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a. 4 . 5 + 28 : 7 - 620 : 618
= 20 + 4 - 62
= 20 + 4 - 36
= .... ( tự làm )
b. 718 : 716 + 22 . 33
= 72 + 25
= 49 + 32
= ...
c. 59 : 57 + 12 . 3 + 70
= 52 + 36 + 0
= ...
d. 205 - [ 1200 - ( 42 - 2 . 3 )3 ]
= 205 - [ 1200 - 103 ]
= 205 - [ 1200 - 100 ]
= ...
e. 695 - [ 200 - ( 11 - 1 )2 ]
= 695 - [ 200 - 102 ]
= 695 - [ 200 - 100 ]
= ...
#A?m?
sai hết r bạn ơi
phải là
a)28
b)157
c)62
d)5
e)598
ko có số âm đâu
\(\frac{3^2.4^2.2^{32}}{11.2^{13}.4^{11}-16^9}=\frac{3^2.2^4.2^{32}}{11.2^{13}.2^{22}-2^{36}}=\frac{3^2.2^{36}}{11.2^{35}-2^{36}}=\frac{3^2.2^{36}}{2^{35}.\left(11-2\right)}=\frac{9.2}{9}=2\)
\(\frac{2^{19}.27^3+15.4^9.9^4}{6^9.2^{10}+12^{10}}=\frac{2^{19}.3^9+3.5.2^{18}.3^8}{6^9.2^{10}+6^{10}.2^{10}}=\frac{2^{19}.3^9+3^9.5.2^{18}}{6^9.2^{10}.\left(1+6\right)}=\frac{2^{18}.3^9.\left(2+5\right)}{2^9.3^9.2^{10}.7}=\frac{2^{18}.7}{2^{19}.7}=\frac{1}{2}\)
Ta có \(\frac{3.4.2^{16}}{11.2^{12}.4^{11}-16^9}\)
\(=\frac{3.2^2.2^{16}}{11.2^{12}.2^{22}-2^{36}}\)
\(=\frac{3.2^{18}}{11.2^{34}-2^{36}}\)
\(=\frac{3.2^{18}}{2^{34}.\left(11-2^2\right)}\)
\(=\frac{3.2^{18}}{2^{34}.5}\)
\(=\frac{3}{2^{16}.5}\)
Ta có : \(\frac{3.4.2^{16}}{11.2^{12}.4^{11}-16^9}=\frac{3.2^2.2^{16}}{11.2^{12}.2^{22}-2^{36}}\)\(=\frac{3.2^{18}}{11.2^{34}-2^{36}}=\frac{2^{18}.3}{2^{34}.\left(11-2^2\right)}\)\(=\frac{2^{18}.3}{2^{34}.7}=\frac{3}{2^{16}.7}\)