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9 tháng 7 2018

a ) 

\(x^2y+x^2+xy+xy^2+xy+y^2\)

\(=\left(x^2y+xy^2\right)+\left(x^2+2xy+y^2\right)\)

\(=xy\left(x+y\right)+\left(x+y\right)^2\)

\(=\left(x+y\right)\left(xy+1\right)\)

b ) 

\(x^2+xy+x+xy+y+y^2\)

\(=\left(x^2+2xy+y^2\right)+\left(x+y\right)\)

\(=\left(x+y\right)^2+\left(x+y\right)\)

\(=\left(x+y\right)\left(x+y+1\right)\)

c ) 

\(x^2+y^2+z^2+2z\left(x+y\right)+2xy\)

\(=\left(x^2+2xy+y^2\right)+z^2+2z\left(x+y\right)\)

\(=\left(x+y\right)^2+z^2+2z\left(x+y\right)\)

\(=\left(x+y\right)\left(x+y+2z\right)+z^2\)

1 tháng 11 2020

a) \(A=3x\left(x^2-2x+3\right)-x^2.\left(3x-2\right)+5\left(x^2-x\right)\)

\(=3x^3-6x^2+9x-3x^3+2x^2+5x^2-5x\)

\(=x^2+4x\)

Thay \(x=5\)vào biểu thức ta có: \(A=5^2+4.5=25+20=45\)

b) \(B=x\left(x^2+xy+y^2\right)-y\left(x^2+xy+y^2\right)\)

\(=\left(x-y\right)\left(x^2+xy+y^2\right)=x^3-y^3\)

Thay \(x=10\)\(y=-1\)vào biểu thức ta có: 

\(B=10^3-\left(-1\right)^3=1000+1=1001\)

a) Ta có: \(VP=x^2+y^2+z^2-2xy+2yz-2zx\)

\(=\left(x^2-xy-xz\right)+\left(y^2-xy+yz\right)+\left(z^2-yz-zx\right)\)

\(=x\left(x-y-z\right)+y\left(y-x+z\right)+z\left(z-y-x\right)\)

\(=x\left(x-y-z\right)-y\left(x-y-z\right)-z\left(x-y-z\right)\)

\(=\left(x-y-z\right)\left(x-y-z\right)\)

\(=\left(x-y-z\right)^2=VT\)(đpcm)

b) Ta có: \(VP=x^2+y^2+z^2+2xy-2yz-2zx\)

\(=\left(x^2+xy-zx\right)+\left(y^2+xy-2yz\right)+\left(z^2-yz-zx\right)\)

\(=x\left(x+y-z\right)+y\left(x+y-z\right)+z\left(z-y-x\right)\)

\(=\left(x+y-z\right)\left(x+y\right)-z\left(x+y-z\right)\)

\(=\left(x+y-z\right)\left(x+y-z\right)\)

\(=\left(x+y-z\right)^2=VT\)(đpcm)

c) Ta có: \(VP=x^4-y^4\)

\(=\left(x^2-y^2\right)\left(x^2+y^2\right)\)

\(=\left(x-y\right)\left(x+y\right)\left(x^2+y^2\right)\)

\(=\left(x-y\right)\left(x^3+xy^2+x^2y+y^3\right)=VT\)(đpcm)

d) Ta có: \(VT=\left(x+y\right)\left(x^4-x^3y+x^2y^2-xy^3+y^4\right)\)

\(=x^5-x^4y+x^3y^2-x^2y^3+xy^4+x^4y-x^3y^2+x^2y^3-xy^4+y^5\)

\(=x^5+y^5=VP\)(đpcm)

14 tháng 8 2020

a) \(\left(x+y-z\right)^2=\left[\left(x+y\right)-z\right]^2\)

\(=\left(x+y\right)^2-2\left(x+y\right)z+z^2\)

\(=x^2+2xy+y^2-2zx-2yz+z^2\)

\(=x^2+y^2+z^2+2xy-2yz-2zx\)

b) \(\left(x-y\right)\left(x^3+x^2y+xy^2+y^3\right)\)

\(=x^4+x^3y+x^2y^2+xy^3-x^3y-x^2y^2-xy^3-y^4\)

\(=x^4-y^4\)

c) \(\left(x+y\right)\left(x^4-x^3y+x^2y^2-xy^3+y^4\right)\)

\(=x^5-x^4y+x^3y^2-x^2y^3+xy^4+x^4y-x^3y^2+x^2y^3-xy^4+y^5\)

\(=x^5+y^5\)

4 tháng 7 2015

a) 2x(x-3y)+3y(2x+5y)

=2x2-6xy+6xy+15y2

=2x2+15y2

b)(5x-3y)(2x+y)-x(10x-y)

=10x2+5xy-6xy-3y2-10x2+xy

=0

c)(x-y)(x2+xy+y2)-(x+y)(x2-xy+y2)

=x3-y3-(x3+y3)

=x3-y3-x3-y3

=-2y3