Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.
x4+2015x2+2014x+2015
=x4-x+2015x2+2015x+2015
=x.(x3-1)+2015.(x2+x+1)
=x.(x-1)(x2+x+1)+2015.(x2+x+1)
=(x2+x+1)(x2-x+2015)
\(x^4+2015x^2+2014x+2015=\left(x^4+x^3+x^2\right)-\left(x^3+x^2+x\right)+\left(2015x^2+2015x+2015\right)\)
\(=x^2\left(x^2+x+1\right)-x\left(x^2+x+1\right)+2015\left(x^2+x+1\right)=\left(x^2+x+1\right)\left(x^2-x+2015\right)\)
trả lời
xx^4+2015x^2+2014x+2015=x^4+2015x^2+2015x-x+2015=x\left(x^3-1\right)+2015\left(X^2+x+1\right)=x\left(x-1\right)\left(x^2+x+1\right)+2015\left(x^2+x+1\right)=\left(x^2+x+1\right)\left(x^2-x+2015\right)xx4+2015x2+2014x+2015=x4+2015x2+2015x−x+2015=x(x3−1)+2015(X2+x+1)=x(x−1)(x2+x+1)+2015(x2+x+1)=(x2+x+1)(x2−x+2015)
hc tốt
\(x^4+2015x^2+2014x+2015\)
\(=\left(x^4-x\right)+2015x^2+2015x+2015\)
\(=x\left(x^3-1\right)+2015\left(x^2+x+1\right)\)
\(=x\left(x-1\right)\left(x^2+x+1\right)+2015\left(x^2+x+1\right)\)
\(=\left(x^2+x+1\right)\left(x^2-x+2015\right)\)
ta có:
x^4+2014x^2+2013x+2014 = x^4+2013x^2+x^2+2013x+2013+1
=(x^4+x^2+1)+2013(x^2+x+1)
=(x^2+1)^2-x^2+2013(x^2+x+1)
=(x^2-x+1)(x^2+x+1)+2013(x^2+x+1)
=(x^2+x+1)(x^2+x+2014)
x4+2014x2+2013x+2014=(x4-x)+(2014x2+2014x+2014)
=x(x-1)(x2+x+1)+2014(x2+x+1)
=(x^2+x+1)(x2-x+2014)
x^4+2014x^2+2013x+2014 = x^4+2013x^2+x^2+2013x+2013+1
=(x^4+x^2+1)+2013(x^2+x+1)
=(x^2+1)^2-x^2+2013(x^2+x+1)
=(x^2-x+1)(x^2+x+1)+2013(x^2+x+1)
=(x^2+x+1)(x^2+x+2014)
9x2-2015x+2006
= 9x2-9x-2006x+2006
= (9x2-9x)-(2006x-2006)
= 9x(x-1)-2006(x-1)
= (x-1) (9x-2006)
Chúc học tốt nhé!
\(a^3-3a+3b-b^3=\left(a^3-b^3\right)-3\left(a-b\right)=\left(a-b\right)\left(a^2+b^2+ab-3\right)\)
\(x^2-2014x+2013=x^2-2013x-x+2013=x\left(x-2013\right)-\left(x-2013\right)=\left(x-2013\right)\left(x-1\right)\)
a3 - 3a + 3b - b3
= ( a3 - b3 ) - ( 3a - 3b )
= ( a - b )( a2 + ab + b2 ) - 3( a - b )
= ( a - b )( a2 + ab + b2 - 3 )
x2 - 2014x + 2013
= x2 - 2013x - x + 2013
= x( x - 2013 ) - ( x - 2013 )
= ( x - 2013 )( x - 1 )
\(x^4+2015x^2+2014x+2015\)
\(=\left(x^4-x^3+2015x^2\right)+\left(x^3-x^2+2015x\right)+\left(x^2-x+2015\right)\)
\(=\left(x^2-x+2015\right)\left(x^2+x+1\right)\)