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x^4-x^3-x^2+2x-2
=(x^4-x^3)-(x^2-2x+2)
=x^3(x-1)-(x-1)^2
=(x^3-x-1)*(x-1)
\(x^5+x^4-x^3+x^2-x+2\)
\(=x^5-x^4+x^3-x^2+x+2x^4-2x^3+2x^2-2x+2\)
\(=x\left(x^4-x^3+x^2-x+1\right)+2\left(x^4-x^3+x^2-x+1\right)\)
\(=\left(x+2\right)\left(x^4-x^3+x^2-x+1\right)\)
\(x^2-\frac{5}{3}x-\frac{2}{3}\)
\(=x^2-2x+\frac{1}{3}x-\frac{2}{3}\)
\(=x\left(x-2\right)+\frac{1}{3}\left(x-2\right)\)
\(=\left(x-2\right)\left(x+\frac{1}{3}\right)\)
\(x^5+x^4-x^3+x^2-x+2\)
\(=x^5+2x^4-x^4+2x^3-x^3+2x^2-x^2+2x-x+2\)
\(=x^4\left(x-2\right)-x^3\left(x-2\right)-x^2\left(x-2\right)-x\left(x-2\right)-\left(x-2\right)\)
\(=\left(x-2\right)\left(x^4-x^3-x^2-x-1\right)\)
x3 -2x2 +x- xy2
= x ( x2 - 2x + 1 - y2)
= x\(\left[\left(x-1\right)^2-y^2\right]\)
= x ( x- 1- y) ( x - 1 + y )
X3-2x2+x-xy2
=(x3+x)-(2x2-xy2)
=x(x2+1)-x(2x-y2)
=x(x2-2x+1-y2)
=x[(x-1)2-y]
=x(x-1-y)(x-1+y)
Chúc bạn làm tốt@"
\(=x\left(x^2-2x+1-y^2\right)\)
\(=x\left[\left(x^2-2x+1\right)-y^2\right]\)
\(=x\left[\left(x-1\right)^2-y^2\right]\)
\(=x\left(x-1+y\right)\left(x-1-y\right)\)
=2 nha
=2 nha