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Trả lời :
\(B=\frac{4^2\cdot25^2+32\cdot125}{2^3\cdot5^2}=\frac{\left(2^2\right)^2\cdot\left(5^2\right)^2+2^5\cdot5^3}{2^3\cdot5^2}=\frac{2^4\cdot5^4+2^5\cdot5^3}{2^3\cdot5^2}=\frac{2^3\cdot5^2\left(2\cdot5^2+2^3\cdot5\right)}{2^3\cdot5^2}\)
\(=2\cdot5^2+2^3\cdot5=2\cdot25+8\cdot5=50+40=90\)
\(B=\frac{4^2\cdot25^2+32\cdot125}{2^3\cdot5^2}\)
\(B=\frac{2^4\cdot5^4+2^5\cdot5^3}{2^3\cdot5^2}\)
\(B=\frac{2^4\cdot5^3\left(5+2\right)}{2^3\cdot5^2}\)
\(B=\frac{2^4\cdot5^3\cdot7}{2^3\cdot5^2}\)
B = 2 . 5 . 7
B = 70
Không chắc =))
a.
=(5^7+5^9)(6^8+6^10)(16-4^2)
=(5^7+5^9)(6^8+6^10)(16-16)
=(5^7+5^9)(6^8+6^10).0
=0
a,M=2^0-2^1+2^2-2^3+2^4-2^5+.....+2^2012
2M=2^1-2^2+2^3-2^4+2^5-2^5+......-2^2012+2^2013
3M=2^0+2^2013
M=(2^0+2^2013)÷3
Vậy.......
b,N=3-3^2+3^3-3^4+3^5-3^6+.....+3^2011-3^2012
3N=3^2-3^3+3^4-3^5+3^6-3^7+......+3^2012-3^2013
4N=3-3^2013
N=(3-3^2013)÷4
Vậy........
K tao nhé ko lên lớp tao đánh m😈😈😈
a)\(\frac{484}{-860}=\frac{121}{215}\)
b)\(\frac{14.20-70.13}{21.10+7.80}=\frac{7.2.10.2-7.10.13}{7.3.10+7.8.10}=\frac{7.4.10-7.10.13}{7.3.10+7.8.10}=\frac{7.10.\left(4-13\right)}{7.10.\left(3+8\right)}=\frac{-9}{11}\)
c)\(\frac{-10.21.35}{15.\left(-14\right).\left(-4\right)}=\frac{-2.5.3.7.7.5}{3.5.7.\left(-2\right).\left(-4\right)}=\frac{35}{-4}\)
d)\(\frac{\left(-4\right)^3.27^2.\left(-10\right)^3}{8^3.\left(-9\right)^2.25^2}=\frac{\left(-2^2\right)^3.\left(3^3\right)^2.\left(-2.5\right)^3}{\left(2^3\right)^3.\left[\left(-3\right)^2\right]^2.\left(5^2\right)^2}=\frac{-2^5.3^5.\left(-2\right)^3.5^3}{2^6.\left(-3\right)^4.5^4}=\frac{2^2.3}{5}=\frac{4.3}{5}=\frac{12}{5}\)
a,\(\frac{484}{-860}=\frac{484:\left(-4\right)}{-860:\left(-4\right)}=\frac{-121}{215}\)
b,\(\frac{14.20-70.13}{21.10+7.80}\)\(=\frac{280-910}{210+560}=\frac{-630}{770}=\frac{-9}{11}\)
c,\(\frac{-10.21.35}{15.\left(-14\right).\left(-4\right)}=\frac{1.\left(-3\right).35}{3.2.2}=\frac{105}{12}=8\frac{3}{4}\)
d,tự làm