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a/ -8x2 - 12xy3 - 4xy2 = -4x (2x + 3y3 + y2)
b/ (x - y)3 - x3 + y3 = x3 - 3x2y + 3xy2 - y3 - x3 + y3 = -3x2y + 3xy2 = -3xy (x - y)
c/ 3x(x - y) - 2y(x - y) = (x - y) (3x - 2y)
d/ a(x + 2) - 2b(x + 2) + (x + 2) = (x + 2) (a - 2b +1)
e/ 5x(x - y) - (y - x) = 5x(x - y) + (x - y) = (x - y) (5x + 1)
a. 2x-1-x2= -(x2-2x+1)=-(x-1)2
b. 8x3+y6=(2x)3+(y2)3
=(2x+y2)(4x2-2xy2+y4)
c. x2-16+4xy+4y2=(x2+4xy+4y2)-16
=(x+2y)2-16=(x+2y+4)(x+2y-4)
a) x2 + 6x + 9 = x2 + 2 . x . 3 + 32 = (x + 3)2
b) 10x – 25 – x2 = -(-10x + 25 +x2) = -(25 – 10x + x2)
= -(52 – 2 . 5 . x – x2) = -(5 – x)2
c) 8x3 - 1/8 = (2x)3 – (1/2)3 = (2x - 1/2)[(2x)2 + 2x . 12 + (1/2)2]
= (2x - 1/2)(4x2 + x + 1/4)
d)1/25x2 – 64y2 = (1/5x)2(1/5x)2- (8y)2 = (1/5x + 8y)(1/5x - 8y)
a) 8x2 + 4xy - 2ax - ay = (8x2 + 4xy) - (2ax + ay) = 4x(2x + y) - a(2x + y) = (4x - a)(2x + y)
b) 2xy - x2 - y2 = 16 - (-2xy + x2 + y2) = 42 - (x - y)2 = (4 - x + y)(4 + x - y)
c) x2 - y2 - 2yz - z2 = x2 - (y2 + 2yz + z2) = z2 - (y + z)2 = (z - y - z)(z + y + z)
Phân tích đa thức thành nhân tử :
8x3 - 8x2y + 2xy2
= 8x3 - 4x2y - 4x2y + 2xy2
= 4x2( x - y ) - 2xy ( x - y )
= ( x - y)(4x2 - 2xy)
= 2x(x - y)(2x - y)
a) \(8x^2-12xy+4y^2-2x-1\)
\(=4y^2-8xy-2y-4xy+8x^2+2x+2y-4x-1\)
\(=\left(4y^2-8xy-2y\right)-\left(4xy-8x^2-2x\right)+\left(2y-4x-1\right)\)
\(=2y\left(2y-4x-1\right)-2x\left(2y-4x-1\right)+\left(2y-4x-1\right)\)
\(=\left(2y-2x+1\right)\left(2y-4x-1\right)\)
b) \(4x^4+16\)
\(=4x^4+16x^2+16-16x^2\)
\(=\left(2x^2+4\right)^2-\left(4x\right)^2\)
\(=\left(2x^2+4x+4\right)\left(2x^2-4x+4\right)\)
\(=4\left(x^2+2x+2\right)\left(x^2-2x+2\right)\)
\(=-4xy^2\left(2x+3y+1\right).\)
\(-8x^2y^2-12xy^3-4xy^2\)
\(=-8x^2y^2-8xy^3-4xy^3-4xy\)
\(=-8xy\left(xy-y^2\right)-4xy\left(y^2-1\right)\)
\(=-8xy\left(y\left(x-y\right)\right)-4xy\left(y-1\right)\left(y+1\right)\)
\(=-4.2xy\left(y\left(x-y\right)\right)-4xy\left(y-1\right)\left(y+1\right)\)
\(=-4\left(2xy\left(y\left(x-y\right)\right)-xy\left(y-1\right)\left(y+1\right)\right)\)
Vậy thôi thành nhân tử là dc rồi
Ủng hộ nha
Thanks