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A)2013x3,64+7,26x2013–2013x10,89
=2013x(3,64+7,26–10,89)
=2013x0,01
=20,13
B) \(3\frac{1}{4}\) giờ —1 giờ 15 phút
=\(3\frac{1}{4}\)giờ —\(1\frac{1}{4}\)giờ
= 2 giờ
3,64x2+1,18x2x2+3,6:1/4
3,64x2+2,36x2+3,6x2x2
3,64x2+2,36x2+7,2x2
(3,64+2,36+7,2)x2
13,2x2
...
a) x + 4,32 = 8,67
x = 8,67 - 4,32
x = 4,35
b) 6,85 + x = 10,29
x = 10,29 - 6,85
x = 3,44
c) x - 3,64 = 5,86
x = 5,86 + 3,64
x = 9,5
d) 7,9 - x = 2,5
x = 2,5 + 7,9
x = 10,4
e) x - 5,2 = 1,9 + 3,8
x - 5,2 = 5,7
x = 5,7 + 5,2
x = 10,9
g) x + 2,7 = 8,7 + 4,9
x + 2,7 = 13,6
x = 13,6 - 2,7
x = 10,9
x + 4,32 = 8,67
x = 8,67 - 4,32
x = 4,35
b) 6,85 + x = 10,29
x = 10,29 - 6,85
x = 3,44
c) x - 3,64 = 5,86
x = 5,86 + 3,64
x = 9,5
d) 7,9 - x = 2,5
x = 7,9 - 2,5
x = 5,4
e) x -5,2 = 1,9 + 3,8
x - 5,2 = 5,7
x = 5,7 + 5,2
x = 10,9
g) x + 2,7 = 8,7 + 4,9
x + 2,7 = 13,6
x = 13,6 - 2,7
x = 10,9
tích mk mk tích lại!
\(\left(1+x\right)+\left(2+x\right)+\left(3+x\right)+\)\(\left(4+x\right)+\left(5+x\right)=10\times5\)
\(\left(1+2+3+4+5\right)+\left(x+x+x+x+x\right)=50\)
\(15+5x=50\)
\(5x=35\)
\(x=7\)
Vậy \(x=7\)
\(\left(1+x\right)+\left(2+x\right)+\left(3+x\right)+\left(4+x\right)+\left(5+x\right)=10\times5\)
\(\Rightarrow1+x+2+x+3+x+4+x+5+x=50\)
\(\Rightarrow\left(1+2+3+4+5\right)+\left(x+x+x+x+x\right)=50\)
\(\Rightarrow15+5x=50\)
\(\Rightarrow5x=50-15\)
\(\Rightarrow5x=35\)
\(\Rightarrow x=35:5\)
\(\Rightarrow x=7\).
\(x(\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+...+\frac{1}{132}=\) \(5\frac{1}{2}\)
\(x\left(\frac{1}{1\cdot2}+\frac{1}{2\cdot3}+\frac{1}{3\cdot4}+...+\frac{1}{11\cdot12}\right)=\frac{11}{2}\)
\(x\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{11}-\frac{1}{12}\right)=\frac{11}{2}\)
\(x\left(1-\frac{1}{12}\right)=\frac{11}{2}\)
\(x\cdot\frac{11}{12}=\frac{11}{2}\)
\(x=\frac{11}{2}:\frac{11}{12}\)
\(x=6\)
Vậy x = 6
\(\frac{x}{2}+\frac{x}{6}+\frac{x}{12}+\frac{x}{20}+...+\frac{x}{132}=5\frac{1}{2}\)
\(\Rightarrow x\left(\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+...+\frac{1}{132}\right)=\frac{11}{2}\)
\(\Rightarrow x\left(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{11.12}\right)=\frac{11}{2}\)
\(\Rightarrow x\left(\frac{1}{1}-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{11}-\frac{1}{12}=\frac{11}{2}\right)\)
\(\Rightarrow x\left(1-\frac{1}{12}\right)=\frac{11}{2}\)
\(\Rightarrow x.\frac{11}{12}=\frac{11}{12}\)
\(\Rightarrow x=\frac{11}{12}:\frac{11}{12}=1\)
Vậy x = 1
a) \(\frac{1}{3}-\frac{2}{x}=\frac{1}{6}\)
=> \(\frac{2}{x}=\frac{1}{3}-\frac{1}{6}\)
=> \(\frac{2}{x}=\frac{1}{6}\)
\(\Rightarrow x=12\)
Vậy x = 12
b) \(\frac{x-1}{2}=\frac{3}{4}\)
\(\Rightarrow\left(x-1\right).4=2.3\)
=> 4x - 4 = 6
=> 4.(x-1) = 6
=> x-1 = 6:4 = 1,5
=> x = 1,5 + 1
=> x = 2,5
Vậy x = 2,5
x – 3,64 = 5,86
x = 5,86 + 3,64
x = 9,5