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A:
\(Cu\left(OH\right)_2--to->CuO+H_2O\)
\(CuO+2HCl-->CuCl_2+H_2O\)
\(CuCl_2+2NaOH-->Cu\left(OH\right)_2+2NaCl\)
\(Cu\left(OH\right)_2+H_2SO_4-->CuSO_4+2H_2O\)
B:
\(Mg\left(OH\right)_2--to->MgO+H_2O\)
\(MgO+2HCl-->MgCl_2+H_2O\)
\(MgCl_2+2NaOH-->Mg\left(OH\right)_2+2NaCl\)
\(Mg\left(OH\right)_2+H_2SO_4-->MgSO_4+2H_2O\)
A: Cu(OH)2 \(\underrightarrow{t^o}\) CuO + H2O
CuO + 2HCl \(\rightarrow\) CuCl2 + H2O
CuCl2 +2 NaOH \(\rightarrow\) Cu(OH)2 + NaCl
Cu(OH)2 + H2SO4 \(\rightarrow\) CuSO4 + 2H2O
B: Mg(OH)2 \(\underrightarrow{t^o}\) 2MgO + H2O
MgO + 2HCl \(\rightarrow\) MgCl2 + H2O
MgCl2 + 2NaOH \(\rightarrow\) Mg(OH)2 + NaCl
Mg(OH)2 + H2SO4 \(\rightarrow\) MgSO4 + 2H2O
Giải được câu A rồi thì câu B làm tương tự thôi
\(CaCO_3->CaO->Ca\left(OH\right)_2->CaCl_2->Ca\left(NO_3\right)_2->CaCO_3->CaCl_2\)
\(CaCO_3->Ca\left(HCO_3\right)_2->Ca\left(NO_3\right)_2\)
\(CaCO_3-to>CaO+CO_2\)
\(CaO+H_2O->Ca\left(OH\right)_2\)
\(Ca\left(OH\right)_2+2HCl->CaCl_2+2H_2O\)
\(CaCl_2+2AgNO_3->Ca\left(NO_3\right)_2+2AgCl\)
\(Ca\left(NO_3\right)_2+Na_2CO_3->CaCO_3+2NaNO_3\)
\(CaCO_3+2HCl->CaCl_2+H_2O+CO_2\)
\(CaCO_3+CO_2+H_2O->Ca\left(HCO_3\right)_2\)
\(Ca\left(HCO_3\right)_2+2HNO_3->Ca\left(NO_3\right)_2+2H_2O+2CO_2\)
Fe + HCl - > Fecl2 + H2
2FeCl2 + NaClO + 4NaOH + H2O -> 5NaCl + 2Fe(OH)3
2Fe(OH)3 -^t0-> Fe2o3 + 3H2O
Fe2O3 + 3H2 -t0-> 2Fe + 3H2O
* cái đâu tiên là \(FeCl_3\) không phải \(FeCl_2\)
\(Fe+Cl-->FeCl_3\)
\(FeCl_3+3NaOH-->Fe\left(OH\right)_3+3NaCl\)
\(2Fe\left(OH\right)_3-->Fe_2O_3+3H_2O\)
\(2Fe\left(OH\right)_3-->Fe_2O_3+3H_2O\)
a) 2Ca + O2 => 2CaO
CaO + H2O => Ca(OH)2
Ca(OH)2 + CuCl2 => CaCl2 + Cu(OH)2↓
b) 4FeS2 + 11O2 => 2Fe2O3 + 8SO2↑
2SO2 + O2 => 2SO3
xt V2O5
SO3 + H2O => H2SO4
H2SO4 + Ba(NO3)2 => 2HNO3 + BaSO4↓
c) 3Fe + 2O2 => Fe3O4
Fe3O4 + 4H2SO4 => FeSO4 + Fe2(SO4)3 + 4H2O
Fe2(SO4)3 + 3Ba(OH)2 => 2Fe(OH)3↓ + 3BaSO4↓
d) 4FeS2 + 11O2 => 2Fe2O3 + 8SO2↑ ( M : SO2)
2SO2 + O2 => 2SO3 (N : SO3)
xt V2O5
SO3 + H2O => H2SO4 (D : H2SO4)
H2SO4 + CuO => CuSO4 + H2O
e) CuSO4 + BaCl2 => CuCl2 + BaSO4↓ (X : CuCl2)
CuCl2 + 2NaOH => 2NaCl + Cu(OH)2↓ (Y : Cu(OH)2)
Cu(OH)2 => CuO + H2O (Z : CuO)
CuO + H2 => Cu + H2O
a) 2Ca + O2 => 2CaO
CaO + H2O => Ca(OH)2
Ca(OH)2 + CuCl2 => CaCl2 + Cu(OH)2
b) 4FeS2 + 11O2 => 2Fe2O3 + 8SO2
2SO2 + O2 => 2SO3
SO3 + H2O => H2SO4
H2SO4 + Ba(NO3)2 => 2HNO3 + BaSO4
c) 3Fe + 2O2 => Fe3O4
Fe3O4 + 4H2SO4 => FeSO4 + Fe2(SO4)3 + 4H2O
Fe2(SO4)3 + 3Ba(OH)2 => 2Fe(OH)3 + 3BaSO4
d) 4FeS2 + 11O2 => 2Fe2O3 + 8SO2↑
2SO2 + O2 => 2SO3
SO3 + H2O => H2SO4
H2SO4 + CuO => CuSO4 + H2O
e) CuSO4 + BaCl2 => CuCl2 + BaSO4
CuCl2 + 2NaOH => 2NaCl + Cu(OH)2
Cu(OH)2 => CuO + H2O
CuO + H2 => Cu + H2O
\(\left(1\right)2Fe+3Cl_2\rightarrow2FeCl_3\)
\(\left(2\right)FeCl3+3NaOH\rightarrow Fe\left(OH\right)_3+3NaCl\)
\(\left(3\right)2Fe\left(OH\right)_3-^{t^o}\rightarrow Fe2O3+3H_2O\)
\(\left(4\right)Fe_2O_3+3H_2-^{t^o}\rightarrow2Fe+3H_2O\)
1) 2Fe + 3Cl2 -> 2FeCl3
2) FeCl3 + 3NaOH -> 3NaCl + Fe(OH)3
3) 2Fe(OH)3 -to-> Fe2O3 + 3H2O
4) Fe2O3 + 3CO -to->2 Fe + 3CO2
Fe2O3+3H2->2Fe+3H2O
Fe+2HCl->FeCl2+H2
FeCl2+2NaOH->Fe(OH)2+2NaCl
Fe(OH)2+MgSO4->FeSO4+Mg(OH)2
2FeCl2+Cl2->2FeCl3
FeCl3+3NaOH->Fe(OH)3+3NaCl
2Fe(OH)3->Fe2O3+H2O
Viết các PTHH theo chuỗi phản ứng.
\(\left(1\right)Fe_2O_3+3H_2\rightarrow2Fe+3H_2O\)
\(\left(2\right)Fe+2HCl\rightarrow FeCl_2+H_2\uparrow\)
\(\left(3\right)FeCl_2+Ba\left(OH\right)_2\rightarrow Fe\left(OH\right)_2\downarrow+BaCl_2\)
\(\left(4\right)Fe\left(OH\right)_2+H_2SO_4\rightarrow FeSO_4+2H_2O\)
\(\left(5\right)2Fe+3Cl_2\rightarrow2FeCl_3\)
\(\left(6\right)FeCl_3+3NaOH\rightarrow Fe\left(OH\right)_3\downarrow+3NaCl\)
\(\left(7\right)2Fe\left(OH\right)_3\underrightarrow{t^o}Fe_2O_3+3H_2O\)
\((-C_6H_{10}O_5-)_n\) + nH2O \(\xrightarrow[t^o]{axit}\) nC6H12O6
C6H10O6 \(\xrightarrow[menruou]{t^o}2C_2H_5OH\) +2CO2
C2H5OH + O2 \(\underrightarrow{mengiam}\) CH3COOH + H2O
CH3COOH + C2H5OH \(\xrightarrow[t^o]{H_2SO_4dac}\) CH3COOC2H5 + H2O
CH3COOC2H5 + H2O \(\rightarrow\) CH3COOH + C2H5OH
C2H5OH + Na \(\rightarrow\) C2H5ONa + \(\dfrac{1}{2}\) H2