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\(\frac{\left(-11\right)^5.13^7}{11^5.13^8}=\frac{\left(-11\right)^5.13^7}{11^5.13^7}.\frac{1}{13}=-1.\frac{1}{13}=-\frac{1}{13}\)
\(\frac{-11^5.13^7}{11^5.13^8}=\frac{-11^4.\left(-11\right).13^7}{11^4.11.13^7.13}=\frac{-11}{11.13}=\frac{-11}{143}\)
Hai câu a) và b) bạn chỉ cần xem số mũ rồi trừ số mũ là xong
\(c)\) \(\frac{2^{10}.3^{10}-2^{10}.3^9}{2^9.3^{10}}=\frac{2^{10}.3^9\left(3-1\right)}{2^9.3^{10}}=\frac{2^{10}.3^9.2}{2^9.3^{10}}=\frac{2^{11}.3^9}{2^9.3^{10}}=\frac{2^2}{3}=\frac{4}{3}\)
\(d)\) \(\frac{5^{11}.7^{12}+5^{11}.7^{11}}{5^{12}.7^{12}+9.5^{11}.7^{11}}=\frac{5^{11}.7^{11}\left(7+1\right)}{5^{11}.7^{11}\left(5.7+9\right)}=\frac{8}{35+9}=\frac{8}{44}=\frac{2}{11}\)
Chúc bạn học tốt
\(\left(-\right)\frac{1989\cdot1990+3970}{1992\cdot1991+3984}=\frac{1989\cdot\left(1990+2\right)}{1992\cdot\left(1991+2\right)}=\frac{1989}{1993}\)
\(\left(-\right)\frac{3^{10}\cdot\left(-5\right)^{21}}{\left(-5\right)^{20}\cdot3^{12}}=\frac{3^{10}\cdot\left(-5\right)^{20}\cdot\left(-5\right)}{3^{10}\cdot\left(-5\right)^{20}\cdot3^2}=-\frac{5}{9}\)
\(\left(-\right)\frac{\left(-11\right)^5\cdot13^7}{11^5\cdot13^8}=\frac{11^5\cdot13^7\cdot\left(-1\right)}{11^5\cdot13^7\cdot13}=-\frac{1}{13}\)
\(\left(-\right)\frac{2^{10}\cdot3^{10}-2^{10}\cdot3^9}{2^9\cdot3^{10}}=\frac{2^{10}\cdot3^9\left(3-1\right)}{2^9\cdot3^{10}}=\frac{2^{11}\cdot3^9}{2^9\cdot3^{10}}=\frac{4}{3}\)
\(\frac{-11^{5^{ }}.13^7}{11^5.13^8}\)=\(\frac{11^5.\left(-13^7\right)}{11^5.13^8}\)=\(\frac{-13^7}{13^8}\)=\(\frac{-1}{13}\)
\(\frac{-11^5.13^7}{11^5.13^8}=\frac{-11^5.13^7}{11^5.13^7.13}=\frac{1}{\left(-1\right).13}=\frac{1}{-13}\)