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\(\frac{6}{1\times3\times7}+\frac{6}{3\times7\times9}+\frac{6}{7\times9\times13}+\frac{6}{9\times13\times15}+\frac{6}{13\times15\times9}\)
\(=\frac{1}{1\times3}-\frac{1}{3\times7}+\frac{1}{3\times7}-\frac{1}{7\times9}+\frac{1}{7\times9}-\frac{1}{9\times13}+\frac{1}{9\times13}-\frac{1}{13\times15}+\frac{1}{13\times15}-\frac{1}{15\times9}\)
\(=\frac{1}{1\times3}-\frac{1}{15\times9}=\frac{1}{3}-\frac{1}{135}=\frac{45}{135}-\frac{1}{135}=\frac{44}{135}\)
= 54/6. [6/1.3.7 +6/3.7.9 +6/7.9.13 + 6/9.13.15]
=54/6 [1/1.3-1/3.7 + 1/3.7 - 1/7.9 + 1/7.9 - 1/9.13 + 1/9.13 -1/13.15]
=54/6[1/3- 1/13.15]
=54/6 .64/195
=192/65
\(\frac{27.4500+135.550.2}{2+4+6+...+18}\)
\(=\frac{27.10.450+135.2.550}{\left(2+18\right).9:2}\)
\(=\frac{270.450+270.550}{20.9:2}\)
\(=\frac{270.\left(450+550\right)}{9.20:2}\)
\(=\frac{27.10.1000}{9.10}\)
\(=\frac{3.1000}{1}=3000\)
\(\frac{43}{20}+\frac{17}{6}:\left(\frac{5}{8}+\frac{7}{30}\right)\)
\(=\frac{43}{20}+\frac{17}{6}\cdot\frac{120}{103}\)
\(=\frac{43}{20}+\frac{340}{103}\)
\(=\frac{11229}{2060}\)
a) \(\frac{2}{5}+\left(\frac{2}{8}+\frac{3}{5}+\frac{6}{8}\right)=\left(\frac{2}{5}+\frac{3}{5}\right)+\left(\frac{2}{8}+\frac{6}{8}\right)=1+1=2\)
b) \(\frac{6}{9}+\left(\frac{15}{25}+\frac{12}{9}+\frac{6}{15}\right)=\left(\frac{6}{9}+\frac{12}{9}\right)+\left(\frac{15}{25}+\frac{6}{15}\right)\)
\(=2+\left(\frac{3}{5}+\frac{2}{5}\right)=2+1=3\)