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\(\frac{18.2+9}{27}=\frac{9.2.2+9}{3.9}=\frac{9\left(2.2+1\right)}{3.9}\)
\(\Rightarrow\frac{2.2+1}{3}=\frac{5}{3}\)
\(a.\frac{4.7}{9.32}=\frac{4.7}{4.8.9}=\frac{7}{8.9}=\frac{7}{72}\)
\(b.\frac{990}{2610}=\frac{990\div90}{2610\div90}=\frac{11}{29}\)
\(c.\frac{374}{-506}=\frac{374\div\left(-22\right)}{-506\div\left(-22\right)}=\frac{-17}{23}\)
\(\frac{4\cdot7}{9\cdot32}=\frac{4\cdot7}{9\cdot4\cdot8}=\frac{7}{9\cdot8}=\frac{7}{72}\)
\(\frac{990}{2610}=\frac{2\cdot3^2\cdot5\cdot11}{2\cdot3^2\cdot5\cdot29}=\frac{11}{29}\)
\(\frac{374}{-506}=-\frac{374}{506}=\frac{2\cdot11\cdot17}{2\cdot11\cdot23}=-\frac{17}{23}\)
\(\frac{3600-75}{8400-175}=\frac{75.48-75}{175.48-175}=\frac{75.\left(48-1\right)}{175.\left(48-1\right)}\)
\(=\frac{75}{175}=\frac{25.3}{25.7}=\frac{3}{7}\)
Chỉ còn cách này nữa thôi
\(\frac{3600-75}{8400-175}=\frac{75.48-75}{175.48-175}\)
\(=\frac{75.\left(48-1\right)}{175.\left(48-1\right)}\)
\(=\frac{75}{175}=\frac{3}{7}\)
\(\frac{3600-75}{8400-175}=\frac{3525}{8225}\)
\(=\frac{3}{7}\)
Chúc bạn học tốt nha!
dấu mũ ngược đời v
\(\frac{9^{14}.25^5.8^7}{18^{12}.625^3.24^3}\)
=\(\frac{3.2^3}{5^2}\)=24/25
\(\frac{44116-14}{10290-35}=\frac{44102}{10255}\)
\(\frac{3600-75}{8400-175}=\frac{75\left(48-1\right)}{35\left(240-5\right)}=\frac{15\cdot47}{7\cdot235}=\frac{3\cdot5\cdot47}{7\cdot5\cdot47}=\frac{3}{7}\)
g, \(\frac{44116-14}{10290-35}=\frac{44102}{10255}\)
h, \(\frac{3600-75}{8400-175}=\frac{3525}{8225}=\frac{3}{7}\)