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a, \(\left[\left(-8\right)+\left(-7\right)+\left(-10\right)\right]\) = -25
b, 555-(-333)-100-80 = 555 + 333 - 100 - 80
= 888-100-80
= 788 - 80
= 708
c, -(-229) +(-219) - 401 +12 = 229 - 219 - 401 + 12
= 10 + 12 - 401
= 22 - 401
= -379
d, 300 - (-200) - (-120) + 18 = 300 + 200 + 120 +18
= 620 + 18
= 638
a) 300^200 = 300^(2.100)=90000^100
200^300= 200^(3.100) = 8000000^100
ma 90000<8000000
nên 300^200 <200^300
vay 300^200<200^300
Ta có:
a) \(A=2000\cdot2009=2000\cdot\left(2005+4\right)=2000\cdot2005+2000\cdot4\)
\(B=2004\cdot2005=\left(2000+4\right)\cdot2005=2000\cdot2005+2005\cdot4\)
Do \(2000< 2005\)
\(\Rightarrow2000\cdot4< 2005\cdot4\)
\(\Rightarrow2000\cdot2005+2000\cdot4< 2000\cdot2005+2005\cdot4\)
Vậy A < B
b) \(A=3004^2=\left(3000+4\right)\cdot3004=3000\cdot3004+3004\cdot4\)
\(B=3000\cdot3008=3000\cdot\left(3004+4\right)=3000\cdot3004+3000\cdot4\)
Do \(3004>3000\)
\(\Rightarrow3004\cdot4>3000\cdot4\)
\(\Rightarrow3000\cdot3004+3004\cdot4>3000\cdot3004+3000\cdot4\)
Vậy A > B
Tính các tổng dưới đây sau khi đã rút gọn phân số :
a)\(\dfrac{7}{21}\) + \(\dfrac{9}{-36}\) = \(\dfrac{7}{21}\)+\(\dfrac{-9}{36}\)=\(\dfrac{1}{3}\)+\(\dfrac{-1}{4}\)=\(\dfrac{4}{12}\)+\(\dfrac{-3}{12}\)=\(\dfrac{1}{12}\)
b) \(\dfrac{-12}{18}\)+\(\dfrac{-21}{35}\)=\(\dfrac{-2}{3}\)+\(\dfrac{-3}{5}\)=\(\dfrac{-10}{15}\)+\(\dfrac{-9}{15}\)=\(\dfrac{-19}{15}\)
c) \(\dfrac{-3}{21}\)+\(\dfrac{6}{42}\)=\(\dfrac{-1}{7}\)+\(\dfrac{1}{7}\)=0
d) \(\dfrac{-18}{24}\)+\(\dfrac{15}{-21}\)=\(\dfrac{-18}{24}\)+\(\dfrac{-15}{21}\)=\(\dfrac{-3}{4}\)+\(\dfrac{-5}{7}\)=\(\dfrac{-21}{28}\)+\(\dfrac{-20}{28}\)=\(\dfrac{-41}{28}\)
a) 2011 + 5[300 - (17 - 7)2 ]
= 2011 + 5[300 - 100]
= 2011 + 5.200
= 2011 + 1000
= 3011
b) 695 - [200 + (11 - 1)2 ]
= 695 - [200 + 100]
= 695 - 300
= 395
c) 129 - 5[29 - (6-1)2 ]
= 129 - 5[29 - 25]
= 129 - 5 . 4
= 129 - 20
= 109
d) 2345 - 1000 : [19 - 2(21-18)2 ]
= 2345 - 1000 : [19 - 2 . 9]
= 2345 - 1000 : 1
= 2345 - 1000
= 1345
a, 2011+5 [300-(17-7)2 ] =2011+5[300-102]
=2011+5[300-100]=2011+5.200
=2011+1000=3011
b, 695-[200+(11-1)2]=695-[200+102]
=695-[200+100]=695-300=395
300 – (-200) – (-120) + 18 = (300 + 200) + (120 + 18) = 500 + 138= 638