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a)( 124 x 237 + 152 ) : ( 870 + 235 x 122 )
= 29540 + 29540
= 29540 x 2
= 59080
b) 101 + 100 + 99 + 98 + ... + 3 + 2 + 1
= ( 101 - 1 ) : 1 + 1] x ( 101 + 1 ) : 2
= 101 x 102 : 2
= 10302 : 2
= 5151
c) 101 - 100 + 99 - 98 + .. 3 - 2 + 1
(101-100) + (99-98) + ... + (5-4) + (3-2) +1
=1 + 1 + ... + 1 + 1 + 1
= 1 x 51
= 51
a)13x3x32,27+67,63x39
=39x32,27+67,63x39
=39x(32,27+67,63)
=39x100
=3900
b,= 1- [ 1/2 x 1/3 x1/4 x..... x 1/100 ]
=1/2 x 2/3 x 3/4 x .......x 99/100
= 1x2x3x......x99 / 2x3x4x...... x100 [ rút gọn ]
= 1/100
a)\(=\frac{1}{2}.\frac{2}{3}.\frac{3}{4}.\frac{4}{5}......\frac{99}{100}\)
\(=\frac{1.2.3.4.....99}{2.3.4.5.6.....100}\)
\(=\frac{1}{100}\)
b) Tương tự như câu a
a) \(\frac{1}{3}-\frac{2}{x}=\frac{1}{6}\)
=> \(\frac{2}{x}=\frac{1}{3}-\frac{1}{6}\)
=> \(\frac{2}{x}=\frac{1}{6}\)
\(\Rightarrow x=12\)
Vậy x = 12
b) \(\frac{x-1}{2}=\frac{3}{4}\)
\(\Rightarrow\left(x-1\right).4=2.3\)
=> 4x - 4 = 6
=> 4.(x-1) = 6
=> x-1 = 6:4 = 1,5
=> x = 1,5 + 1
=> x = 2,5
Vậy x = 2,5
3/4 * x + 1/2 * x -15 = 35
3/4 * x +1/2 * x = 35 + 15
3/4 * x +1/2 * x = 50
x * ( 3/4 + 1/2 ) = 50
x * 5/4 = 50
x = 50 : 5/4
x = 40
phan b mik ko nhap dc nen bn tu lm nha
a, \(\frac{3}{4}\times x+\frac{1}{2}\times x-15=35\)
\(x+x-15=\frac{3}{4}-\frac{1}{2}\)
\(x+x-15=\frac{2}{8}=\frac{1}{4}\)
\(x=35-15\)
\(x=20\)
Vậy \(x=\frac{1}{4}\)và \(x=20\)
b, Chịu
a) \(\frac{3}{5}+25-\frac{1}{5}=\left(\frac{3}{5}-\frac{1}{5}\right)+25=\frac{2}{5}+25=\frac{2}{5}+\frac{125}{5}=\frac{127}{5}\)
b) \(13\times3\times32,27+67,63\times39=39\times32,27+67,63\times39\)
\(=39\times\left(32,27+67,63\right)\)
\(=39\times99,9=3196,8\)
(Bạn xem lại đề nhé)
c) \(\left(1-\frac{1}{2}\right)\times\left(1-\frac{1}{3}\right)\times\left(1-\frac{1}{4}\right)\times....\times\left(1-\frac{1}{100}\right)\)
\(=\frac{1}{2}\times\frac{2}{3}\times\frac{3}{4}\times.....\times\frac{99}{100}\)
\(=\frac{1\times2\times3\times...\times99}{2\times3\times4\times....\times100}=\frac{1}{100}\)
a, \(\frac{3}{5}+25-\frac{1}{5}=\frac{127}{5}\)
b, \(\text{13 x 3 x 32,27 + 67,63 x 39 =}3896,1\)
............................
thank for watching me do homework
\(\frac{1}{5.8}\)\(+\frac{1}{8.11}+\frac{1}{11.14}+...+\frac{1}{x\left(x+3\right)}=\frac{98}{1545}\)
\(\Leftrightarrow\frac{3}{5.8}+\frac{3}{8.11}+\frac{3}{11.14}+...+\frac{3}{x\left(x+3\right)}=3.\frac{98}{1545}\)
\(\Leftrightarrow\frac{3}{5.8}+\frac{3}{8.11}+\frac{3}{11.14}+...+\frac{3}{x\left(x+3\right)}=\frac{98}{515}\)
\(\Leftrightarrow\frac{1}{5}-\frac{1}{8}+\frac{1}{8}-\frac{1}{11}+\frac{1}{11}-\frac{1}{14}+...+\frac{1}{x}-\frac{1}{x+3}=\frac{98}{515}\)
\(\Leftrightarrow\frac{1}{5}-\frac{1}{x+3}=\frac{98}{515}\)
\(\Leftrightarrow\frac{1}{x+3}=\frac{1}{5}-\frac{98}{515}\)
\(\Leftrightarrow\frac{1}{x+3}=\frac{1}{103}\)
\(\Leftrightarrow x+3=103\)
\(\Leftrightarrow x\)\(=103-3\)
\(\Leftrightarrow x\)\(=100\)
Vậy x = 100
~~~~~~~Hok tốt~~~~~~~~
ta có \(\frac{1}{5.8}+\frac{1}{8.11}+...\frac{1}{x.\left(x+3\right)}\)\(=\frac{1}{3}\left(\frac{3}{5.8}+\frac{3}{8.11}+...+\frac{3}{x.\left(x+3\right)}\right)\)\(=\frac{1}{3}.\left(\frac{1}{5}-\frac{1}{8}+\frac{1}{8}-\frac{1}{11}+...+\frac{1}{x}-\frac{1}{x+3}\right)\)
\(\Rightarrow\frac{1}{3}.\left(\frac{1}{5}-\frac{1}{x+3}\right)=\frac{98}{1545}\)
\(\Rightarrow\frac{1}{5}-\frac{1}{x+3}=\frac{98}{1545}:\frac{1}{3}=\frac{98}{515}\)
\(\Rightarrow\frac{1}{x+3}=\frac{1}{5}-\frac{98}{515}=\frac{1}{103}\)
\(\Rightarrow x+3=103\)
\(\Rightarrow x=100\)
nhớ k nha
a) x : 100 = 9,5 x 3, 58
x : 100 = 34,01
x : 100 = 34,01 x 100
x = 3401
b) 98 – x = 255,92 : 5,6 ?
98 – x = 45,7
x = 98 – 45,7
x = 52,3