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\(\frac{10.\left(4^6.9^5+6^9.120\right)}{8^4.3^{12}-6^{11}}\)
=\(\frac{2.5.\left[\left(2^2\right)^6.\left(3^2\right)^5+\left(2.3\right)^9.2^3.3.5\right]}{\left(2^3\right)^4.3^{12}-\left(2.3\right)^{11}}\)
=\(\frac{2^{13}.5.3^{10}+2^{13}.5^2.3^{10}}{2^{12}.3^{12}-3^{11}.2^{11}}\)
=\(\frac{2^{13}.5.3^{10}.\left(1+5\right)}{2^{11}.3^{11}.\left(2.3-1\right)}\)
=\(\frac{4.5.6}{3.5}\)
= 8
a/ M = (71+x)-(-24+x)+(-35-x) = 71 + x + 24 - x - 35 - x = (71 + 24 - 35) - x = 95 - 35 - x = 60 - x
b/ N=x-34-[(15+x)-(23-x)] = x - 34 - (15 + x - 23 + x) = x - 34 - (-8 + 2x) = x - 34 + 8 - 2x = -26 - x
\(a,M=\left(71+x\right)-\left(-24+x\right)+\left(-35-x\right)\)
\(=71+x+24-x-35-x\)
\(=60-x\)
\(b,N=x-34-\left[\left(15+x\right)-\left(23-x\right)\right]\)
\(=x-34-\left(15+x-23+x\right)\)
\(=x-34-15-x+23-x\)
\(=-26-x\)
a/ (71+x) - [(-24) - x] + [(-35) - x ]=71+x+24+x-35-x=x+60
b/ x - 34 - [(15 + x) - (23 - x)]=x-34-15-x-23+x=x-72
c/ 26 - [(-x) + 126 - 13) + [(-113) + x]=26+x-126+13-113+x=2x-200=2(x-100)
A = ( 71 + x ) - ( -24 - x ) + ( -35 - x )
= 71 + x - ( -24 ) + x + ( -35 ) + x
= 71 - ( -24 ) + ( -35 ) + x . 3
= 60 + 3x
= 3 ( 20 + x )
B = x - 34 - [ ( 15 + x ) - ( 23 - x ) ]
= x - 34 - [ 15 + x - 23 + x ]
= x - 34 - ( 15 - 23 ) - 2x
= x - 34 - ( -8 ) - 2x
= x - 26 - 2x
= ( -x ) - 26
C ) tương tự
a) Ta có: \(|x+6|\ge0\forall x\)
\(\Rightarrow-|x+6|\le0\forall x\)
\(\Rightarrow2015-|x+6|\le2015-0\forall x\)
Hay \(A\le2015\forall x\)
Dấu "=" xảy ra \(\Leftrightarrow x+6=0\)
\(\Leftrightarrow x=-6\)
Vậy Max A =2015\(\Leftrightarrow x=-6\)
\(A=2015-\left|x+6\right|\)
Ta có : \(\left|x+6\right|\ge0\)
\(\Leftrightarrow2015-\left|x+6\right|\ge2015\)
GTNN của A là 2015 khi \(x+6=0\Leftrightarrow x=-6\)
`a, = 5^3 xx 3^3 = 15^3`
`b, = 12^3 xx 4^3 = 48^3`
`c, = 625^3 xx 8^3 = 5000^3`
`d, = 625 ^3 xx 125^3 = 78125^3`
`e, = 5^20 : 5^14 = 5^6`
1,\(125\cdot27=5^3\cdot3^3=\left(5\cdot3\right)^3=15^3\)
2, \(12^3\cdot64=12^3\cdot4^3=\left(12\cdot4\right)^3=48^3\)
3, \(25^6\cdot8^3=\left(5^2\right)^6\cdot\left(2^3\right)^3=5^8\cdot2^9\)
4, \(25^6\cdot125^3=\left(5^2\right)^3\cdot\left(5^3\right)^3=5^6\cdot5^9=5^{15}\)
5,\(625^5:25^7=\left(5^4\right)^5:\left(5^2\right)^7=5^{20}:5^{14}=5^6\)
0 à ghi đề ko hiểu gì hết
-8 + (x - 35 ) + 6
=(-8 + 6 ) + (x - 35)
= -2 + x + 35
=(-2 + 35) + x
=33 + x
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