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a) 8x2-2x-1=8x2+4x-2x-2x-1=(8x2+4x)-(2x+1)=4x.(2x+1)-(2x+1)=(2x+1).(4x-1)
b) x2-y2+10x-6y+16x=x2-y2+10x+10y-16y+16x=(x-y)(x+y)+10(x+y)-16(y+x)=(x+y)(x-y+10+16)
a) \(x^2-5x+6=x^2-2x-3x+6=x\left(x-2\right)-3\left(x-2\right)=\left(x-2\right)\left(x-3\right)\)
b) \(x^2+x-12=x^2+4x-3x-12=x.\left(x+4\right)-3.\left(x+4\right)=\left(x+4\right)\left(x-3\right)\)
a) x2 - 3x + 2 = x2 - x - 2x + 2 = x( x - 1 ) - 2( x - 1 ) = ( x - 1 )( x - 2 )
b) 2x2 - x - 6 = 2x2 - 4x + 3x - 6 = 2x( x - 2 ) + 3( x - 2 ) = ( x - 2 )( 2x + 3 )
c) x2 - 5x - 6 = x2 + x - 6x - 6 = x( x + 1 ) - 6( x + 1 ) = ( x + 1 )( x - 6 )
d) x2 + 8x + 7 = x2 + x + 7x + 7 = x( x + 1 ) + 7( x + 1 ) = ( x + 1 )( x + 7 )
e) 3x2 + 2x - 5 = 3x2 - 3x + 5x - 5 = 3x( x - 1 ) + 5( x - 1 ) = ( x - 1 )( 3x + 5 )
f) 4x2 - 3x - 1 = 4x2 - 4x + x - 1 = 4x( x - 1 ) + ( x - 1 ) = ( x - 1 )( 4x + 1 )
a \(x^2-3x+2=x^2-x-2x+2=\left(x-1\right)\left(x-2\right)\)
b, \(2x^2-x-6=2x^2-4x+3x-6=\left(x-2\right)\left(2x+3\right)\)
c, \(x^2-5x-6=x^2+x-6x-6=\left(x+1\right)\left(x-6\right)\)
d, \(x^2+8x+7=x^2+x+7x+7=\left(x+1\right)\left(x+7\right)\)
e, \(3x^2+2x-5=3x^2-3x+5x-5=\left(x-1\right)\left(3x+5\right)\)
f, \(4x^2-3x-1=4x^2-4x+x-1=\left(x-1\right)\left(4x+1\right)\)
a) Ta có : x2 + 7x + 12
= x2 + 3x + 4x + 12
= (x2 + 3x) + (4x + 12)
= x(x + 3) + 4(x + 3)
= (x + 4)(x + 3)
Bạn ơi mk nhầm đề rồi số 30 thay bằng số 60 còn 36 thay bằng 72 và 39 thay bằng 75 nha
\(A=x^2-7xy+12y^2\)
\(A=x^2-3xy-4xy+12y^2\)
\(A=x\left(x-3y\right)-4y\left(x-3y\right)\)
\(A=\left(x-4y\right)\left(x-3y\right)\)
\(B=x^2-3xy-4y^2\)
\(B=x^2+xy-4xy-4y^2\)
\(B=x\left(x+y\right)-4y\left(x+y\right)\)
\(B=\left(x-4y\right)\left(x+y\right)\)
\(A=x^2-7xy+12y^2\)
\(=x^2-3xy-4xy+12y^2\)
\(=x\left(x-3y\right)-4y\left(x-3y\right)\)
\(=\left(x-4y\right)\left(x-3y\right)\)
\(x^2+x-42=x^2+7x-6x-42=x\left(x+7\right)-6\left(x+7\right)=\left(x-6\right)\left(x+7\right)\)
ONline math chọn em đi
a) 8x2 - 2x - 1
=8x2+2x-4x-1
=2x.(4x+1)-(4x+1)
=(4x+1)(2x-1)
b) x2 - y2 + 10x - 6y + 16
=x2+10x+25-y2-6y-9
=(x+5)2-(y+3)2
=(x+5-y-3)(x+5+y+3)
=(x-y+2)(x+y+8)