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\(\left(2m-a\right)^2+\left(2m-b\right)^2+\left(2m-c\right)^2+\left(2m-d\right)^2+\left(2m-e\right)^2\)
\(=4m^2-4ma+a^2+4m^2-4mb+b^2+4m^2-4mc+c^2+4m^2-4md+d^2+4m^2-4me+e^2\)
\(=20m^2-4m\left(a+b+c+d+e\right)+a^2+b^2+c^2+d^2+e^2\)
\(=20m^2-4m.5m+a^2+b^2+c^2+d^2+e^2\)
\(=a^2+b^2+c^2+d^2+e^2\)
a) \(\left(a+b+c\right)^2+a^2+b^2+c^2\)
\(=a^2+b^2+c^2+2ab+2bc+2ca+a^2+b^2+c^2\)
\(=a^2+2ab+b^2+b^2+2bc+c^2+c^2+2ca+a^2\)
\(=\left(a+b\right)^2+\left(b+c\right)^2+\left(c+a\right)^2\)
b) \(\left(a+b+c\right)^3-a^3-b^3-c^3\)
\(=\left(b+c\right)\left[\left(a+b+c\right)^2+\left(a+b+c\right)a+a^2\right]-\left(b+c\right)\left(b^2+bc+c^2\right)\)
\(=\left(b+c\right)\left(3a^2+3ab+3bc+3ac\right)\)
\(=3\left(a+b\right)\left(b+c\right)\left(c+a\right)\)
\(VT=\left(m-a\right)^2+\left(2m-b\right)^2+\left(3m-c\right)^2\)
\(=m^2-2am+a^2+4m^2-4bm+9m^2-6mc+c^2\)
\(=14m^2-2m\left(a+2b+3c\right)+a^2+b^2+c^2\)
\(=14m^2-14m^2+a^2+b^2+c^2\) ( do \(a+2b+3c=7m\) )
\(=a^2+b^2+c^2=VP\)
\(\Rightarrowđpcm\)
Ta có: \(VT=\left(m-a\right)^2+\left(2m-b\right)^2+\left(3m-c\right)^2\)
\(=m^2-2ma+a^2+4m^2-4mb+b^2+9m^2-6mc+c^2\)
\(=m^2-2ma+4m^2-4mb+9m^2-6mc+a^2+b^2+c^2\)
\(=m\left(14m-2a-4b-6c\right)+a^2+b^2+c^2\)
\(=-2m\left(-7m+a+2b+6c\right)+a^2+b^2+c^2\)
\(=-2m\left(-7m+7m\right)+a^2+b^2+c^2\)
\(=a^2+b^2+c^2=VP\)
Vậy (m - a)2 + (2m - b)2 + (3m - c)2 = a2 + b2 + c2.
a^3/b +a^3/b +b^2 >=3.a^2
=>2a^3/b +b^2>=3a^2
tuong tu
2b^3/c +c^2 >=3.b^2
2c^3/a +a^2 >=3.c^2
cog lai ta dc
2(a^3/b+b^3/c+c^3/a) +(a^2+b^2+c^2) >=3.(a^2+b^2+c^2)
=>a^3/b+b^3/c+c^3/a >=a^2+b^2+c^2
mat khc
a^2+b^2+c^2>=ab+bc+ca
nen
a^3/b+b^3/c+c^3/a >=ab+bc+ca
dau = xay ra khi a=b=c
k nha
a^3/b +a^3/b +b^2 >=3.a^2
=>2a^3/b +b^2>=3a^2
tuong tu
2b^3/c +c^2 >=3.b^2
2c^3/a +a^2 >=3.c^2
cog lai ta dc
2(a^3/b+b^3/c+c^3/a) +(a^2+b^2+c^2) >=3.(a^2+b^2+c^2)
=>a^3/b+b^3/c+c^3/a >=a^2+b^2+c^2
mat khc
a^2+b^2+c^2>=ab+bc+ca
nen
a^3/b+b^3/c+c^3/a >=ab+bc+ca
dau = xay ra khi a=b=c
Ta có
\(\left(2m-a\right)^2+\left(3m-b\right)^2+\left(3m-c\right)^2=\)
\(=4m^2-4ma+a^2+9m^2-6mb+b^2+9m^2-6mc+c^2=\)
\(=22m^2-2m\left(2a+3b+3c\right)+a^2+b^2+c^2=\)
\(=22m^2-2m.11m+a^2+b^2+c^2=a^2+b^2+c^2\)