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b) y + y : 0,5 + y : 0,25 + y : 0,125 = 15
yx1+yx2+yx4+yx8=15
yx(1+3+4+8)=15
yx15=15
y=15:15
y=1
#)Giải :
11 x ( y - 6 ) = ( 4 x y ) + 11
11 x y - 66 = 44 x y + 11
y x ( 11 + 11 ) = 66 + 44
y x 22 = 110
y = 110 : 22
y = 5
#) Coi như là làm lại đi ha :D
#~Will~be~Pens~#
a) \(\frac{7}{10}-y\cdot\frac{3}{4}=\frac{1}{5}\)
\(y\cdot\frac{3}{4}=\frac{7}{10}-\frac{1}{5}\)
\(y\cdot\frac{3}{4}=\frac{1}{2}\)
\(y=\frac{1}{2}:\frac{3}{4}\)
\(y=\frac{1}{2}\cdot\frac{4}{3}\)
\(y=\frac{2}{3}\)
b) \(\frac{5}{6}:\left(y+\frac{7}{9}\right)=\frac{3}{4}\)
\(y+\frac{7}{9}=\frac{5}{6}:\frac{3}{4}\)
\(y+\frac{7}{9}=\frac{5}{6}\cdot\frac{4}{3}\)
\(y+\frac{7}{9}=\frac{10}{9}\)
\(y=\frac{10}{9}-\frac{7}{9}\)
\(y=\frac{3}{9}=\frac{1}{3}\)
**** !
a, \(\frac{7}{10}-y\times\frac{3}{4}=\frac{1}{5}\)
\(\Rightarrow y\times\frac{3}{4}=\frac{7}{10}-\frac{1}{5}\)
\(\Rightarrow y\times\frac{3}{4}=\frac{1}{2}\)
\(\Rightarrow y=\frac{1}{2}\div\frac{3}{4}\)
\(\Rightarrow y=\frac{1}{3}\)
b, \(\frac{5}{6}\div\left(y+\frac{7}{9}\right)=\frac{3}{4}\)
\(\Rightarrow y+\frac{7}{9}=\frac{5}{6}\div\frac{3}{4}\)
\(\Rightarrow y+\frac{7}{9}=\frac{10}{9}\)
\(\Rightarrow y=\frac{10}{9}-\frac{7}{9}\)
\(\Rightarrow y=\frac{1}{3}\)
a 9/15 x y = (5/7 +3/14) x 4/7
9/15 x y = 13/14 x 4/7
9/15 x y = 26/49
y= 26/49 : 9/15
y= 130/147
b, y : 0,25 = (2,5-1,3) : 0,75
y : 1/4 = 8/5
y= 8/5 x 1/4 = 2/5
a/
9/14 x y = (5/7 + 3/14) x 4/7
9/14 x y = 13/14 x 4/7
9/14 x y = 26/49
y = 26/49 : 9/14
y = 52/63
b/
y : 0,25= (2,5 - 1,3) : 0,75
y : 0,25= 1,2 : 0,75
y : 0,25= 1,6
y = 1,6 x 0,25
y = 0,4
chúc học tốt nhé!!! học giỏi !!!
- Ta có: \(\frac{3}{x}+\frac{y}{3}=\frac{5}{6}\)
\(\Leftrightarrow\frac{3}{x}=\frac{5}{6}-\frac{y}{3}\)
\(\Leftrightarrow\frac{3}{x}=\frac{5-2y}{6}\)
\(\Leftrightarrow x.\left(5-2y\right)=18=1.18=\left(-1\right).\left(-18\right)=2.9=\left(-2\right).\left(-9\right)=3.6=\left(-3\right).\left(-6\right)\)
- Vì \(5-2y\)là lẻ \(\Rightarrow\)\(5-2y\in\left\{-9,-3,-1,1,3,9,\right\}\)
- Ta có bảng giá trị:
| \(5-2y\) | \(-9\) | \(-3\) | \(-1\) | \(1\) | \(3\) | \(9\) |
| \(x\) | \(-2\) | \(-6\) | \(-18\) | \(18\) | \(6\) | \(2\) |
| \(y\) | \(7\) | \(4\) | \(3\) | \(2\) | \(1\) | \(-2\) |
| \(\left(TM\right)\) | \(\left(TM\right)\) | \(\left(TM\right)\) | \(\left(L\right)\) | \(\left(L\right)\) | \(\left(L\right)\) |
Vậy \(\left(x,y\right)\in\left\{\left(-2,7\right);\left(-6,4\right);\left(-18,3\right)\right\}\)
!@#$!@$! ^_^ Chúc bn hok tốt ^_^ @#$!#$!
a) (y - 24) : 28 = 20
y - 24 = 20 x 28
y - 24 = 560
y = 560 + 24
y = 584
vậy y = ...
a.
\(\left(y-24\right):28=20\)
\(\left(y-24\right)=560\)
\(y=584\)
b. \(13\times\left(y-6\right)=4\times y-6\)
\(13\times y-78=4\times y-6\)
\(9\times y=72\)
\(y=8\)
c.\(y\times3+y\times4+y:3+y:4=182\)
\(y\times\left(3+4\right)+y:\left(3+4\right)=182\)
\(y\times\left(7+\dfrac{1}{7}\right)=182\)
\(y=\dfrac{637}{25}\)