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Ai bít giải chi tiết ra hk ạ????
Giúp e với !!!!!!Làm ơn làm phước, đúng e k cho mak TTTTTTTTT
\(=\dfrac{\left[\left(10.4+8.1\right)^2-6.5^2\right]:0.025}{576-336}+25+\dfrac{4}{3}-\dfrac{4}{3}\)
\(=\dfrac{3000}{240}+25=\dfrac{25}{2}+25=37.5\)
a, \(\frac{1-\frac{1}{1+\frac{1}{2}}}{1+\frac{1}{1-\frac{1}{2}}}=\frac{1-\frac{1}{\frac{3}{2}}}{1+\frac{1}{\frac{1}{2}}}=\frac{1-\frac{2}{3}}{1+2}=\frac{\frac{1}{3}}{3}=\frac{1}{9}\)
b, \(0,8:\frac{4}{5}-\frac{4}{5}\cdot\left[1,08-\frac{2}{25}\right]=0,8:\frac{4}{5}-\frac{4}{5}\cdot1\)
\(=\frac{4}{5}\cdot\left[0,8+1\right]=\frac{4}{5}\cdot1,8=\frac{36}{25}\)
c, \(\left[1-\frac{1}{2}\right]\cdot\left[1-\frac{1}{3}\right]\cdot...\cdot\left[1-\frac{1}{11}\right]\)
\(=\frac{1}{2}\cdot\frac{2}{3}\cdot\frac{3}{4}\cdot...\cdot\frac{10}{11}=\frac{1\cdot2\cdot3\cdot4\cdot...\cdot10}{2\cdot3\cdot4\cdot5\cdot...\cdot11}=\frac{1}{11}\)
Phan Hoàng Mai
Tính :
\(\left(-0,5-\frac{3}{5}\right):\left(-\frac{22}{25}\right)+\left(\frac{2}{25}-1,08\right).\frac{3}{8}-72:12^2\)
\(=\left(-\frac{5}{10}-\frac{3}{5}\right):\frac{-22}{25}+\left(\frac{2}{25}-\frac{108}{100}\right).\frac{3}{8}-72:144\)
\(=\left(-\frac{5}{10}-\frac{6}{10}\right).\frac{-25}{22}+\left(\frac{8}{100}-\frac{108}{100}\right).\frac{3}{8}-\frac{1}{2}\)
\(=\frac{-11}{10}.\frac{-25}{22}+\left(-1\right).\frac{3}{8}-\frac{1}{2}\)
\(=\frac{\left(-11\right).\left(-25\right)}{10.22}+\frac{-3}{8}-\frac{1}{2}\)
\(=\frac{5}{4}+\frac{-3}{8}-\frac{1}{2}\)
\(=\frac{10}{8}+\frac{-3}{8}-\frac{4}{8}\)
\(=\frac{3}{8}\)
Chúc bạn học tốt!!!
\(\left(-0,5-\frac{3}{5}\right):\left(-\frac{22}{25}\right)+\left(\frac{2}{25}-1,08\right)\cdot\frac{3}{8}-72:12^2\)
=\(\left(-\frac{1}{2}-\frac{3}{5}\right):\left(-\frac{22}{25}\right)+\left(\frac{2}{25}-\frac{27}{25}\right)\cdot\frac{3}{8}-\frac{72}{144}\)
=\(\left(-\frac{11}{10}.\left(-\frac{25}{22}\right)\right)-1\cdot\frac{3}{8}-\frac{1}{2}\)
= \(\frac{5}{4}-\frac{3}{8}-\frac{1}{2}\)
= \(\frac{10}{8}-\frac{3}{8}-\frac{4}{8}=\frac{3}{8}\)
Ta có: \(\frac{0,8:\left(\frac{4}{5}\cdot1,25\right)}{0,64-\frac{1}{25}}+\frac{\left(1,08-\frac{2}{25}\right):\frac{4}{7}}{\left(6\frac{5}{9}-3\frac{1}{4}\right)\cdot2\frac{2}{17}}+\frac{\left(1,2\cdot0,5\right)}{\frac{4}{5}}\)
\(=\frac{\frac{4}{5}:\left(\frac{4}{5}\cdot\frac{5}{4}\right)}{\frac{16}{25}-\frac{1}{25}}+\frac{\left(\frac{27}{25}-\frac{2}{25}\right)\cdot\frac{7}{4}}{\left(\frac{59}{9}-\frac{13}{4}\right)\cdot\frac{36}{17}}+\frac{6}{5}\cdot\frac{1}{2}\cdot\frac{5}{4}\)
\(=\frac{\frac{4}{5}}{\frac{3}{5}}+\frac{\frac{7}{4}}{\frac{119}{36}\cdot\frac{36}{17}}+\frac{3}{4}\)
\(=\frac{4}{5}\cdot\frac{5}{3}+\frac{7}{4}\cdot\frac{1}{7}+\frac{3}{4}=\frac{4}{3}+\frac{1}{4}+\frac{3}{4}=\frac{7}{3}\)
\(\left(-0,5-\dfrac{3}{5}\right):\left(\dfrac{-22}{25}\right)+\left(\dfrac{2}{25}-1,08\right).\dfrac{3}{8}-72:12^2\)
\(=\left(\dfrac{-1}{2}-\dfrac{3}{5}\right):\left(\dfrac{-22}{25}\right)+\left(\dfrac{2}{25}-\dfrac{27}{25}\right).\dfrac{3}{8}-\dfrac{72}{144}\)
\(=\left[\dfrac{-11}{10}.\dfrac{-25}{22}\right]-1.\dfrac{3}{8}-\dfrac{1}{2}\)
\(=\dfrac{5}{4}-\dfrac{3}{8}-\dfrac{1}{2}\)
\(=\dfrac{10}{8}-\dfrac{3}{8}-\dfrac{4}{8}\)
\(=\dfrac{3}{8}\)
bà cụ non
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