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Bài làm:
1)3x2 + 5y - 3xy - 5x = (3x2 - 3xy) + (5y - 5x)
= 3x(x - y) + 5(y - x)
= 3x(x - y) - 5(x - y)
(3x - 5)(x - y)
2)3y2 - 3z2 + 3x2 + 6xy = (3x2 + 6xy + 3y2) - 3z2
= (\(\sqrt{3x}\) + \(\sqrt{3y}\))2 - (\(\sqrt{3z}\))2
= (\(\sqrt{3x}\) + \(\sqrt{3y}\) - \(\sqrt{3z}\)).(\(\sqrt{3x}\) + \(\sqrt{3y}\) + \(\sqrt{3z}\))
4)x2 - 25 - 2xy + y2 = (x2 - 2xy + y2) - 25
= (x - y)2 - 52
= (x - y - 5).(x - y + 5)
5)x5 - 3x4 + 3x3 - x2 = x2.(x3 - 3x2 - 3x - 1)
Còn câu 3) Vàng sẽ nghĩ sau :v
a) x2 + 6x + 9 = x2 + 2 . x . 3 + 32 = (x + 3)2
b) 10x – 25 – x2 = -(-10x + 25 +x2) = -(25 – 10x + x2)
= -(52 – 2 . 5 . x – x2) = -(5 – x)2
c) 8x3 - 1/8 = (2x)3 – (1/2)3 = (2x - 1/2)[(2x)2 + 2x . 12 + (1/2)2]
= (2x - 1/2)(4x2 + x + 1/4)
d)1/25x2 – 64y2 = (1/5x)2(1/5x)2- (8y)2 = (1/5x + 8y)(1/5x - 8y)
Bài làm
a) 4x2 - 6x
= 2x( 2x - 3 )
b) 9x4y3 + 3x2y4
= 3x2y3( 3x2 + y )
c) x3 - 2x2 + 5x
= x( x2 - 2x + 5 )
d) 3x( x - 1 ) + 5( x - 1 )
= ( x - 1 )( 3x + 5 )
e) 2x2( x + 1 ) + 4( x + 1 )
= ( x + 1 )( 2x2 + 4 )
= ( x + 1 )2( x2 + 2 )
= 2( x + 1 )( x2 + 2 )
f) -3x - 6xy + 9xz
= -( 3x + 6xy - 9xz )
= -3x( 1 + 2y - 3z )
# Học tốt #
3x^2 +3y^2 -6xy -12
=3(x^2 - 2xy +y^2 - 2^2 )
=3 (x-y)^2 - 2^2
=3(x-y-2)(x-y+2)
3(x+y) -(x^2+2xy+y^2)
=3(x+y) -(x+y)^2
(x+y)(3-x-y)
a,3x2-6x+9x2
=>12x2-6x
=>6x(2x-1)
b,10x(x-y)-6y(y-x)
=>10x(x-y)-6y(-(x-y))
=>10x(x-y)+6y(x-y)
=>2(x-y)(5x+3y)
c,3x2+5y-3xy-5x
=>3x(x-y)-5(x-y)
=>(x-y)(3x-5)
d,3y2-3z2+3x2+6xy
=>3(y2-z2+x2+2xy)
=>3[(y+x)2-z2]
=>3(y+x-z)(y+x+z)
e,16x3+54y3
=>2(8x3+27y3)
=>2(2x+3y)(4x2-6xy+9y2)
g,x2-25-2xy+y2
=>(x-y)2-25
=>(x-y-5)(x-y+5)
h,x5-3x4+3x3-x2
=>x2(x3-3x2+3x-1)
=>x2(x-1)3
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