfrac{28}{9}\)
d: \(=\dfrac{22}{7}:\dfrac{5}{3}=\dfrac{22}{7}\cdot\dfrac{3}{5}=\dfrac{66}{35}\)
e: \(=2:\dfrac{1}{200}=\dfrac{400}{1}\)
f: =13/5:37/10=13/5x10/37=26/37