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C = ( 23 . 21 - 23 . 17 ) + 1253 : (52)3 . 20180
C = ( 8 . 21 - 8 . 17 ) + 1953125 :253 . 1
C = ( 168 - 136 ) + 1953125 : 15625 . 1
C = 32 + 125 . 1
C = 32 + 125
C = 157
Chúc bạn học tốt !
C = ( 23 . 21 - 23 . 17 ) + 1253 : (52)3 . 20180
C = [23 . (21 - 17)] + 1253 : 56 . 1
C = [8 . 4] + 1253 : 1252 . 1
C = 32 + 125 . 1
C = 32 + 125
C = 157.
\(\dfrac{3}{5.7}+\dfrac{3}{7.9}+...+\dfrac{3}{59.61}\)
= \(\dfrac{2}{2}.\left(\dfrac{3}{5.7}+\dfrac{3}{7.9}+...+\dfrac{3}{59.61}\right)\)
= \(\dfrac{3}{2}.\left(\dfrac{2}{5.7}+\dfrac{2}{7.9}+...+\dfrac{2}{59.61}\right)\)
= \(\dfrac{3}{2}.\left(\dfrac{1}{5}-\dfrac{1}{7}+\dfrac{1}{7}-\dfrac{1}{9}+...+\dfrac{1}{59}-\dfrac{1}{61}\right)\)
= \(\dfrac{3}{2}.\left(\dfrac{1}{5}-\dfrac{1}{61}\right)\)
=\(\dfrac{3}{2}.\dfrac{56}{305}\)
= \(\dfrac{78}{305}\)
\(\left(x^2-4\right)\left(6-2x\right)=0\) ⇔ \(x^2-4=0\) hoặc \(6-2x=0\)
*Nếu \(x^2-4=0\)
⇒ x2 = 4
⇒ x ∈ {2 ; -2}
*Nếu \(6-2x=0\)
⇒2x = 6
⇒ x = 6 : 2 = 3
Vậy x ∈ { -2 ; 2 ; 3 }
\(A=1+3+3^2+3^3+...+3^{20}\)
\(\Rightarrow3A=3+3^2+3^3+...+3^{21}\)
\(\Rightarrow3A-A=\left(3+3^2+3^3+...+3^{21}\right)-\left(1+3+3^2+3^3+...+3^{20}\right)\)
\(\Rightarrow2A=3^{21}-1\)
\(\Rightarrow A=\frac{3^{21}-1}{2}=\frac{3^{21}}{2}-\frac{1}{2}\)
Ta lại có:
\(B=\frac{3^{21}}{2}\)
\(\Rightarrow B-A=\left(\frac{3^{21}}{2}-\frac{1}{2}\right)-\frac{3^{21}}{2}=\frac{1}{2}\)
7x - x = 521: 519 + 3.22 - 70
=> 6x = 52 + 3.4 - 1
=> 6x = 25 + 12 - 1
=> 6x = 36
=> x = 36 : 6
=> x = 6
2x : 23 = 16
=> 2x = 16.23
=> 2x = 128
=> 2x = 27
=> x = 7
32x + 3 - 9x + 1 = 2.310
=> 32x + 3 - 32x + 2 = 2.310
=> 32x + 2. 3 - 32x + 2 = 2.310
=> 32x + 2. (3 - 1) = 2.310
=> 32x + 2.2 = 2.310
=> 32x + 2 = 310
=> 2x + 3 = 10
=> 2x = 10 - 3
=> 2x = 7
=> x = 7/2
a) \(7x-x=5^{21}:5^{19}+3.2^2-7^0\)
\(\Rightarrow6x=25+12-1\)
\(\Rightarrow x=6\)
b) \(2^x:2^3=16\)
\(\Rightarrow2^x=2^4.2^3=2^7\)
\(\Rightarrow x=7\)
c) \(3^{2x+3}-9^{x+1}=2.3^{10}\)
\(\Rightarrow9^x.27-9^x.9=2.3^{10}\)
\(\Rightarrow9^x.18=2.3^{10}\)
\(\Rightarrow9^x=3^8=9^4\)
\(\Rightarrow x=4\)
a,
625^5=(125.5)^5=125^5.5^5
125^7 =125^5 . 5^2
Vì 5^5 > 5^2
=> 625^5 > 125^7
Đừng đăng lại nữa :vv
= 2011 - [39 - (8 . 3 - 21)2] : (-3) + 1
= 2011 - [39 - (24 - 21)2 ] : (-3) + 1
= 2011 - (39 - 9) : (-3) + 1
= 2011 - 30 : (-3) + 1
= 2011 + 10 + 1
= 2021 + 1
= 2022