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\(3x^2-3y^2-2\left(x-y\right)^2\)
\(=3x^2-3y^2-2\left(x^2-2xy+y^2\right)\)
\(=3x^2-3y^2-2x^2+4xy-2y^2\)
\(=x^2+4xy-5y^2\)
\(=x^2+4xy+4y^2-9y^2\)
\(=\left(x+2y\right)^2-\left(3y\right)^2\)
\(=\left(x+2y-3y\right)\left(x+2y+3y\right)\)
\(=\left(x-y\right)\left(x+5y\right)\)
x2+4xy+2x+3y2+6y
=(x2+xy+2x)+(3xy+3y2+6y)
=x(x+y+2)+3y(x+y+2)
=(x+y+2)(x+3y)
3*(\(4x^2-4xy+y^2\))-10(2x-y)+8
3*(2x-y)^2-10(2x-y)+8
3*(2x-y)^2-6(2x-y)-4(2x-y)+8
3(2x-y)(2x-y-2)-4(2x-y-2)
(2x-y-2)(6x-3y-40
\(\left(12x^2-12xy+3y^2\right)-10\left(2x-y\right)+8\)
\(=\left(12x^2-6xy-6xy+3y^2\right)-10\left(2x-y\right)+8\)
\(=\left[6x\left(2x-y\right)-3y\left(2x-y\right)\right]-10\left(2x-y\right)+8\)
\(=\left(2x-y\right)\left(6x-3y\right)-10\left(2x-y\right)+8\)
\(=3\left(2x-y\right)^2-10\left(2x-y\right)+8\)
Đặt \(2x-y=a\), khi đó biểu thức có dạng:
\(3a^2-10a+8=3a^2-6a-4a+8\)
\(=3a\left(a-2\right)-4\left(a-2\right)=\left(a-2\right)\left(3a-4\right)\)
\(=\left(2x-y-2\right)\left(6x-3y-4\right).\)
\(x^2+3x+2\)
\(=x^2+x+2x+2\)
\(=x\left(x+1\right)+2\left(x+1\right)\)
\(=\left(x+1\right)\left(x+2\right)\)
Ta có:\(x^2-4\)
\(=x^2-2^2\)
\(=\left(x-2\right)\left(x+2\right)\)
\(x^2-4\)
\(=x^2-2^2\)
\(=\left(x-2\right)\left(x+2\right)\)
\(x^2+7x+6\)
\(=x^2+x+6x+6\)
\(=x\left(x+1\right)+6\left(x+1\right)\)
\(=\left(x+1\right).\left(x+6\right)\)
\(x^2-y^2+3x-3y\)
\(=\left(x^2-y^2\right)+\left(3x-3y\right)\)
\(=\left(x-y\right)\left(x+y\right)+3.\left(x-y\right)\)
\(=\left(x-y\right)\left(x+y+3\right)\)
\(x^2-y^2+4x+4\)
\(=\left(x^2+2.2x+2^2\right)-y^2\)
\(=\left(x+2\right)^2-y^2\)
\(=\left(x+2-y\right)\left(x+2+y\right)\)
Tham khảo nhé~
y2 + 3y + 2
= y2 + y + 2y + 2
= (y2 + y) + (2y + 2)
= y(y + 1) + 2(y + 1)
= (y + 1) (y + 2)
t i c k nha!! 64564645645676576876879798707896473762463464576576876689
\(y^2+y+2y+2\)
\(=y\left(y+1\right)+2\left(y+1\right)\)
\(=\left(y+1\right)\left(y+2\right)\)