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3A:
a: \(75\cdot20.9+5^2\cdot20.9\)
\(=20.9\cdot100\)
=2090
b: \(86\cdot15+150\cdot1.4\)
\(=86\cdot15+15\cdot14\)
\(=15\cdot100=1500\)
c: \(93\cdot32+14\cdot16\)
\(=93\cdot32+32\cdot7\)
=3200
a) 85.12,7+5,3.12,7
=12,7(85+5,3)=1146,81
b) 52.143-52.39-8.26
=52.(143-39)-208
= 5200
=
\(\text{∘ Ans}\)
\(\downarrow\)
`1,`
`86.15 + 150. 1,4`
`= 86. 15 + 15. 14`
`= 15.(86 + 14)`
`= 15.100`
`= 1500`
`2,`
`93.32 + 14.16`
`= 93.32 + 2.7.16`
`= 93.32 + 32.7`
`= 32.(93 + 7)`
`= 32.100`
`= 3200`
`3,`
\(98,6\cdot199-990\cdot9,86\)
`=`\(98,6\cdot199-99\cdot98,6\)
`=`\(98,6\cdot\left(199-99\right)\)
`=`\(98,6\cdot100\)
`=`\(9860\)
`4,`
\(85\cdot12,7+5\cdot3\cdot12,7?\)
`=`\(85\cdot12,7+15+12,7\)
`=`\(12,7\cdot\left(85+15\right)\)
`=`\(12,7\cdot100\)
`= 1270`
`5,`
\(0,12\cdot90-110\cdot0,6+36-25\cdot6?\)
\(=6\cdot1,8-11\cdot6+6\cdot6-25\cdot6\)
\(=6\cdot\left(1,8-11+6-25\right)\)
\(=6\cdot\left(-28,2\right)=-169,2\)
85.12,7 + 5.3.12,7
= 12,7.(85 + 5.3)
= 12,7. ( 85 + 15)
= 12,7.100 = 1270
a) 2012 = ( 200 + 1 )2
= 2002 + 400 + 1 =40000 + 400 + 1
= 40401
b) 992 = ( 100 - 1 )2
= 1002 - 200 + 1 = 10000 - 200 + 1
= 9801
c) 48.52
= ( 50 - 2 )( 50 + 2 )
= 502 - 22 = 2500 - 4
= 2496
d) 322 + 682 + 68.64
= 322 + 682 + 68.2.32
= ( 32 + 68 )2
= 1002 = 10000
e) 862 + 362 - 72.86
= 862 - 2.36.86 + 362
= ( 86 - 36 )2
= 502 = 2500
b)\(\left(x^4+16x^2+64\right)-16x^2\)
\(=\left(x^2+8\right)^2-16x^2\)
\(=\left(x^2+4x+8\right)\left(x^2-4x+8\right)\)
c) thêm bớt \(16x^2\)
d)thêm bớt\(36x^2\)
a)\(\left(x^4+4x^2+4\right)-4x^2\)
\(=\left(x^2+2\right)^2-4x^2\)
\(=\left(x^2+2x+2\right)\left(x^2-2x+2\right)\)
a/ \(\left(x-4\right)^2-36=0\)
<=> \(\left(x-4-6\right)\left(x-4+6\right)=0\)
<=> \(\left(x-10\right)\left(x+2\right)=0\)
<=> \(\orbr{\begin{cases}x-10=0\\x+2=0\end{cases}}\)<=> \(\orbr{\begin{cases}x=10\\x=-2\end{cases}}\)
b/ \(\left(x+8\right)^2=121\)
<=> \(\left(x+8\right)^2-121=0\)
<=> \(\left(x+8-11\right)\left(x+8+11\right)=0\)
<=> \(\left(x-3\right)\left(x+19\right)=0\)
<=> \(\orbr{\begin{cases}x-3=0\\x+19=0\end{cases}}\)<=> \(\orbr{\begin{cases}x=3\\x=-19\end{cases}}\)
d/ \(4x^2-12x+9=0\)
<=> \(\left(2x\right)^2-2.2x.3+3^2=0\)
<=> \(\left(2x-3\right)^2=0\)
<=> \(2x-3=0\)
<=> \(x=\frac{3}{2}\)
a, 36.28+36.82 +64.69+64.41
=36(28+82)+64(69+41)
=36.110+64.110
=110(36+64)
=110.100
=11000
bài 1.
a.\(\left(x+4\right)\left(x^2-4x+16\right)=x^3-4^3=x^3-64\)
b.\(\left(x^2-\frac{1}{3}\right)\left(x^4+\frac{1}{3}x^2+\frac{1}{9}\right)=\left(x^2\right)^3-\left(\frac{1}{3}\right)^3=x^6-\frac{1}{27}\)
bài 2.
a.\(892^2+892.216+108^2=892^2+2.892.108+108^2\)
\(=\left(892+108\right)^2=1000^2=1_{ }000_{ }000\)
b.\(36^2+26^2-52.36=36^2+26^2-2.26.36=\left(36-26\right)^2=10^2=100\)
a) Kết quả 1270.
b) Kết quả 840. Chú ý: 840.0,155 = 8,4.15,5.
c) Kết quả 1300.
Chú ý: 0,78.1300 = 78.13; 50.6,5 = 25.13; 39 = 3.13.
d) Kết quả -72. Chú ý: 0,12.90 = 6.18; 110.0,6 = 11.6; 36 = 6.6.