Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
( 1,25 - 0,25 x 5 ) x ( 1,2 x 1,2 x 1,3 x 1,4 x 1,5)
= ( 1,25 - 1,25) x ( 1,2 x 1,2 x 1,3 x 1,4 x 1,5)
= 0 x ( 1,2 x 1,2 x 1,3 x 1,4 x 1,5)
= 0
1. 12,48 : 0,5 x 6,25 x 4 x 2 2: 2 x 3,1 x 1,25 : 0,25 x10
\(=\)12,48 x 2 x 6,25 x 4 x 2 \(=\)2 x 3,1 x 1,25 x 4 x 10
\(=\)< 2 x 6,25 > x < 2 x 4> x 12,48 \(=\) < 1,25 x 10 > x < 2 x 4> x 3,1
\(=\)12,5 x 8 x 12,48 \(=\)12,5 x 8 x 3,1
\(=\)100 x 12,48 \(=\)100 x 3,1
\(=\)1248 \(=\)310
Nhớ k chị nha.
tui cũng hỏi giống bạn nhưng không ai giai cho tui cả huhu
(1,25 - 0,25 x 5) x (1,1 x 1,2 x 1,3 x 1,4 x 1,5)
= 0 x 3,6036
= 0
(1,25 - 0,25 x 5) x (1,1 x 1,2 x 1,3 x 1,4 x 1,5)
= ( 1,25-(0,25x5))x(1,1x1,2x1,3x1,4x1,5)
= (1,25-1,25)x( 1,1x1,2x1,3x1,4x1,5)
= 0 x ( 1,1x1,2x1,3x1,4x1,5)
= 0
mk viết rùi nè
\(a.5,2\times9+5,2=5,2\times\left(9+1\right)=5,2\times10=52\)
\(b.12,3\times101-12,3=12,3\times\left(101-1\right)=12,3\times100=1230\)
\(c.1,25\times0,25\times2,3\times4\times8\times11=\left(1,25\times8\right)\times\left(0,25\times4\right)\times2,3\times11=10\times1\times25,3=253\)
a , 5,2 . 9 + 5,2
= 5,2 . 9 + 5,2 . 1
= 5,2 . ( 9 + 1 )
= 5,2 . 10
= 52 .
b , 12,3 . 101 - 12,3
= 12,3 . 101 - 12,3 . 1
= 12,3 . ( 101 - 1 )
= 12,3 . 100
= 1230 .
c , 1,25 . 0,25 . 2,3 . 4 . 8 . 11
= ( 1,25 . 8 ) . ( 0,25 . 4 ) . ( 2,3 . 11 )
= 10 . 1 . 25,3
= 10 . 25,3
= 253 .
Hok tốt :))
6*x+7.19*x=3.558
(6+7.19)*x=3.558
13.19*x=3.558
x=3.558/13.19
=0.2697498105
tính nhanh
0,8 x 0,4 x 1,25 x 25 + 0,725 + \(\frac{0,25}{2,25\times4\times8\times25}\)
= (0,8 x 0,4) x (1,25 x 25) + 0,725 + \(\frac{0,25}{2,25\times4\times8}\)
= 0,32 x 31,25 + 0,725 + \(\frac{0,25}{2,25\times4\times8}\)
= 10 + 0,725 + \(\frac{0,25}{2,25\times4\times8}\)
= 10 + 18,725
= 28,725
Hk tốt,
k nhé
\(\frac{2x-4,36}{0,125}=0,25.42,9-11,7.0,25+0,25.0,8\)
\(\Leftrightarrow\frac{2x-4,36}{0,125}=0,25.\left(42,9-11.7+0,8\right)\)
\(\Leftrightarrow\frac{2x-4,36}{0,125}=0,25.32\)
\(\Leftrightarrow\frac{2x-4,36}{0,125}=8\)
\(\Leftrightarrow2x-4,36=1\)
\(\Leftrightarrow2x=5,36\)
\(\Leftrightarrow x=2,68\)
b) \(N=\frac{1}{1.5}+\frac{1}{5.10}+\frac{1}{10.15}+\frac{1}{15.20}+...+\frac{1}{2005.2010}\)
\(\Leftrightarrow N=\frac{1}{5}\left(1-\frac{1}{5}+\frac{1}{5}-\frac{1}{10}+\frac{1}{10}-\frac{1}{15}+\frac{1}{15}-\frac{1}{20}+...+\frac{1}{2005}-\frac{1}{2010}\right)\)
\(\Leftrightarrow N=\frac{1}{5}\left(1-\frac{1}{2010}\right)\)
\(\Leftrightarrow N=\frac{1}{5}.\frac{2009}{2010}=\frac{2009}{10050}\)
Bài 1:
a)\(\frac{2\cdot x-4,36}{0,125}=0,25\cdot42,9-11,7\cdot0,25+0,25\cdot0,8\)
\(\frac{2\cdot x-4,36}{0,125}=0,25\cdot\left(42,9-11,7+0,8\right)\)
\(\frac{2\cdot x-4,36}{0,125}=0,25\cdot32\)
\(\frac{2\cdot x-4,36}{0,125}=8\)
\(2\cdot x-4,36=8\cdot0,125\)
\(2\cdot x-4,36=1\)
\(2\cdot x=1+4,36\)
\(2\cdot x=5,36\)
\(x=\frac{5,36}{2}=2,68\)
b) \(N=\frac{1}{1\cdot5}+\frac{1}{5\cdot10}+\frac{1}{10\cdot15}+\frac{1}{15\cdot20}+...+\frac{1}{2005\cdot2010}\)
\(4N=\frac{4}{1\cdot5}+\frac{4}{5\cdot10}+\frac{4}{10\cdot15}+\frac{4}{15\cdot20}+...+\frac{4}{2005\cdot2010}\)
\(4N=1-\frac{1}{5}+\frac{1}{5}-\frac{1}{10}+\frac{1}{10}-\frac{1}{15}+\frac{1}{15}-\frac{1}{20}+...+\frac{1}{2005}-\frac{1}{2010}\)
\(4N=1-\frac{1}{2010}=\frac{2009}{2010}\)
\(N=\frac{2009}{2010}\div4=\frac{2009}{8040}\)
Bài 2:
a) ( x + 5,2 ) : 3,2 = 4,7 ( dư 0,5 )
\(x+5,2=4,7\cdot3,2+0,5\)
\(x+5,2=15,54\)
\(x=15,54-5,2=10,34\)
b)\(A=\frac{4047991-2010\cdot2009}{4050000-2011\cdot2009}\)
\(A=\frac{4047991-2010\cdot2009}{4050000-2009-2010\cdot2009}\)
\(A=\frac{4047991-2010\cdot2009}{4047991-2010\cdot2009}=1\)
Bài 3:
a) \(104,5\cdot x-14,1\cdot x+9,6\cdot x=25\)
\(x\cdot\left(104,5-14,1+9,6\right)=25\)
\(x\cdot100=25\)
\(x=\frac{25}{100}=\frac{1}{4}=0,25\)
b) \(T=\frac{2009\cdot2010+2000}{2011\cdot2010-2020}\)
\(T=\frac{2009\cdot2010+2000}{2009\cdot2010+4020-2020}\)
\(T=\frac{2009\cdot2010+2000}{2009\cdot2010+2000}=1\)
a)
=9,85.(25,82-12,32-3,5)
=9,85.10
=98,5.
b)
=5/4.1/4.4.4/5.1/4.6/5
=3/40.
= ( 0,25 x 4 ) x ( 1,25 x 8 )
= 1 x 10
= 10
10