\(\dfrac{x-1}{x+5}=\dfrac{6}{7}\)

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22 tháng 2 2023

`(x-1)/(x+5) = 6/7` ĐKXĐ : `x-5≠0<=>x≠5`

`<=> (7(x-1))/(7(x+5)) = (6(x+5))/(7(x+5))`

`=> 7(x-1)=6(x+5)`

`<=>7x-7=6x+30`

`<=>7x-6x=30+7`

`<=>x= 37 (TM)`

\(6\left(x+5\right)=7\left(x-1\right)\)

\(6x+30=7x-7\)

\(-x=-37\)

\(x=37\)

12 tháng 1 2018

2, \(\Rightarrow\left\{{}\begin{matrix}\\\dfrac{5}{4}x-\dfrac{7}{2}=0\\\dfrac{5}{8}x+\dfrac{3}{5}=0\\\end{matrix}\right.\)

\(\Rightarrow\left\{{}\begin{matrix}x=\dfrac{14}{5}\\\\x=\dfrac{-24}{25}\\\end{matrix}\right.\)

28 tháng 8 2017

a) \(x+\dfrac{1}{3}=\dfrac{3}{4}\Leftrightarrow x=\dfrac{3}{4}-\dfrac{1}{3}\Leftrightarrow x=\dfrac{5}{12}\) vậy \(x=\dfrac{5}{12}\)

b) \(x-\dfrac{2}{5}=\dfrac{5}{7}\Leftrightarrow x=\dfrac{5}{7}+\dfrac{2}{5}\Leftrightarrow x=\dfrac{39}{35}\) vậy \(x=\dfrac{39}{35}\)

c) \(-x-\dfrac{2}{3}=\dfrac{-6}{7}\Leftrightarrow x=\dfrac{-2}{3}+\dfrac{6}{7}\Leftrightarrow x=\dfrac{4}{21}\) vậy \(x=\dfrac{4}{21}\)

d) \(\dfrac{4}{7}-x=\dfrac{1}{3}\Leftrightarrow x=\dfrac{4}{7}-\dfrac{1}{3}\Leftrightarrow x=\dfrac{5}{21}\) vậy \(x=\dfrac{5}{21}\)

2 tháng 9 2018

a) x + \(\dfrac{1}{3}\) = \(\dfrac{3}{4}\)

x = \(\dfrac{3}{4}\) - \(\dfrac{1}{3}\)

x = \(\dfrac{5}{12}\)

Vậy x = \(\dfrac{5}{12}\)

b) x - \(\dfrac{2}{5}\) = \(\dfrac{5}{7}\)

x = \(\dfrac{5}{7}\) + \(\dfrac{2}{5}\)

x = \(\dfrac{39}{35}\)

Vậy x = \(\dfrac{39}{35}\)

c) -x - \(\dfrac{2}{3}\) = \(-\dfrac{6}{7}\)

- x = \(-\dfrac{6}{7}\) + \(\dfrac{2}{3}\)

- x = \(-\dfrac{4}{21}\)

⇒ x = \(\dfrac{4}{21}\)

Vậy x = \(\dfrac{4}{21}\)

d) \(\dfrac{4}{7}\) - x = \(\dfrac{1}{3}\)

x = \(\dfrac{4}{7}\) - \(\dfrac{1}{3}\)

x = \(\dfrac{5}{21}\)

Vậy x = \(\dfrac{5}{21}\)

a: x>-3/5 nên x+3/5>0

x<1/7 nên x-1/7<0

A=1/7-x-x-3/5+4/5=-2x+12/35

b: B=|x-1/7|+|x+3/5|-1/3

x>-3/5 nên x+3/5>0

x<1/7 nên x-1/7<0

B=1/7-x+3/5+x-1/3=43/105

30 tháng 8 2019

1) -2/3

1: \(\Leftrightarrow3x+4=2\)

=>3x=-2

=>x=-2/3

2: \(\Leftrightarrow7x-7=6x-30\)

=>x=-23

3: =>\(5x-5=3x+9\)

=>2x=14

=>x=7

4: =>9x+15=14x+7

=>-5x=-8

=>x=8/5

14 tháng 2 2018

a) \(2\left(4x-30\right)-3\left(x+5\right)+4\left(x-10\right)=5\left(x+2\right)\)

\(\Leftrightarrow8x-60-3x+15+4x-40=5x+10\)

\(\Leftrightarrow9x-35=5x+10\)

\(\Leftrightarrow9x-5x=10+35\)

\(\Leftrightarrow4x=45\)

\(\Leftrightarrow x=\dfrac{45}{4}=11,25\)

b) \(\dfrac{11}{12}-\left(\dfrac{2}{5}+x\right)=\dfrac{2}{3}\left(6x+1\right)\)

\(\Leftrightarrow\dfrac{11}{12}-\left(\dfrac{2}{5}+x\right)=4x+\dfrac{2}{3}\)

\(\Leftrightarrow\dfrac{31}{60}+x=4x+\dfrac{2}{3}\)

\(\Leftrightarrow\dfrac{31}{60}-\dfrac{2}{3}=4x-x\)

\(\Leftrightarrow3x=\dfrac{1}{60}\)

\(\Leftrightarrow x=\dfrac{1}{180}\)

c) \(\dfrac{7}{3}-\left(2x-\dfrac{1}{3}\right)=\left(-2\dfrac{1}{6}+1\dfrac{1}{2}\right):0,25\)

\(\Leftrightarrow\dfrac{7}{3}-2x+\dfrac{1}{3}=-1\dfrac{2}{3}:\dfrac{1}{4}\)

\(\Leftrightarrow\dfrac{8}{3}-2x=\dfrac{-5}{3}.4\)

\(\Leftrightarrow\dfrac{8}{3}-2x=\dfrac{-20}{3}\)

\(\Leftrightarrow2x=\dfrac{8}{3}+\dfrac{20}{3}\)

\(\Leftrightarrow2x=\dfrac{28}{3}\)

\(\Leftrightarrow x=4\dfrac{2}{3}\)

d) \(0,75+\dfrac{5}{9}:x=5\dfrac{1}{2}\)

\(\Leftrightarrow\dfrac{3}{4}+\dfrac{5}{9}:x=\dfrac{11}{2}\)

\(\Leftrightarrow\dfrac{5}{9}:x=\dfrac{11}{2}-\dfrac{3}{4}\)

\(\Leftrightarrow\dfrac{5}{9}:x=\dfrac{19}{4}\)

\(\Leftrightarrow x=\dfrac{5}{9}:\dfrac{19}{4}\)

\(\Leftrightarrow x=\dfrac{20}{171}\)

27 tháng 9 2017

Bài 1:

\(a,\dfrac{x}{3}=\dfrac{y}{7}\)\(x+y=20\)

\(=\dfrac{x+y}{3+7}=\dfrac{20}{10}=2\)

\(\Rightarrow x=2.3=6\)

\(y=2.7=14\)

Vậy \(x=6\)\(y=14\)

\(b,\dfrac{x}{5}=\dfrac{y}{2}\)\(x-y=6\)

\(=\dfrac{x-y}{5-2}=\dfrac{6}{3}=2\)

\(\Rightarrow x=2.5=10\)

\(y=2.2=4\)

Vậy \(x=10\)\(y=4\)

\(c,\dfrac{x}{7}=\dfrac{18}{14}\)

Từ tỉ lệ thức trên ta có:

\(14x=7.18\)

\(x=\dfrac{7.18}{14}\)

\(x=9\)

Vậy \(x=9\)

\(d,6:x=1\dfrac{3}{4}:5\)

\(6:x=\dfrac{7}{20}\)

\(x=6:\dfrac{7}{20}\)

\(x=\dfrac{120}{7}\)

Vậy \(x=\dfrac{120}{7}\)

\(e,\dfrac{x}{2}=\dfrac{y}{4}=\dfrac{z}{6}\)\(x-y+z=8\)

\(=\dfrac{x-y+z}{2-4+6}=\dfrac{8}{4}=2\)

\(\Rightarrow x=2.2=4\)

\(y=2.4=8\)

\(z=2.6=12\)

Vậy \(x=4;y=8;z=12\)

27 tháng 9 2017

a, \(\dfrac{x}{3}=\dfrac{y}{7}=\dfrac{x+y}{3+7}=\dfrac{1}{2}\)

Từ đó suy ra x=1,5; y=3,5

b,\(\dfrac{x}{5}=\dfrac{y}{2}=\dfrac{x-y}{5-2}=\dfrac{1}{2}\)

Từ đó suy ra x=2,5; y=1

c,\(\dfrac{x}{7}=\dfrac{18}{14}\Leftrightarrow\dfrac{x}{7}=\dfrac{9}{7}\Rightarrow x=9\)

d,\(\dfrac{6}{x}=\dfrac{\dfrac{7}{4}}{5}\Leftrightarrow\dfrac{6}{x}=\dfrac{24}{7}\left(\dfrac{\dfrac{7}{4}}{5}\right)\Leftrightarrow\dfrac{6}{x}=\dfrac{6}{\dfrac{120}{7}}\Rightarrow x=\dfrac{120}{7}\)

e,\(\dfrac{x}{2}=\dfrac{y}{4}=\dfrac{z}{8}=\dfrac{x-y+z}{2-4+8}=\dfrac{4}{3}\)

Từ đó suy ra x=\(\dfrac{8}{3}\); y=\(\dfrac{16}{3}\); z=\(\dfrac{32}{3}\)

31 tháng 7 2017

31 tháng 7 2017

j vậy bạn?????hum

a: |x-1/2|=7/2

=>x-1/2=7/2 hoặc x-1/2=-7/2

=>x=4 hoặc x=-3

b: \(x:\dfrac{3}{8}+\dfrac{5}{8}=x\)

=>8/3x-x=-5/8

=>5/3x=-5/8

hay x=-5/8:5/3=-5/8x3/5=-15/40=-3/8

c: \(\dfrac{5}{6}-\left|x-\dfrac{1}{2}\right|=\dfrac{15}{18}=\dfrac{5}{6}\)

=>|x-1/2|=0

=>x-1/2=0

hay x=1/2

e: \(\left(5x-3\right)^2-\dfrac{1}{64}=0\)

=>(5x-3)2=1/64

=>5x-3=1/8 hoặc 5x-3=-1/8

=>5x=25/8 hoặc 5x=23/8

=>x=5/8 hoặc x=23/40

21 tháng 11 2022

1: =>1/3:x=3/5-2/3=9/15-10/15=-1/15

=>x=-1/3:1/15=5

2: \(\Leftrightarrow x\cdot\dfrac{2}{3}-3=\dfrac{2}{5}\cdot\left(-10\right)=-4\)

=>x*2/3=-1

=>x=-3/2

3: \(\Leftrightarrow\dfrac{8}{3}:x=\dfrac{25}{12}:\dfrac{-3}{50}=\dfrac{25}{12}\cdot\dfrac{-50}{3}\)

hay x=-48/625

9: =>x=-2*3/1,5=-4

8: =>2/3:x=5/2:-3/10=5/2*(-10)/3=-50/6=-25/3

=>x=-2/3:25/3=-2/3*3/25=-2/25

5 tháng 8 2018

a. \(\dfrac{-39}{7}:x=26\)

x = \(\dfrac{-39}{7}:26\)

x = \(\dfrac{-3}{14}\)

b. \(x:\dfrac{13}{5}=\dfrac{7}{4}\)

x = \(\dfrac{7}{4}.\dfrac{13}{5}\)

x = \(\dfrac{91}{20}\)

c. x = \(\dfrac{-3}{5}-\dfrac{1}{2}\)

x = \(\dfrac{-11}{10}\)

d. \(x-\dfrac{3}{4}=\dfrac{9}{4}\)

x = \(\dfrac{9}{4}+\dfrac{3}{4}\)

x = 3

e. \(\dfrac{7}{8}:x=\dfrac{14}{3}\)

x = \(\dfrac{7}{8}:\dfrac{14}{3}\)

x = \(\dfrac{3}{16}\)

f. \(x:\dfrac{8}{3}=\dfrac{13}{3}\)

x = \(\dfrac{13}{3}.\dfrac{8}{3}\)

x = \(\dfrac{104}{9}\)

g. x = \(\dfrac{4}{10}-\dfrac{2}{5}\)

x = 0

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