\(\dfrac{3}{4}-\sqrt{\dfrac{3}{12}}+\dfrac{\left(\sqrt{3}\right)^2}{4}\)

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11 tháng 7 2022

= 3/4 - 1/2 + 3/4

= 3/4+3/4-1/2

= 3/2-1/2

= 1

11 tháng 7 2022

\(\dfrac{3}{4}-\sqrt{\dfrac{3}{12}}+\dfrac{(\sqrt{3})^2}{4}\)

\(=\dfrac{3}{4}-\dfrac{1}{2}+\dfrac{3}{4}\)

\(=\dfrac{3}{4}-\dfrac{2}{4}+\dfrac{3}{4}\)

\(=\dfrac{4}{4}=1\)

19 tháng 11 2018

5) \(\left(-2\right)^2+\sqrt{36}-\sqrt{9}+\sqrt{25}\)

=\(4+6-3+5\)

=\(12\)

19 tháng 11 2018

2) \(\dfrac{11}{25}.\left(-24,8\right)-\dfrac{11}{25}.75,2\)

=\(\dfrac{11}{25}.\left(-24,8-75,2\right)\)

=\(\dfrac{11}{25}.\left(-100\right)\)

=\(-44\)

27 tháng 11 2022

a: \(=\left(\dfrac{1}{4}+\dfrac{3}{4}\right)\cdot\dfrac{18}{5}-\dfrac{6}{5}:\dfrac{-9}{5}+4\)

\(=\dfrac{18}{5}-\dfrac{6}{5}\cdot\dfrac{-5}{9}+4\)

\(=\dfrac{18}{5}+\dfrac{2}{3}+4\)

\(=\dfrac{124}{15}\)

b: \(=\dfrac{9}{25}\cdot\left(\dfrac{3}{5}-\dfrac{1}{5}+\dfrac{1}{2}\right)-\dfrac{3}{8}:\dfrac{9}{8}\)

\(=\dfrac{9}{25}\cdot\dfrac{4}{10}-\dfrac{1}{3}\)

\(=-\dfrac{71}{375}\)

c: \(=\dfrac{7}{10}:\dfrac{4}{5}+\dfrac{2}{9}:\dfrac{5}{9}+\dfrac{1}{8}\)

\(=\dfrac{7}{10}\cdot\dfrac{5}{4}+\dfrac{2}{5}+\dfrac{1}{8}\)

=1+2/5

=7/5

d: \(=\dfrac{3}{7}\left(19+\dfrac{1}{3}-33-\dfrac{1}{3}\right)-\dfrac{2}{7}=\dfrac{3}{7}\cdot\left(-14\right)-\dfrac{2}{7}=-6-\dfrac{2}{7}=\dfrac{-44}{7}\)

e: \(=\dfrac{2^{12}\cdot3^{10}+2^{12}\cdot3^{10}\cdot5}{-2^{11}\cdot3^{11}-2^{12}\cdot3^{12}}\)

\(=\dfrac{2^{12}\cdot3^{10}\cdot6}{-2^{11}\cdot3^{11}\left(1+2\cdot3\right)}=-\dfrac{2^{13}\cdot3^{11}}{2^{11}\cdot3^{11}\cdot7}=\dfrac{-4}{7}\)

6 tháng 1 2018

\(\left(\dfrac{4}{5}\right)^x\) - \(\sqrt{\left(\dfrac{2}{5}\right)^4}\) = \(\sqrt{2^3+3^3-19}\) - \(\left|-3\dfrac{12}{25}\right|\)

\(\left(\dfrac{4}{5}\right)^x\) - \(\sqrt{\left(\dfrac{2}{5}\right)^4}\) = \(\sqrt{8+27-19}\) - \(3\dfrac{12}{25}\)

\(\left(\dfrac{4}{5}\right)^x\) - \(\sqrt{\left(\dfrac{16}{625}\right)}\) = \(\sqrt{16}\) - \(\dfrac{87}{25}\)

\(\left(\dfrac{4}{5}\right)^x\) - \(\dfrac{4}{25}\) = \(4\) - \(\dfrac{87}{25}\)

\(\left(\dfrac{4}{5}\right)^x\) - \(\dfrac{4}{25}\) = \(\dfrac{13}{25}\)

\(\left(\dfrac{4}{5}\right)^x\) = \(\dfrac{13}{25}\) + \(\dfrac{4}{25}\)

\(\left(\dfrac{4}{5}\right)^x\) = \(\dfrac{17}{25}\)

\(\left(\dfrac{4}{5}\right)^x\) = \(\left(\dfrac{4}{5}\right)^{1,783156}\)

Vậy x = 1,783156

Rạc cả tay ! MÀ HÌNH ĐỀ BẠN VIẾT SAI RỒI BẠN :)

5 tháng 1 2018

Đề nâng cao à :3

25 tháng 10 2022

a: \(=2\cdot\dfrac{5}{4}-3\cdot\dfrac{7}{6}+4\cdot\dfrac{9}{8}=\dfrac{5}{2}-\dfrac{7}{2}+\dfrac{9}{2}=\dfrac{7}{2}\)

b: \(=18-16\cdot\dfrac{1}{2}+\dfrac{1}{16}\cdot\dfrac{3}{4}\)

=10+3/64

=643/64

c: \(=\dfrac{2}{3}\cdot\dfrac{9}{4}-\dfrac{3}{4}\cdot\dfrac{8}{3}+\dfrac{7}{5}\cdot\dfrac{5}{14}=\dfrac{3}{2}-2+\dfrac{1}{2}=2-2=0\)

8 tháng 9 2018

\(a,A=\dfrac{7}{35}+\left(-1\dfrac{3}{4}+\dfrac{12}{7}\right)-\left(\dfrac{1}{4}-\dfrac{2}{7}-\dfrac{12}{35}\right)-\dfrac{3}{7}\)\(A=\dfrac{7}{35}-\dfrac{7}{4}+\dfrac{12}{7}-\dfrac{1}{4}+\dfrac{2}{7}+\dfrac{13}{35}-\dfrac{3}{7}\\ A=\left(\dfrac{7}{35}+\dfrac{13}{35}\right)-\left(\dfrac{7}{4}-\dfrac{1}{4}\right)+\left(\dfrac{12}{7}+\dfrac{2}{7}-\dfrac{3}{7}\right)\)

\(A=\dfrac{4}{7}-\dfrac{3}{2}+\dfrac{11}{7}\\ A=\left(\dfrac{4}{7}+\dfrac{11}{7}\right)-\dfrac{3}{2}\\ A=\dfrac{15}{7}-\dfrac{3}{2}=\dfrac{9}{14}\)

25 tháng 10 2022

a: \(=7\cdot\dfrac{6}{7}-5+\dfrac{3\sqrt{2}}{2}=1+\dfrac{3}{2}\sqrt{2}\)

b: \(=-\dfrac{8}{7}-\dfrac{3}{5}\cdot\dfrac{5}{8}+\dfrac{1}{2}=\dfrac{-16+7}{14}-\dfrac{3}{8}=\dfrac{-9}{14}-\dfrac{3}{8}\)

\(=\dfrac{-72-42}{112}=\dfrac{-114}{112}=-\dfrac{57}{56}\)

c: \(=20\sqrt{5}-\dfrac{1}{4}\cdot\dfrac{4}{3}+\dfrac{3}{2}=20\sqrt{5}+\dfrac{3}{2}-\dfrac{1}{3}=20\sqrt{5}+\dfrac{7}{6}\)

 

a: \(=\dfrac{3}{2}\left(-21-\dfrac{1}{3}+1+\dfrac{1}{3}\right)=\dfrac{3}{2}\cdot\left(-20\right)=-30\)

b: \(=-9-4:4+1:\dfrac{4}{3}\)

\(=-10+1\cdot\dfrac{3}{4}=-10+\dfrac{3}{4}=-\dfrac{37}{4}\)

c: \(=2\sqrt{3}+3\sqrt{3}-\sqrt{3}=4\sqrt{3}\)

12 tháng 7 2017

\(5\dfrac{1}{3}+2,5\left(\dfrac{1}{3}-\dfrac{5}{12}\right)\)

\(=\dfrac{16}{3}+2,5.\dfrac{-1}{12}\)

\(=\dfrac{16}{3}+\dfrac{-5}{24}=\dfrac{41}{8}\)

\(\sqrt{12^2-44}-\left(1\dfrac{3}{4}-2\right)^2+\left(-1,5\right)^5:\left(\dfrac{-3}{2}\right)^4\)

\(=\sqrt{144-44}-\left(\dfrac{7}{4}-2\right)^2+\left(-1,5\right)^5:\left(\dfrac{3}{-2}\right)^4\)

\(=\sqrt{100}-\left(\dfrac{-1}{4}\right)^2+\left(1,5\right)^5:\left(\dfrac{3}{-2}\right)^4\)

\(=10-\dfrac{1}{16}+\dfrac{243}{32}:\dfrac{81}{16}\)

\(=\dfrac{183}{16}\)

12 tháng 7 2017

mình tính cái này hay nhầm lẫn lắm nên bấm máy trước khi chép

11 tháng 11 2018

e)\(16\dfrac{2}{7}:\left(-\dfrac{3}{5}\right)+28\dfrac{2}{7}:\left(-\dfrac{3}{5}\right)\)

=\(\left(16\dfrac{2}{7}+28\dfrac{2}{7}\right):\left(-\dfrac{3}{5}\right)\)

=\(\dfrac{312}{7}\)\(:\left(-\dfrac{3}{5}\right)\)

=\(-\dfrac{516}{7}\)

11 tháng 11 2018

a)\(\dfrac{7}{8}.\left(\dfrac{2}{12}+\dfrac{4}{10}\right)\)

=\(\dfrac{7}{8}.\left(\dfrac{1}{6}+\dfrac{2}{5}\right)\)

=\(\dfrac{7}{8}.\)\(\dfrac{17}{30}\)

=\(\dfrac{119}{240}\)

27 tháng 7 2018

B1

a. = 7/3. ( 37/5 - 32/5)

= 7/3 . 1

= 7/3

humPhần b có gì đó sai sao lại có 3:+

c. = 4 + 6 - 3 + 5

= 12

d. = -5/21 : -19/21 : 4/5

= 25/76

B2

a. 1/4 : x =1/2 - 3/4

x = -1/4

x = 1/4 : -1/4

x = -1

b. 2 . | 2x - 3 | = 4 - (-8)

2 . | 2x - 3| = 12

| 2x - 3 | = 12:2

| 2x - 3 | = 6

| x - 3 | = 6:2

| x - 3 | = 3

=> x - 3 = +- 3

* x - 3 = 3

x = 6

* x - 3 = -3

x = 0

Chúc bạn vui vẻ yeu

28 tháng 7 2018

b. = 3 : 9/4 + 1/9 .6

= 4/3 + 2/3

= 2