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3) C thiếu đề
4) \(D=\frac{1}{9}-\left|\frac{-5}{23}\right|-\left(\frac{-5}{23}+\frac{1}{9}+\frac{25}{7}\right)+\frac{50}{4}-\frac{7}{30}\)
\(D=\frac{1}{9}-\frac{5}{23}+\frac{5}{23}-\frac{1}{9}-\frac{25}{7}+\frac{50}{4}-\frac{7}{30}\)
\(D=\frac{1}{9}-\frac{1}{9}-\frac{5}{23}+\frac{5}{23}+\frac{-25}{7}+\frac{50}{4}-\frac{7}{30}\)
\(D=0+0+\frac{125}{14}-\frac{7}{30}\)
\(D=\frac{913}{105}\)
=> \(C=\frac{3}{1.4}+\frac{5}{4.9}+\frac{7}{9.16}+...+\frac{19}{81.100}\)
C = \(1-\frac{1}{4}+\frac{1}{4}-\frac{1}{9}+\frac{1}{9}-\frac{1}{16}+....+\frac{1}{81}-\frac{1}{100}\)
C = \(1-\frac{1}{100}<1\)
=> C < D
\(\left[18\frac{1}{6}-\left(0,06:7\frac{1}{2}+3\frac{2}{5}\cdot0,38\right)\right]:\left(19-2\frac{2}{3}\cdot4\frac{3}{4}\right)\)
\(< =>\left[\frac{109}{6}-\left(\frac{3}{50}:\frac{15}{2}+\frac{17}{5}\cdot\frac{19}{50}\right)\right]:\left(19-\frac{8}{3}\cdot\frac{19}{4}\right)\)
\(< =>\left[\frac{109}{6}-\left(\frac{1}{125}+\frac{323}{250}\right)\right]:\left(19-\frac{38}{3}\right)\)
\(< =>\left[\frac{109}{6}-\frac{13}{10}\right]:\frac{19}{3}\)
\(< =>\frac{253}{15}:\frac{19}{3}\)
\(< =>\frac{253}{95}\)
\(\frac{42}{-37}va\frac{-56}{43}\)
\(\frac{42}{-37}=\frac{-42}{37}=\frac{-1806}{1591}\)
\(\frac{-56}{37}=\frac{-2408}{1591}\)
Vì\(\frac{-1806}{1591}>\frac{-2408}{1591}\)
=>\(\frac{42}{-37}>\frac{-56}{43}\)
\(\frac{217}{18}va\frac{217}{19}\)
Vì\(\frac{217}{18}>\frac{217}{19}\)
=>\(\frac{217}{18}>\frac{217}{19}\)
\(\frac{-9}{14}va\frac{19}{-25}\)
\(\frac{-9}{14}=\frac{-225}{350};\frac{19}{-25}=\frac{-19}{25}=\frac{-266}{350}\)
Vì\(\frac{-225}{350}>\frac{-266}{350}\)
=>\(\frac{-9}{14}>\frac{19}{-25}\)
Chúc bạn học tốt!
đáp án N > M , mk ko chắc,mk làm theo cách lớp 5
\(\frac{9^{20}+3}{9^{19}+3}=\frac{9\cdot20+3}{9\cdot19+3}=\frac{183}{174}\)
\(\frac{7^{19}+3}{7^{18}+3}=\frac{7\cdot19+3}{7\cdot18+3}=\frac{136}{129}\)
quy đồng 2 số lại thành N > M