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15 tháng 12 2020

a, \(20x^2y^3-15xy^2=5xy^2\left(4xy-3\right)\)

b, \(3x+3y-x^2-xy=3\left(x+y\right)-x\left(x+y\right)=\left(3-x\right)\left(x+y\right)\)

c, \(9-x^2-y^2+2xy=9-\left(x^2+y^2-2xy\right)\)

\(=3^2-\left(x-y\right)^2=\left(3-x+y\right)\left(3+x-y\right)\)

15 tháng 12 2020

20x2y3 - 15xy2 = 5xy2( 4xy - 3 )

3x + 3y - x2 - xy = ( 3x + 3y ) - ( x2 + xy ) = 3( x + y ) - x( x + y ) = ( x + y )( 3 - x )

9 - x2 - y2 + 2xy = 9 - ( x2 - 2xy + y2 ) = 32 - ( x - y )2 = ( 3 - x + y )( 3 + x - y )

4 tháng 8 2016

=(3x+3y)-(x^2+2xy+y^2)=3(x+y)-(x+y)^2=k rõ nữa

=(4x^2-4xy) -(6y^2-6xy)= 4x(x-y)+6y(x-y)=2(x-y)(2x+3y)

24 tháng 10 2021

A) x2 -3x+xy-3y=x2+xy-3x-3y=x(x+y)-3(x+y)=(x+y)(x-3)

24 tháng 10 2021

\(x^2-3x+xy-3y\)

\(=\left(x^2+xy\right)-\left(3x+3y\right)\)

\(=x.\left(x+y\right)-3.\left(x+y\right)\)

\(=\left(x-3\right).\left(x+y\right)\)

\(2x^2-x+2xy-y\)

\(=2x^2-\left(x-2xy+y\right)\)

\(=2x^2-\left(x-y\right)^2\)

\(=\left(\sqrt{2}x\right)^2-\left(x-y\right)^2\)

\(=\left(\sqrt{2}x-x+y\right).\left(\sqrt{2}x+x-y\right)\)

\(x^4+x^3+2x^2+x+1\)

\(=\left(x^4+2x^2+1\right)+\left(x^3+x\right)\)

\(=\left(x^2+1\right)^2+x.\left(x^2+1\right)\)

\(=\left(x^2+1\right).\left(x^2+1+x\right)\)

\(16+2xy-x^2-y^2\)

\(=16-x^2+2xy-y^2\)

\(=16-\left(x^2-2xy+y^2\right)\)

\(=4^2-\left(x-y\right)^2\)

\(=[4-\left(x-y\right)].[4+\left(x-y\right)]\)

\(=\left(4-x+y\right).\left(4+x-y\right)\)

23 tháng 10 2016

đề hình như bị sai rồi bạn

23 tháng 10 2016

câu a phải là 3x+3y-x^2-2xy+y^2 chứ

9 tháng 10 2020

a) 36 - 4a2 + 20ab - 25b2 = 36 - ( 4a2 - 20ab + 25b2 ) = 62 - ( 2a - 5b )2 = ( 6 - 2a + 5b )( 6 + 2a - 5b )

b) ( xy + 4 )2 - 4( x + y )= ( xy + 4 )2 - 22( x + y )2 = ( xy + 4 )2 - [ 2( x + y ) ]2 

                                        = ( xy + 4 )2 - ( 2x + 2y )2 = ( xy + 4 - 2x - 2y )( xy + 4 + 2x + 2y )

                                        = [ x( y - 2 ) - 2( y - 2 ) ][ x( y + 2 ) + 2( y + 2 ) ]

                                        = ( y - 2 )( x - 2 )( y + 2 )( x + 2 )

c) x2 + y2 - x2y2 + xy - x - y

= ( x2 - x2y2 ) + ( y2 - y ) + ( xy - x )

= x2( 1 - y2 ) + y( y - 1 ) + x( y - 1 )

= x2( 1 - y )( 1 + y ) - y( 1 - y ) - x( 1 - y )

= ( 1 - y )[ x2( 1 + y ) - y - x ) ]

= ( 1 - y )( x2 + x2y - y - x )

= ( 1 - y )[ ( x2 - x ) + ( x2y - y ) ]

= ( 1 - y )[ x( x - 1 ) + y( x2 - 1 ) ]

= ( 1 - y )[ x( x - 1 ) + y( x - 1 )( x + 1 ) ]

= ( 1 - y )( x - 1 )[ x + y( x + 1 ) ]

= ( 1 - y )( x - 1 )( x + xy + y )

d) 3x + 3y - x2 - 2xy - y2

= 3( x + y ) - ( x2 + 2xy + y2 )

= 3( x + y ) - ( x + y )2

= ( x + y )( 3 - x - y )

e) ( 2xy + 1 )2 - ( 2x + y )2

= ( 2xy + 1 - 2x - y )( 2xy + 1 + 2x + y )

= [ ( 2xy - 2x ) - ( y - 1 ) ][ ( 2xy + 2x ) + ( y + 1 ) ]

= [ 2x( y - 1 ) - ( y - 1 ) ][ 2x( y + 1 ) + ( y + 1 ) ]

= ( y - 1 )( 2x - 1 )( y + 1 )( 2x + 1 )

9 tháng 10 2020

a) \(36-4a^2+20ab-25b^2\)

\(=36-\left(4a^2-20ab+25b^2\right)\)

\(=36-\left(2a-5b\right)^2\)

\(=\left(6-2a+5b\right)\left(6+2a-5b\right)\)

b) \(\left(xy+4\right)^2-4\left(x+y\right)^2\)

\(=\left(xy+4-2x-2y\right)\left(xy+4+2x+2y\right)\)

\(=\left[x\left(y-2\right)-2\left(y-2\right)\right]\left[x\left(y+2\right)+2\left(y+2\right)\right]\)

\(=\left(x+2\right)\left(x-2\right)\left(y+2\right)\left(y-2\right)\)

c) \(x^2+y^2-x^2y^2+xy-x-y\)

\(=-\left(x^2y^2-x^2\right)+\left(y^2-y\right)+\left(xy-x\right)\)

\(=-x^2\left(y-1\right)\left(y+1\right)+y\left(y-1\right)+x\left(y-1\right)\)

\(=\left(y-1\right)\left(-x^2y-x^2+y+x\right)\)

\(=\left(1-y\right)\left[\left(x^2y-y\right)+\left(x^2-x\right)\right]\)

\(=\left(1-y\right)\left(x-1\right)\left(xy+y+x\right)\)

14 tháng 8 2015

a/ \(=3y^2-6y-2x+1\)

b/ \(=-\left(x^3-3x^2+3x-1\right)=-\left(x-1\right)^3\)

c/ \(=\left(2-x\right)^3\)

d/ \(=xy^2+x^2y+3xy+x^2y+x^3+3x^2-3xy-3x^2-9x\)

\(=xy\left(y+x+3\right)+x^2\left(y+x+3\right)-3x\left(y+x+3\right)\)

\(=\left(xy+x^2-3x\right)\left(y+x+3\right)=x\left(y+x-3\right)\left(y+x+3\right)\)

e/ \(=xy-x^2+2x-y^2+xy-2y\)

\(=x\left(y-x+2\right)-y\left(y-x+2\right)=\left(x-y\right)\left(y-x+2\right)\)

14 tháng 8 2015

a) =(2x+3y-1)2

b)=-(x-1)3

c)=-(x3-6x2+12x-8)=-(x-2)3

d)x3 + 2x2y + xy2 – 9x

    = x(x2 + 2xy + y2 -9)

    = x[(x2 + 2xy + y2) - 32]

    = x[(x + y)2 - 32]

    = x (x + y – 3)(x + y + 3)

e) 2x-2y-x2+2xy-y2=2(x-y)-(x-y)2=(x-y)(2-x+y)

24 tháng 7 2016

1)\(=x^2\left(x-y\right)-y\left(x-y\right)\\ =\left(x-y\right)\left(x^2-y\right)\)

2)\(=\left(x^2+x\right)-\left(2xy+2y\right)\\ =x\left(x+1\right)-2y\left(x+1\right)\\ =\left(x+1\right)\left(x-2y\right)\)

3)\(=\left(x^2+2.x.2y+4y^2\right)-y^2\\ =\left(x+2y\right)^2-y^2\\ =\left(x+2y+y\right)\left(x+2y-y\right)\)

24 tháng 7 2016

1) x3 - x2y - xy + y2

= (x- x2y) - (xy - y2)

= x2.(x - y) - y.(x - y)

= (x - y).(x2 - y)

2) x2 - 2xy + x - 2y

= (x2 + x) - (2xy + 2y)

= x.(x + 1) - 2y.(x + 1)

= (x + 1).(x - 2y)

3) x2 + 4xy + 3y2

= x2 + 3xy + xy + 3y2

= (x2 + 3xy) + (xy + 3y2)

= x.(x + 3y) + y.(x + 3y)

= (x + 3y).(x + y)