Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
a, x+45-[90+(-20)+5-(-45)]
=x+45-[90+(-20)+5+45]
=x+45-90+20-5-45
=x+(45-45)-(90+20)-5
=x+0-110-5
=x-115
vay x-115
b, x+(294+13)+(94-13)
=x+307+81
=x+388
vay x+388
\(\frac{1}{5}+\frac{1}{20}+\frac{1}{44}+...+\frac{1}{170}=\frac{2}{10}+\frac{2}{40}+\frac{2}{88}+...+\frac{2}{340}\)
\(\frac{2}{2x5}+\frac{2}{5x8}+\frac{2}{8x11}+...+\frac{2}{17x20}=2x\left(\frac{1}{2x5}+\frac{1}{5x8}+\frac{1}{8x11}+...+\frac{1}{17x20}\right)\)
\(2x\left(\frac{1}{2}-\frac{1}{5}+\frac{1}{5}-\frac{1}{8}+\frac{1}{8}-\frac{1}{11}+...+\frac{1}{17}-\frac{1}{20}\right)\)=2x\(\left(\frac{1}{2}-\frac{1}{20}\right)\)
2x\(\frac{9}{20}=\frac{9}{10}\)
1+1/A+1/a2+1/a3+1+.../an+1
=1(1/A/a2/a3/...an)
=1.(1/a1+2+3+...+n)
=1.(1/a6+...+n)
=a6+...+n
a,M=2^0-2^1+2^2-2^3+2^4-2^5+.....+2^2012
2M=2^1-2^2+2^3-2^4+2^5-2^5+......-2^2012+2^2013
3M=2^0+2^2013
M=(2^0+2^2013)÷3
Vậy.......
b,N=3-3^2+3^3-3^4+3^5-3^6+.....+3^2011-3^2012
3N=3^2-3^3+3^4-3^5+3^6-3^7+......+3^2012-3^2013
4N=3-3^2013
N=(3-3^2013)÷4
Vậy........
K tao nhé ko lên lớp tao đánh m😈😈😈
Ta có A=1/5+1/20+1/44+...+1/170
=>A=1/10+1/40+1/88+...+1/340
A=\(\frac{1}{2.5}\)+\(\frac{1}{5.8}\)+\(\frac{1}{8.11}\)+......+\(\frac{1}{17.20}\)
A=1/3.(1/2-1/5+1/5-1/8+1/8-1/11+.....+1/17-1/20)
A=1/3.(1/2-1/20)
A=\(\frac{3}{20}\)