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18 tháng 4 2018

a) \(4.5^2-32:2^5\)

\(=4.25-2^5:2^5\)

\(=100-1\)

\(=99.\)

b) \(9.8.14+6.\left(-17\right)\left(-12\right)+19.\left(-4\right).18\)

\(=9.2.4.14+6.3.\left(-4\right)\left(-17\right)+76.18\)

\(=18.56+18.68+18.76\)

\(=18\left(56+68+76\right)\)

\(=18\left(132+68\right)\)

\(=18.200\)

\(=3600.\)

c) \(\left(\dfrac{-1}{2}\right)^3-2.\left(\dfrac{-1}{2}\right)^2+3.\left(\dfrac{-1}{2}\right)+1\)

\(=\left(\dfrac{-1}{2}\right)\left[\left(\dfrac{-1}{2}\right)^2+2.\dfrac{-1}{2}+3\right]+1\)

\(=\left(\dfrac{-1}{2}\right)\left[\dfrac{1}{4}+\left(-1\right)+3\right]+1\)

\(\)\(=\left(\dfrac{-1}{2}\right)\left[\dfrac{1}{4}+2\right]+1\)

\(=\left(\dfrac{-1}{2}\right).\dfrac{9}{4}+1\)

\(=\dfrac{-9}{8}+1\)

\(=\dfrac{-1}{8}\)

12 tháng 7 2017

a) \(\frac{18^4.3^2.8^3}{27^3.16^2}=\frac{\left(2.3^2\right)^4.3^2.\left(2^3\right)^3}{\left(3^3\right)^3.\left(2^4\right)^2}=\frac{2^4.2^9.3^8.3^2}{3^9.2^8}=\frac{2^{13}.3^{10}}{3^9.2^8}=3.2^5=96\)

b) \(\frac{35^5.9^3.8^5}{81^4.32^5}=\frac{35^5.\left(3^2\right)^3.\left(2^3\right)^5}{\left(3^4\right)^4.\left(2^5\right)^5}=\frac{35^5.3^6.2^{15}}{3^{16}.2^{25}}=\frac{35^5}{3^{10}.2^{10}}=\frac{35^5}{6^{10}}\)

c) \(\frac{48^5.18^2}{81^2.34^4}=\frac{\left(2^4.3\right)^5.\left(2.3^2\right)^2}{\left(3^4\right)^2.\left(2.17\right)^4}=\frac{2^{20}.3^5.2^2.3^4}{3^8.2^4.17^4}=\frac{2^{22}.3^9}{3^8.2^4.17^4}=\frac{2^{18}.3}{17^4}\)

d) \(\frac{54^7.27^3.16^2}{243^2.64^3}=\frac{\left(2.3^3\right)^7.\left(3^3\right)^3.\left(2^4\right)^2}{\left(3^5\right)^2.\left(2^6\right)^3}=\frac{2^7.3^{21}.3^9.2^8}{3^{10}.2^{18}}=\frac{2^{15}.3^{30}}{3^{10}.2^{18}}=\frac{3^{20}}{2^3}\)

12 tháng 7 2017

a)=245482,813

b)=9.779744327x1014

tự giải nốt 

23 tháng 7 2017

a, =7^(8-6)= 7^2

b,=(18-9)^3=9^3

25 tháng 7 2017

Thanks các bn nha ! 

29 tháng 10 2021

a) 12 : { 400 : [500 – (125 + 25 . 7)]} 

=12 : { 400 : [500 – (125 + 175)]} 

=12 : [ 400 : [500 – 300)]

=12 : (400:200)

=12:2=6

b) 5 . 22 – 18 : 3

=5.4-6

=20-6=14

c) 18 : 3 + 182 + 3.(51 : 17)

=5+182+3.3

=187+9=196

d) 25 . 8 – 12.5 + 170 : 17 – 8

=200-60+10-8

=142

e) 2.52+ 3: 710 – 54: 33 

=2.25+3:1-54:27

=50+3-2

=51

f) 189 + 73 + 211 + 127

=(189+211)+(73+127)
=400+200=600

g) 375 : {32 – [ 4 + (5. 32– 42)]} – 14 )

 =375 : {32 – [ 4 + (160– 42)]} – 14 )

 =375 : [32 – ( 4 + 118) – 14 ]

=375:(32-122-14)

=375:-104

=-375/104

h) (52022 + 52021) : 52021

=(52022:52021)+(52021:52021)

=5+1=6

183:93 = (18:9)3

           =23

            =8

8 tháng 9 2016

18 mu 3 chia 9 mu 3 bang 18 mu 3 phan ra bang (9.2) mu 3 bang 9 mu 3 nhan 2 mu 3 9 mu 3 chia cho nhau bang 1 nhan 2 mu 3 =8

b 125 mu 3 = 25 mu 9 chia 25 mu 4 = 25 mu 5

26 tháng 1 2018

2017^0-5*x=-49 =>1-5*x=-49 => 5*x = 49 + 1 =>  5*x=50 => x=10

-17*53-21*(-17)-17 =(-17)*(53-21+1)=(-17)*23=391

6 tháng 7 2016

9920 = 992.10 = (992)10 = 980110 < 999910 ( vì 9801 < 9999 ) nên 9920<999910.

317>316 = 32.8 = (32)8 = 98

232 = 24.8 = (24)8 = 168

168 > 98 ( vì 16>9 ) nên 317<232

a: =18x941+18x59

=18(941+59)

=18x1000=18000

b: \(=81:27-16:8=3-2=1\)

c: =30-40+25=-10+25=15

d: =17(85+15)-150=1700-150=1550

e: =-150-180-200=-530

f: =17+15+40=72

10 tháng 12 2017

d)

\(152-3.\left\{\left[32-2\left(36\div x^2+7\right)\right]+42\right\}=-4\)

\(\Rightarrow3.\left\{\left[32-2\left(36\div x^2+7\right)\right]+42\right\}=152-\left(-4\right)\)

\(\Rightarrow3.\left\{\left[32-2\left(36\div x^2+7\right)\right]+42\right\}=156\)

\(\Rightarrow\left[32-2\left(36\div x^2+7\right)\right]+42=156\div3\)

\(\Rightarrow\left[32-2\left(36\div x^2+7\right)\right]+42=52\)

\(\Rightarrow32-2\left(36\div x^2+7\right)=52-42\)

\(\Rightarrow32-2\left(36\div x^2+7\right)=10\)

\(\Rightarrow2\left(36\div x^2+7\right)=32-10\)

\(\Rightarrow2\left(36\div x^2+7\right)=22\)

\(\Rightarrow36\div x^2+7=22\div2\)

\(\Rightarrow36\div x^2+7=11\)

\(\Rightarrow36\div x^2=11-7\)

\(\Rightarrow36\div x^2=4\)

\(\Rightarrow x^2=36\div4\)

\(\Rightarrow x^2=9\)

\(\Rightarrow x^2=3^2\)

\(\Rightarrow x=3\)

Vậy \(x=3\)

31 tháng 7 2017

a, (0,25)3.32
= 0,5
b, \(\dfrac{72^3.54^2}{108^4}=\dfrac{\left(2^3.3^2\right)^3.\left(2.3^3\right)^2}{\left(2^2.3^3\right)^4}\)\(=\dfrac{2^9.3^6.2^2.3^6}{2^8.3^{12}}\)
\(=\dfrac{2^{11}.3^{12}}{2^8.3^{12}}=2^3\)
c, \(\dfrac{81^{11}.3^{17}}{27^{10}.9^{15}}=\dfrac{\left(3^4\right)^{11}.3^{17}}{\left(3^3\right)^{10}.\left(3^2\right)^{15}}=\dfrac{3^{44}.3^{17}}{3^{30}.3^{30}}\)\(=\dfrac{3^{61}}{3^{60}}=3\)
@Lớp 6B Đoàn Kết