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a) x2 + 6x + 9 = x2 + 2 . x . 3 + 32 = (x + 3)2
b) 10x – 25 – x2 = -(-10x + 25 +x2) = -(25 – 10x + x2)
= -(52 – 2 . 5 . x – x2) = -(5 – x)2
c) 8x3 - 1/8 = (2x)3 – (1/2)3 = (2x - 1/2)[(2x)2 + 2x . 12 + (1/2)2]
= (2x - 1/2)(4x2 + x + 1/4)
d)1/25x2 – 64y2 = (1/5x)2(1/5x)2- (8y)2 = (1/5x + 8y)(1/5x - 8y)
a.\(3x^2-11x+6\)
= \(3x^2-9x-2x+6\)
=\(3x\left(x-3\right)-2\left(x-3\right)\)
=\(\left(x-3\right)\left(3x-2\right)\)
b\(8x^2+10x-3\)
=.\(8x^2-2x+12x-3\)
=\(2x\left(4x-1\right)+3\left(4x-1\right)\)
=\(\left(4x-1\right)\left(2x+3\right)\)
d.\(x^2-y^2+10x-6y+16\)
=\(\left(x^2+10x+25\right)-\left(y^2+6y+9\right)\)
=\(\left(x+5\right)^2-\left(y+3\right)^2\)
=\(\left(x+5-y-3\right)\left(x+5+y+3\right)\)
=\(\left(x-y+2\right)\left(x+y+8\right)\)
e.\(x^4+x^2y^2+y^4\)
=\(x^4+2x^2y^2+y^4-x^2+y^2\)
=\(\left(x^2+y^2\right)^2-x^2y^2\)
=\(\left(x^2+y^2-xy\right)\left(x^2+y^2+xy\right)\)
a)
\(=3x^2-9x-2x+6=3x\left(x-3\right)-2\left(x-3\right)=\left(x-3\right)\left(3x-2\right)\)
1,\(=x^3-2x^2+x^2-2x-6x+12=x^2\left(x-2\right)+x\left(x-2\right)-6\left(x-2\right)\)
\(=\left(x-2\right)\left(x^2-2x+3x-6\right)=\left(x-2\right)^2\left(x+3\right)\)
2,\(=x^3-5x^2-4x^2+20x-5x+25=x^2\left(x-5\right)-4x\left(x-5\right)-5\left(x-5\right)\)
\(=\left(x-5\right)\left(x^2+x-5x-5\right)=\left(x-5\right)^2\left(x+1\right)\)
a/ \(=x^4+2x^3+2x^2+\left(x^3+2x^2+2x\right)-\left(5x^2+10x+10\right)\)
\(=x^2\left(x^2+2x+2\right)+x\left(x^2+2x+2\right)-5\left(x^2+2x+2\right)\)
\(=\left(x^2+x-5\right)\left(x^2+2x+2\right)\)
b/ \(=3x^4+x^3-x^2+\left(9x^3+3x^2-3x\right)-\left(18x^2+6x-6\right)\)
\(=x^2\left(3x^2+x-1\right)+3x\left(3x^2+x-1\right)-6\left(3x^2+x-1\right)\)
\(=\left(x^2+3x-6\right)\left(3x^2+x-1\right)\)
c/ Bạn xem lại đề, câu này ko phân tích được