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18 tháng 9 2018

\(\left(a+b+c\right)\left(ab+bc+ca\right)-abc\)

\(=\left(a+b+c\right)\left(ab+bc\right)+\left(a+b+c\right)ac-abc\)

\(=\left(ab+b^2+bc\right)\left(a+c\right)+\left(a+c\right)ac+abc-abc\)

\(=\left(a+c\right)\left(ab+b^2+bc+ac\right)\)

\(=\left(a+b\right)\left(b+c\right)\left(c+a\right)\)

5 tháng 7 2018

a)  \(bc\left(b+c\right)+ca\left(c-a\right)-ab\left(a+b\right)\)

\(=bc\left(b+c\right)+ca\left(c-a\right)-ab\left[\left(b+c\right)-\left(c-a\right)\right]\)

\(=bc\left(b+c\right)+ca\left(c-a\right)-ab\left(b+c\right)+ab\left(c-a\right)\)

\(=\left(b+c\right)\left(bc-ab\right)+\left(c-a\right)\left(ca+ab\right)\)

\(=\left(b+c\right)\left(c-a\right)b+\left(c-a\right)\left(b+c\right)a\)

\(=\left(b+a\right)\left(c-a\right)\left(c+b\right)\)

b)  \(a^2\left(b-c\right)+b^2\left(c-a\right)+c^2\left(a-b\right)\)

\(=a^2\left(b-c\right)+b^2\left(c-a\right)-c^2\left[\left(b-c\right)+\left(c-a\right)\right]\)

\(=a^2\left(b-c\right)+b^2\left(c-a\right)-c^2\left(b-c\right)-c^2\left(c-a\right)\)

\(=\left(b-c\right)\left(a^2-c^2\right)+\left(c-a\right)\left(b^2-c^2\right)\)

\(=\left(b-c\right)\left(a-c\right)\left(a+c\right)+\left(c-a\right)\left(b-c\right)\left(b+c\right)\)

\(=\left(b-c\right)\left(c-a\right)\left(b+c-a-c\right)\)

\(=\left(b-a\right)\left(b-c\right)\left(c-a\right)\)

13 tháng 11 2016

a) =a2b - ab2 + b2c - bc2 + a2c - ac2

= abc +a2b - ab2 +b2c - bc2 +a2c - ac2 - abc

= (a2b - abc) - (ab2 - b2c) - (bc2 - ac2) - (a2c - abc)

= ab(a - c) - b2(a - c) - c2(b - a) - ac(a - b)

= [ab(a - c) - b2(a - c)] + [c2(a - b) - ac(a - b)]

= (a - c)(ab - b2) + (a - b)(c2 - ac)

= b(a - c)(a - b) + c(a - b)(c - a)

= b(a - c)(a - b) - c(a - b)(a - c)

= (a - c)(a - b)(b - c)

b)= ab2 - ac2 + bc2 - a2b + a2c - b2c

= abc + ab2 - ac2 + bc2 - a2b + a2c - b2c - abc

= (ab2 - abc) + (abc - ac2) - (b2c - bc2) - (a2b - a2c)

= ab(b - c) + ac( b - c) - bc(b - c) - a2(b - c)

= (b - c)(ab + ac - bc - a2)

= (b - c) [(ab - bc) + (ac - a2)]

= (b - c) [b(a - c) +a(c - a)]

= (b - c) [b(a - c) - a(a - c)]

= (b - c)(a - c)(b - a)

c) = ab3 - ac3 + bc3 - a3b + a3c - b3c

= a2bc + ab2c + abc2 + a3b + a2b2 + a2bc - a3c - a2bc - a2c2 + a2c2 + abc2 + ac3 - a2b2

- ab3 - ab2c + ab2c + b3c + b2c2 - abc2 - b2c2 - bc3 - a2bc - ab2c - abc2

= (a2bc + ab2c + abc2) +(a3b + a2b2 + a2bc) - (a3c - a2bc - a2c2) +(a2c2 + abc2 +ac3) -

(a2b2 + ab3 + ab2c) + (ab2c + b3c + b2c2) - (abc2 + b2c2 + bc3) - (a2bc + ab2c + abc2)

= abc(a + b + c) +a2b(a + b + c) - a2c(a + b + c) + ac2(a + b + c) - ab2(a + b + c) + b2c(a + b + c) - bc2(a + b + c) - abc(a + b+ c)

= (a +b +c)(abc + a2b - a2c + ac2 - ab2 + b2c - bc2 - abc)

= (a + b+ c) [(a2b - abc)+(abc - bc2) - (a2c - ac2) - (ab2 - b2c)]

= (a + b + c) [ab(a - c) + bc(a - c) - ac(a - c) - b2(a - c)]

= (a + b + c)(a - c)(ab + bc - ac - b2)

= (a +b + c)(a - c) [(ab - ac) - (b2 - bc)]

= (a + b+ c)(a - c) [a(b - c) - b(b - c)]

= (a + b + c)(a - c)(b - c)(a - b)

 

 

11 tháng 8 2017

trời ơi sao câu c dài thế !!!!! Tui có bài giống vậy nhưng nó ra p/số, còn phải ghi nhiều hơn huhu

30 tháng 9 2015

 

a) x3+y3+z3-3xyz

=(x+y)3+z3-3x2y-3xy2-3xyz

=(x+y+z).[(x+y)2+(x+y).z+z2]-3xy.(x+y+z)

=(x+y+z)(x2+2xy+y2+zx+zy+z2)-3xy.(x+y+z)

=(x+y+z)(x2+2xy+y2+zx+zy+z2-3xy)

=(x+y+z)(x2+y2+zx+zy+z2-zy)

 

b)a2(b-c)+b2(c-a)+c2(a-b)

=a2b-a2c+b2c-b2a+c2a-c2b

=(a2b-c2b)+(-a2c+c2a)+(b2c-b2a)

=b.(a2-c2)-ac.(a-c)-b2.(a-c)

=b.(a+c)(a-c)-ac.(a-c)-b2.(a-c)

=(a-c)[b.(a+c)-ac-b2]

=(a-c)(ab+bc-ac-b2)

=(a-c)[(ab-ac)+(bc-b2)]

=(a-c)[a.(b-c)-b.(b-c)]

=(a-c)(b-c)(a-b)