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\(\left(2x-5\right)^2=0,81\)
\(\left(2x-5\right)^2=0,9^2\)
\(\Rightarrow2x-5=0,9\)
\(2x=0,9+5\)
\(2x=5,9\)
\(x=5,9:2\)
\(x=2,95\)
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\(\left(x-\frac{1}{3}\right)^3=0,027\)
\(\left(x-\frac{1}{3}\right)^3=0,3^3\)
\(\Rightarrow x-\frac{1}{3}=0,3\)
\(x=0,3+\frac{1}{3}\)
\(x=\frac{19}{30}\)
\(\left(2x-5\right)^2=0,81\)
\(\Rightarrow2x-5=0,9\)
\(\Rightarrow2x=5,9\)
\(\Rightarrow x=2,95\)
\(\left(x-\frac{1}{3}\right)^3=0,027\)
\(\Rightarrow x-\frac{1}{3}=0,3\)
\(\Rightarrow x=\frac{19}{30}\)
a/ \(\left(\frac{1}{5}\right)^x=\left(\frac{1}{5^3}\right)^3=\left(\frac{1}{5}\right)^9\Rightarrow x=9\)
b/ \(\left(\frac{3}{5}\right)^x=\left(\frac{3^2}{5^2}\right)^3=\left(\frac{3}{5}\right)^6\Rightarrow x=6\)
c\(2^{3-2x}=\left(2^3\right)^3=2^9\Rightarrow3-2x=9\Rightarrow x=-3\)
d/ \(2^{3x+1}=32^2=\left(2^5\right)^2=2^{10}\Rightarrow3x+1=10\Rightarrow x=3\)
e/ \(3^{6-3x}=81^3=\left(3^4\right)^3=3^{12}\Rightarrow6-3x=12\Rightarrow x=-2\)
\(\left(\frac{1}{5}\right)^x=\left(\frac{1}{125}\right)^3\Leftrightarrow\left(\frac{1}{5}\right)^x=\left[\left(\frac{1}{5}\right)^3\right]^3\Leftrightarrow\left(\frac{1}{5}\right)^x=\left(\frac{1}{5}\right)^9\Leftrightarrow x=9\)
\(\left(\frac{3}{5}\right)^x=\left(\frac{9}{25}\right)^3\Leftrightarrow\left(\frac{3}{5}\right)^x=\left[\left(\frac{3}{5}\right)^2\right]^3\Leftrightarrow\left(\frac{3}{5}\right)^x=\left(\frac{3}{5}\right)^6\Leftrightarrow x=6\)
\(2^{3-2x}=8^3\Leftrightarrow2^{3-2x}=\left(2^3\right)^3\Leftrightarrow2^{3-2x}=2^9\Leftrightarrow3-2x=9\)
\(\Leftrightarrow2x=3-9\Leftrightarrow2x=-6\Leftrightarrow x=\left(-6\right):2\Leftrightarrow x=-3\)
Các phép còn lại làm tương tự bn nha !
\(\frac{25}{5^x}=\frac{1}{125}\Rightarrow25.125=5^x.1\)
\(3125=5^x\)
\(5^5=5^x\)
\(\Rightarrow x=5\)
25/5^x=25/5^5
2^8+2^2+3=288
(2x-1)^4=3^4
2x-1=3
2x=4
x=2