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b) Ta có:
\(64^8=\left(8^2\right)^8=8^{16}=\left(2^3\right)^{16}=2^{48}\)
\(16^{12}=\left(2^4\right)^{12}=2^{48}\)
Vì \(2^{48}=2^{48}\) nên \(64^8=16^{12}\)
a) Ta có:
\(10^{20}=\left(2.5\right)^{20}=2^{20}.5^{20}\)
\(90^{10}=\left(2^2.3.5\right)^{10}=2^{20}.3^{10}.5^{10}\)
Vì \(2^{20}.5^{20}< 2^{20}.3^{10}.5^{10}\) nên \(10^{20}>90^{10}\)
\(\left(\frac{1}{16}\right)^{10}\) và \(\left(\frac{1}{2}\right)^{50}\)
Ta có: \(\left(\frac{1}{2}\right)^{50}=\left[\left(\frac{1}{2}\right)^5\right]^{10}=\left(\frac{1}{32}\right)^{10}\)
Do \(\frac{1}{6}>\frac{1}{32}\Rightarrow\left(\frac{1}{6}\right)^{10}>\left(\frac{1}{32}\right)^{10}\)
Vậy \(\left(\frac{1}{16}\right)^{10}>\left(\frac{1}{2}\right)^{50}\)
a) \(10^{20}\) và \(9^{10}\)
Vì 10 > 9 ; 20 > 10
nên \(10^{20}>9^{10}\)
Vậy \(10^{20}>9^{10}\)
b) \(\left(-5\right)^{30}\) và \(\left(-3\right)^{50}\)
Ta có: \(\left(-5\right)^{30}=5^{30}=\left(5^3\right)^{10}=125^{10}\)
\(\left(-3\right)^{50}=3^{50}=\left(3^5\right)^{10}=243^{10}\)
Vì 243 > 125 nên \(125^{10}< 243^{10}\)
Vậy \(\left(-5\right)^{30}< \left(-3\right)^{50}\)
c) \(64^8\) và \(16^{12}\)
Ta có: \(64^8=\left(4^3\right)^8=4^{24}\)
\(16^{12}=\left(4^2\right)^{12}=4^{24}\)
Vậy \(64^8=16^{12}\left(=4^{24}\right)\)
d) \(\left(\frac{1}{6}\right)^{10}\) và \(\left(\frac{1}{2}\right)^{50}\)
Ta có: \(\left(\frac{1}{6}\right)^{10}=\left[\left(\frac{1}{2}\right)^4\right]^{10}=\left(\frac{1}{2}\right)^{40}\)
Vì 40 < 50 nên \(\left(\frac{1}{2}\right)^{40}< \left(\frac{1}{2}\right)^{50}\)
Vậy \(\left(\frac{1}{16}\right)^{10}< \left(\frac{1}{2}\right)^{50}\)
a/
\(2^{225}=\left(2^3\right)^{75}=8^{75}\)
\(3^{150}=\left(3^2\right)^{75}=9^{75}\)
\(8< 9\Rightarrow8^{75}< 9^{75}\Rightarrow2^{225}< 3^{150}\)
b/
\(12^8.9^{12}=\left(2^2\right)^8.3^8.\left(3^2\right)^{12}=2^{16}.3^{32}\)
\(18^{16}=2^{16}.\left(3^2\right)^{16}=2^{16}.3^{32}\)
\(\Rightarrow12^8.9^{12}=18^{16}\)
c/
\(45^{10}.5^{30}=\left(3^2\right)^{10}.5^{10}.5^{30}=3^{20}.5^{40}\)
\(75^{20}=3^{20}.\left(5^2\right)^{20}=3^{20}.5^{40}\)
\(\Rightarrow45^{10}.5^{30}=75^{20}\)
Ta có
\(64^8=\left(2^6\right)^8=2^{48}\)
\(16^{12}=\left(2^4\right)^{12}=2^{48}\)
\(\Rightarrow64^8=16^{12}\)
a) 1020 và 9010
ta có: 1020 = (102)10 = 10010
vì 100 > 90 nên 10010 > 9010
vậy 1020 > 9010
b) tương tự nhé
ok mk nhé!!! 5656757567687686712676576568768763575475437445756725676568
a) 1020=(102)10=10010>9010
b) 648=(43)8=424=(42)12=1612