Question

[Nguyen Tong Duy Dan]

\(tc1:\frac{a}{b}=\frac{c}{d}=>\frac{a}{b}=\frac{c}{d}=\frac{a+c}{b+d}\)

\(tc2:\frac{a}{b}=\frac{c}{d}=>\frac{a}{b}=\frac{c}{d}=\frac{a-c}{b-d}\)

\(tc3:\frac{a}{b}=\frac{c}{d}=\frac{e}{f}=>\frac{a}{b}=\frac{c}{d}=\frac{e}{f}=\frac{a+c+e}{b+d+f}\)

           \(\frac{a}{b}=\frac{c}{d}=\frac{e}{f}=>\frac{a}{b}=\frac{c}{d}=\frac{e}{f}=\frac{a-c+e}{b-d+f}\)

Answer 1

[Lê Quốc Vương]

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