PT
1
K
Khách
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PT
1
CM
24 tháng 10 2018
S = 1-1/2 + 1/3-1/4 + 1/5-1/6 + ..... 1/499-1/500
= (1 + 1/3 + 1/5 + ..+ 1/499) - (1/2 + 1/4 + 1/6 + ...+ 1/500) - (1/2 + 1/4 + 1/6 + ...+ 1/500) + (1/2 + 1/4 + 1/6 + ...+ 1/500)
S = (1 + 1/2 + 1/3 + 1/4 + ....+ 1/500) - 2.(1/2 + 1/4 + 1/6 + ...+ 1/500)
= (1 + 1/2 + 1/3 + 1/4 + ....+ 1/500)- (1 + 1/2 + 1/3 + ...+1/250)
= 1/251 + 1/252 + ...+ 1/500.
Vậy S = 1/251 + 1/252 + ...+ 1/500
TN
0
18 tháng 10 2016
Bài 1 :
\(S=\frac{1}{1}-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{2010}-\frac{1}{2011}\)
\(S=\frac{1}{1}-\frac{1}{2011}=\frac{2010}{2011}\)
Bài 2 :
\(S=\frac{1}{10}-\frac{1}{13}+\frac{1}{13}-\frac{1}{16}+\frac{1}{16}-\frac{1}{19}+...+\frac{1}{58}-\frac{1}{61}\)
\(S=\frac{1}{10}-\frac{1}{61}=\frac{51}{610}\)
Bài 3 :
\(3S=\frac{3}{4\times7}+\frac{3}{7\times11}+...+\frac{3}{19\times22}\)
\(3S=\frac{1}{4}-\frac{1}{7}+\frac{1}{7}-\frac{1}{11}+...+\frac{1}{19}-\frac{1}{22}\)
\(3S=\frac{1}{4}-\frac{1}{22}\)
\(S=\frac{18}{88}\div3=\frac{6}{88}\)
NK
11 tháng 8 2017
Bài 1:
Ta thấy:
\(\frac{1}{2}>\frac{1}{6};\frac{1}{3}>\frac{1}{6};\frac{1}{4}>\frac{1}{6};\frac{1}{5}>\frac{1}{6};\frac{1}{6}=\frac{1}{6}\)
\(=>\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+\frac{1}{5}+\frac{1}{6}>\frac{1}{6}+\frac{1}{6}+\frac{1}{6}+\frac{1}{6}+\frac{1}{6}\)
\(=>\frac{1}{2}+\frac{1}{3}+\frac{1}{4}+\frac{1}{5}+\frac{1}{6}>\frac{5}{6}\)
NK
11 tháng 8 2017
Bài 2:
Đặt \(A=\frac{1}{5}+\frac{1}{45}+\frac{1}{117}+...+\frac{1}{1517}\)
Ta thấy \(\frac{1}{5}=\frac{1}{1.5};\frac{1}{45}=\frac{1}{5.9};\frac{1}{117}=\frac{1}{9.13}\)
Theo quy luật như vậy ta có các số tiếp theo là:
\(\frac{1}{13.17}=\frac{1}{221};\frac{1}{17.21}=\frac{1}{357};\frac{1}{21.25}=\frac{1}{525};\frac{1}{25.29}=\frac{1}{725};...\)
Ta có \(A=\frac{1}{5}+\frac{1}{45}+\frac{1}{117}+...+\frac{1}{1517}\)
\(=>A=\frac{1}{1.5}+\frac{1}{5.9}+\frac{1}{9.13}+...+\frac{1}{27.31}\)
\(=>4A=\frac{4}{1.5}+\frac{4}{5.9}+\frac{4}{9.13}+...+\frac{4}{27.31}\)
\(=>4A=\frac{5-1}{1.5}+\frac{9-5}{5.9}+\frac{13-9}{9.13}+...+\frac{31-27}{27.31}\)
\(=>4A=\frac{5}{1.5}-\frac{1}{1.5}+\frac{9}{5.9}-\frac{5}{5.9}+\frac{13}{9.13}-\frac{9}{9.13}+...+\frac{31}{27.31}-\frac{27}{27.31}\)
\(=>4A=1-\frac{1}{5}+\frac{1}{5}-\frac{1}{9}+\frac{1}{9}-\frac{1}{13}+...+\frac{1}{27}-\frac{1}{31}\)
\(=>4A=1-\frac{1}{31}=\frac{30}{31}=>A=\frac{30}{31}.\frac{1}{4}=\frac{15}{62}\)
OC
1
DP
29 tháng 7 2017
\(\frac{1}{3}+\frac{1}{6}+\frac{1}{10}+....+\frac{2}{x\left(x+1\right)}=\frac{499}{999}\)
\(\Leftrightarrow\frac{2}{6}+\frac{2}{12}+\frac{2}{20}+....+\frac{2}{x\left(x+1\right)}=\frac{499}{999}\)
\(\Leftrightarrow\frac{2}{2.3}+\frac{2}{3.4}+\frac{2}{4.5}+....+\frac{2}{x\left(x+1\right)}=\frac{499}{999}\)
\(\Leftrightarrow2\left(\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+....+\frac{1}{x}-\frac{1}{x+1}\right)=\frac{499}{999}\)
\(\Leftrightarrow\frac{1}{2}-\frac{1}{x+1}=\frac{499}{999}\div2\)
\(\Leftrightarrow\frac{1}{x+1}=\frac{1}{2}-\frac{499}{1998}\)
\(\Leftrightarrow\frac{1}{x+1}=\frac{250}{999}\)
\(\Leftrightarrow\left(x+1\right).250=999\Rightarrow x+1=\frac{999}{250}\Rightarrow x=\frac{999}{250}-1=\frac{749}{250}\)
Như kiểu đề sai hay sao ý
7 tháng 8 2016
\(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{x\left(x+1\right)}=\frac{499}{500}\)
\(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{x}-\frac{1}{x+1}=\frac{499}{500}\)
\(1-\frac{1}{x+1}=\frac{499}{500}\)
\(\frac{1}{x+1}=1-\frac{499}{500}=\frac{1}{500}\)
=> x + 1 = 500
=> x = 500 - 1
=> x = 499
Vậy x = 499
7 tháng 8 2016
1/1.2 + 1/2.3 + 1/3.4 +...+ 1/x.(x+1)=499/500
1 - 1/2 + 1/2 -1/3 + 1/3 - 1/4 +...+ 1/x -1/(x+1) =499/500
1-1/(x+1)=499/500
=>x/(x+1)=499/500
=>x=499
24 tháng 11 2019
ta có:
1-1/2+1/2-1/3+1/3-1/4+....+1/x -1/x+1 =499/500
1-1/x+1 =499/500
1/x+1 =1/500
x+1=500
x=499
24 tháng 11 2019
\(\frac{1}{1\times2}+\frac{1}{2\times3}+\frac{1}{3\times4}+...+\frac{1}{X\times\left(X+1\right)}=\frac{499}{500}\)
\(\Leftrightarrow1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{X}-\frac{1}{X+1}=\frac{499}{500}\)
\(\Leftrightarrow1-\frac{1}{X+1}=\frac{499}{500}\)
\(\Leftrightarrow\frac{1}{X+1}=\frac{1}{500}\)
\(\Leftrightarrow X+1=500\)
\(\Leftrightarrow X=499\)
ML
0
DP
18 tháng 6 2017
\(\frac{1}{1+2}+\frac{1}{1+2+3}+\frac{1}{1+2+3+4}+\frac{1}{1+2+3+4+5}\)
\(=\frac{1}{1+2}\times\left(1+\frac{1}{1+2+3}\div\frac{1}{1+2}+\frac{1}{1+2+3+4}\div\frac{1}{1+2}+\frac{1}{1+2+3+4+5}\div\frac{1}{1+2}\right)\)
\(=\frac{1}{1+2}\times\left(1+\frac{1}{2}+\frac{3}{10}+\frac{1}{5}\right)\)
\(=\frac{1}{1+2}\times2\)
\(=\frac{2}{3}\)
S = 1-1/2 + 1/3-1/4 + 1/5-1/6 + ..... 1/499-1/500 = (1 + 1/3 + 1/5 + ..+ 1/499) - (1/2 + 1/4 + 1/6 + ...+ 1/500) - (1/2 + 1/4 + 1/6 + ...+ 1/500) + (1/2 + 1/4 + 1/6 + ...+ 1/500) S = (1 + 1/2 + 1/3 + 1/4 + ....+ 1/500) - 2.(1/2 + 1/4 + 1/6 + ...+ 1/500) = (1 + 1/2 + 1/3 + 1/4 + ....+ 1/500)- (1 + 1/2 + 1/3 + ...+1/250) = 1/251 + 1/252 + ...+ 1/500.
Vậy S = 1/251 + 1/252 + ...+ 1/500