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A, B, C,... là tên của bài bạn nha
VD: A, 15+x=15
B, 16+14+14+14
a) 2.84 = 2.(23)4 = 2.212 = 213
b) 256 . 1253 = (52)6 . (53)3 = 512.59 = 521
c) 6255 : 257 = (54)5 : (52)7 = 520:514 = 56
d) 123.33 = (12.3)3 = 363
e) 23.84.163 = 23.(23)4.(24)3 = 23.212.212 = 227
f) 643 . 43 : 163 = (43)3 . 43 : (42)3 = 49.43:46 = 412:46 = 46
G) 812 : ( 32 . 27 ) = (34)2 : 32 . 33 = 38 : 32 . 33 = 36.33 = 39
a) 2 . 84=2.(22)4=2.28=21+8=29
b) 256 . 1253=(22)6.(53)3=212.59=212+9=221
c) 6255 : 257=(54)5:(52)7=520:514=520-14=56
d) 123 . 33=(12.3)3=363
e) 23 . 84 . 163=23.(23)4.(24)3=23.212.212=23+12+12=227
f) 643 . 43 : 163=(43)3.43:(42)3=49.43:46=49+3-6=46
g) 812 : ( 32 . 27 )=(34)2:(32.33)=38:32+3=38:35=38-5=33
a)\(2.2.2.3.3=2^3.3^2\)
b)\(8.8.8.2=2^3.2^3.2^3.2=2^{10}\)
c)\(8^4.16^5=\left(2^3\right)^4.\left(2^4\right)^5=2^{12}.2^{20}=2^{32}\)
d)\(5^{40}.125^2.625^3=5^{40}.\left(5^3\right)^2.\left(5^4\right)^3=5^{40}.5^6.5^{12}=5^{58}\)
e)\(27^4.81^{10}=\left(3^3\right)^4.\left(3^4\right)^{10}=3^{12}.3^{40}=3^{52}\)
f)\(10^3.100^5.1000^4=10^3.\left(10^2\right)^5.\left(10^3\right)^4=10^3.10^{10}.10^{12}=10^{25}\)
Bài 1:
a) 6/2 x+ 1 = 2/7
6/2 x = 2/7 - 1
6/2 x = 2/7 - 7/7
6/2 x = -5/7
x = - 5/7 : 6/2
x = - 5/7 . 2/6
x = -5/21
Ủng hộ nha! :)
BÀI 1 a 6/2x+1=2/7
6/2x=2/7-1
6/2x=-5/7
6*7=5*2x
42=5*2x
42/5=2x
x=42/5:2
x=21/5
Giải:
a) \(4.2^5:\left(2^3.\dfrac{1}{16}\right)\)
\(=4.2^5:\dfrac{2^3}{16}\)
\(=2^2.2^5:\dfrac{2^3}{2^4}\)
\(=2^7:\dfrac{1}{2}\)
\(=2^6=64\)
Vậy ...
b) \(\dfrac{8^5.10^4.25^3}{16^4.625^3}\)
\(=\dfrac{2^{15}.2^4.5^4.5^6}{2^8.5^{12}}\)
\(=\dfrac{2^{19}.5^{10}}{2^8.5^{12}}\)
\(=\dfrac{2^{11}}{5^2}\)
Vậy ...
c) \(C=2^{200}-2^{199}+2^{198}-2^{197}+...+2^2-2\)
\(\Leftrightarrow C=\left(2^{200}-2^{199}\right)+\left(2^{198}-2^{197}\right)+...+\left(2^2-2\right)\)
\(\Leftrightarrow C=2^{199}\left(2-1\right)+2^{197}\left(2-1\right)+...+2\left(2-1\right)\)
\(\Leftrightarrow C=2^{199}+2^{197}+...+2\)
\(\Leftrightarrow4C=2^{201}+2^{199}+...+2^3\)
\(\Leftrightarrow3C=4C-C=2^{201}-2\)
\(\Leftrightarrow C=\dfrac{2^{201}-2}{3}\)
Vậy ...
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