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25/49 x 21/29 - 25/49 x 7/29 + 24/29
= 25/49 x ( 21/ 29 - 7/29 ) + 24/49
= 25/49 x 14/29 + 24/29
= 350/1421 + 24/29
= 350/1421 + 1176/1421
= 1526/1421
\(\frac{25}{49}\times\frac{21}{29}-\frac{25}{49}\times\frac{7}{29}+\frac{24}{49}\)
\(=\frac{25\times\left(21-7\right)}{49\times29}+\frac{24}{49}\)
\(\frac{50}{7\times29}+\frac{24}{49}=\frac{2450+4872}{7\times29\times49}=\frac{7322}{7\times29\times49}=\frac{1046}{1421}\)
a)\(\frac{27}{5}\text{x}\frac{91}{12}\text{x}\frac{125}{9}\text{x}\frac{96}{13}=\frac{27}{9}\text{x}\frac{91}{13}\text{x}\frac{125}{5}\text{x}\frac{96}{12}=3\text{x}7\text{x}25\text{x}8\)
Đến đây tự tính nha !
b)\(\frac{2539}{35}\text{x}\frac{7}{90}+\frac{561}{35}\text{x}\frac{7}{90}=\frac{7}{90}\text{x}\left(\frac{2539}{35}+\frac{561}{35}\right)=\frac{7}{90}\text{x}\frac{3100}{35}=\frac{3100}{90}\text{x}\frac{7}{35}=\frac{310}{9}\text{x}\frac{1}{5}=\frac{62}{9}\)
Cần nhớ:
\(\frac{a}{b}< 1\Rightarrow\frac{a}{b}< \frac{a+n}{b+n}\left(n\inℕ^∗\right)\)
\(\frac{a}{b}>1\Rightarrow\frac{a}{b}>\frac{a+n}{b+n}\left(n\inℕ^∗\right)\)
Ta thấy:
\(\frac{19}{29}< 1\Rightarrow\frac{19}{29}< \frac{19+1}{29+1}=\frac{20}{30}=\frac{2}{3}\)
Ta lại có:
\(\frac{2}{3}=\frac{2.7}{3.7}=\frac{14}{21}< 1\Rightarrow\frac{14}{21}< \frac{14+6}{21+6}=\frac{20}{27}=\frac{20.3}{27.3}=\frac{60}{81}\)
\(\Rightarrow\frac{19}{29}< \frac{60}{81}\) (1)
Ta có:
\(\frac{60}{81}=\frac{20}{27}< 1\Rightarrow\frac{20}{27}< \frac{20+1}{27+1}=\frac{21}{28}< \frac{21}{25}\)
=>\(\frac{60}{81}< \frac{21}{25}\) (2)
Từ (1) và (2) => \(\frac{19}{29}< \frac{60}{81}< \frac{21}{25}\)
\(\frac{21}{25}=\frac{49329}{58725}\)
\(\frac{60}{81}=\frac{43500}{58725}\)
\(\frac{19}{29}=\frac{38475}{58725}\)
\(\)vì \(\frac{49329}{58725}>\frac{43500}{58725}>\frac{38475}{58725}\)nên\(\frac{21}{25}>\frac{60}{81}>\frac{19}{29}\)
\(\frac{21}{25};\frac{60}{81};\frac{19}{29}\)
Ta có : \(\frac{60}{81}=\frac{60:3}{81:3}=\frac{20}{27}\); giữ nguyên \(\frac{21}{25};\frac{19}{29}\).
Vì \(\frac{21}{25}>\frac{20}{25}>\frac{20}{27}\)nên \(\frac{21}{25}>\frac{20}{27}\)
Vì \(\frac{20}{27}>\frac{20}{29}>\frac{19}{29}\)nên \(\frac{20}{27}>\frac{19}{29}\). Vậy :
\(\frac{21}{25}>\frac{20}{27}>\frac{19}{29}\)hay \(\frac{21}{25}>\frac{60}{81}>\frac{19}{29}\)
22/7:( 11 – x ) + 2/3 = 7/5
22/7 : ( 11 - x ) = 7/5 – 2/3
22/7 : ( 11 - x ) = 11/15
11 – x = 22/7 : 11/15
11 – x = 30/7
x = 11 – 30/7
x = 47/7
A,33;36;39;42;45
B,8,6,4,2,0
C,19;21;23;25;27;29
hinh nhu cau b bi sai de
a/ số hạng đầu là 0
b/số hạng đầu là ko xác định đc
c/số hạng đầu là 1
k minhnha,mình đầutiên
a) 652 + 327 + 148 + 73 = ( 652 + 148) +( 327+73) = 800+400 =1200
b) 19 x 16 x 4 + 76 x 34 = ( 19 x 4 ) x 16 + 76 x 34 = 76 x 16 + 76 x 34 = 76 x( 16+34 ) = 76 x 50= 3800
c) 136 x 68 + 16 x 2 x 136 = 136 x ( 68 + 32 ) = 136 x 100 = 13600
d) 45 x 125 - 45 x 25 + 55 x 31 + 55 x 69 = 46 x ( 125-25) + 55 x ( 31+69) = 46 x100 + 55x 100 = 4600 + 5500 = 10100
e) 125 x 25 + 125 x 74 + 125 = 125 x( 25+74 +1 ) = 125 x 100 =12500
f) 43,5 x 2015 x ( 630 - 315 x 2 ) = 43,5 x 2015 x 0 = 0
g) 0,2 x 41 x 36 + 0,8 x 9 x 58 + 1,2 x 6
= 0,2 x4 x41x 9 + 0,8 x 9 x 58 +7,2
= (0,8 x9)x 41 + ( 0,8 x 9) x 58 + 7,2 x 1
= 7,2 x 41 + 7,2 x 58 + 7,2 x 1
= 7,2 x( 41+58+1)
= 7,2 x 100 = 720.
a) 652 + 327 + 148 + 73
=(73+327)+(652+148)
=400+800
=1200
b) 19 x 16 x 4 + 76 x 34
=76*16+76*34
=76*(16+34)
=76*50
=3800
c)136*68+16*2*136
=136*68+32*136
=136*(68+32)
=136*100
=13600
d)45*125-45*25+55*31+55*69
=45*(125-25)+55*(31+69)
=45*100+55*100
=100*(45+55)
=100*100
=10 000
e)125*25+125*74+125
=125*(25+75+1)
=125*100
=12 500
còn lại bạn tự làm đi mk mỏi tay lắm rồi
a, \(\dfrac{90}{37}-\dfrac{38}{25}-\dfrac{8}{25}-\dfrac{4}{25}\)
= \(\dfrac{90}{37}\) - \(\dfrac{38+8+4}{25}\)
= \(\dfrac{90}{37}\) - 2
= \(\dfrac{16}{37}\)
\(\dfrac{24}{29}\) + \(\dfrac{32}{41}\) + \(\dfrac{34}{29}\) + \(\dfrac{50}{41}\)
=(\(\dfrac{24}{29}\) + \(\dfrac{34}{29}\)) + (\(\dfrac{32}{41}\) + \(\dfrac{50}{41}\))
= \(\dfrac{58}{29}\) + \(\dfrac{82}{41}\)
= 2 + 2
= 4