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Tìm y :
( y + 1/3 ) + ( y + 1/9 ) + ( y + 1/27 ) + ( y + 1/81 ) = 56/81
y + 1/3 + y + 1/9 + y + 1/27 + y + 1/81 = 56/81
y x 4 + ( 1/3 + 1/9 + 1/27 +1/81 ) = 56/81
y x 4 + ( 27/81 + 9/81 + 3/81 + 1/81 ) = 56/81
y x 4 + 40/81 = 56/81
y x 4 = 56/81 - 40/81
y x 4 = 16/81
y = 16/81 : 4
y = 4/81
b) y + y : 0,5 + y : 0,25 + y : 0,125 = 15
yx1+yx2+yx4+yx8=15
yx(1+3+4+8)=15
yx15=15
y=15:15
y=1
- Ta có: \(\frac{3}{x}+\frac{y}{3}=\frac{5}{6}\)
\(\Leftrightarrow\frac{3}{x}=\frac{5}{6}-\frac{y}{3}\)
\(\Leftrightarrow\frac{3}{x}=\frac{5-2y}{6}\)
\(\Leftrightarrow x.\left(5-2y\right)=18=1.18=\left(-1\right).\left(-18\right)=2.9=\left(-2\right).\left(-9\right)=3.6=\left(-3\right).\left(-6\right)\)
- Vì \(5-2y\)là lẻ \(\Rightarrow\)\(5-2y\in\left\{-9,-3,-1,1,3,9,\right\}\)
- Ta có bảng giá trị:
\(5-2y\) | \(-9\) | \(-3\) | \(-1\) | \(1\) | \(3\) | \(9\) |
\(x\) | \(-2\) | \(-6\) | \(-18\) | \(18\) | \(6\) | \(2\) |
\(y\) | \(7\) | \(4\) | \(3\) | \(2\) | \(1\) | \(-2\) |
\(\left(TM\right)\) | \(\left(TM\right)\) | \(\left(TM\right)\) | \(\left(L\right)\) | \(\left(L\right)\) | \(\left(L\right)\) |
Vậy \(\left(x,y\right)\in\left\{\left(-2,7\right);\left(-6,4\right);\left(-18,3\right)\right\}\)
!@#$!@$! ^_^ Chúc bn hok tốt ^_^ @#$!#$!
y x 0,3 + y x 0,2 + y x 0 , 5 = 3570
y x ( 0,3 + 0,2 + 0,5 ) = 3570
y x 1 = 3570
y = 3570 : 1
y = 3570
Vậy y = 3570
a, ( 5 x y - 15 ) : 5 = 0
( 5 x y - 15 ) = 0 x 5
( 5 x y - 15 ) = 0
5 x y = 0 + 15
5 x y = 15
y = 15 : 5
y = 3
b. 14 x ( y - 7 ) = 210
( y - 7 ) = 210 : 14
( y - 7 ) = 15
y = 15 + 7
y = 22
c. 84 - 4 x ( 2 x y + 1 ) = 48
4 x ( 2 x y + 1 ) = 84 - 48
4 x ( 2 xy + 1 ) = 36
( 2 x y + 1 ) = 36 : 4
( 2 x y + 1 ) = 9
2 x y = 9 - 1
2 x y = 8
y = 8 : 2
y = 4
d. 5 x y - 2009 = 1201
5 x y = 1201 + 2009
5 x y = 3210
y = 3210 : 5
y = 642
a. (5.y-15):5=0
=> 5.y-15 = 0
=> 5.y = 15
=> y = 3
b. 14.(y-7) = 210
=> y-7 = 15
=> y = 22
c. 84-4.(2.y+1)=48
=> 4.(2.y+1) = 36
=> 2.y+1 = 9
=> 2.y = 8
=> y = 4
d) 5.y-2009 = 1201
=> 5.y = 3210
=> y = 642
\(\frac{-48}{x}=\frac{y}{-72}=\frac{36}{z+1}=\frac{-3}{4}\)
Ta có: \(\frac{36}{z+1}=\frac{-3}{4}\)
\(\Leftrightarrow z+1=\frac{36.4}{-3}=-48\)
\(\Leftrightarrow z=-49\)
Lại có: \(\frac{y}{-72}=\frac{36}{-48}\)
\(\Leftrightarrow y=\frac{\left(-72\right).36}{\left(-48\right)}=54\)
Ta có: \(\frac{-48}{x}=\frac{54}{-72}\)
\(\Leftrightarrow x=\frac{\left(-48\right)\left(-72\right)}{54}=64\)
Vậy ...
P/s: Hoq chắc :)
Y : 0,25 + Y x 8 + Y : 0,5 = 0,14
=>Y :\(\frac{1}{4}\)+ Y x 8 + Y :\(\frac{1}{2}\)=0,14
==>Y x 4+ Y x 8 + Y x 2=0,14
==>Y x(4+8+2)=0,14
Y x 14=0,14
==>Y=0,14:14
Y=0,01
y x 7,26 + y x 3,74 - y = 2019
y x ( 7,26 + 3,74 - 1 ) = 2019
y x 10 = 2019
y = 2019 : 10
y = 201,9