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a; 7/2+33/7-75/14=20/7
b: 9/2+1/2:11/2=9/2+1/11=101/22
\(\frac{7}{18}\)+ \(\frac{5}{3}\)* 1\(\frac{3}{9}\): \(\frac{55}{4}\)
Mọi người giúp mình giải nhé!!!

\(\frac{7}{18}+\frac{5}{3}\times1\frac{3}{9}\div\frac{55}{4}=\)\(\frac{7}{18}+\frac{5}{3}\times\frac{12}{9}\div\frac{55}{4}=\)\(\frac{7}{18}+\frac{5}{3}\times\frac{12}{9}\times\frac{4}{55}=\)\(\frac{7}{18}+\frac{5\times12\times4}{3\times9\times55}=\)\(\frac{7}{18}+\frac{4\times4}{9\times11}=\)\(\frac{7}{18}+\frac{16}{99}=\)\(\frac{693}{1782}+\frac{288}{1782}=\)\(\frac{981}{1782}=\frac{109}{198}\)

\(\dfrac{3}{4}\times\dfrac{8}{5}:1\dfrac{1}{6}\)
=\(\dfrac{6}{5}:\) \(\dfrac{7}{6}\)
=\(\dfrac{6}{5}\times\dfrac{6}{7}=\dfrac{36}{35}\)
2\(\dfrac{1}{3}\) x 1\(\dfrac{1}{4}\) -\(\dfrac{7}{5}\)
\(\dfrac{7}{3}\times\dfrac{5}{4}-\) \(\dfrac{7}{5}\)
\(\dfrac{35}{12}-\dfrac{7}{5}\)
\(\dfrac{175}{60}-\dfrac{84}{60}=\dfrac{91}{60}\)
4\(\dfrac{2}{3}+1\dfrac{1}{4} +2\dfrac{1}{3}+2\dfrac{3}{7}\)
(4 +2) + \(\left(\dfrac{2}{3}+\dfrac{1}{3}\right)\) +1\(\dfrac{1}{4}\) + \(2\dfrac{3}{7}\)
6 + 1 + \(\dfrac{5}{4}\) + \(\dfrac{17}{7}\)
7 + \(\dfrac{103}{28}\)
\(\dfrac{299}{28}\)

A,\(\frac{7}{13}+\frac{1}{7}+\frac{18}{30}=\frac{49}{91}+\frac{13}{91}+\frac{18}{30}=\frac{62}{91}+\frac{18}{30}=\frac{1860}{2730}+\frac{1638}{2730}=\frac{583}{455}\)
B,\(\left(\frac{20}{21}+\frac{3}{14}\right)-\frac{2}{3}=\left(\frac{280}{294}+\frac{63}{294}\right)-\frac{2}{3}=\frac{7}{6}-\frac{2}{3}=\frac{21}{18}-\frac{12}{18}=\frac{9}{18}=\frac{1}{2}\)
C,\(=\frac{17}{5}+\frac{31}{7}=\frac{119}{35}+\frac{155}{35}=\frac{234}{35}\)

3\(\frac{1}{2}\)+4\(\frac{5}{7}\)- 5\(\frac{5}{14}\)=
=\(\frac{7}{2}\)+\(\frac{33}{7}\)-\(\frac{65}{14}\)
=\(\frac{49}{14}\)+\(\frac{66}{14}\)-\(\frac{65}{14}\)
=\(\frac{50}{14}\)

a,=25/6;7/6=25/6x6/7=25/7
b,=7/2x32/6=56/3
c,=17/5-11/10=34/10-11/10=23/10
d,=8/3+11/4=32/12+33/12=65/12
\(\frac{1}{2}+\frac{4}{5}:\frac{3}{5}-\frac{1}{5}\)
\(=\frac{1}{2}+\frac{4.5}{5.3}-\frac{1}{5}\)
\(=\frac{1}{2}+\frac{4}{3}-\frac{1}{5}\)
\(=\frac{11}{6}-\frac{1}{5}=\frac{49}{30}\)
= \(\frac{1}{2}\)+ \(\frac{20}{15}\)- \(\frac{1}{5}\)
= \(\frac{55}{30}\)- \(\frac{1}{5}\)
= \(\frac{49}{30}\)