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\(=x\left(\frac{x^2}{4}+x+1\right)=x\left(\frac{x}{2}+1\right)^2\)
\(x^2+7x+6\)
\(=x^2+x+6x+6\)
\(=x\left(x+1\right)+6\left(x+1\right)\)
\(=\left(x+1\right).\left(x+6\right)\)
\(x^2+3x+2\)
\(=x^2+x+2x+2\)
\(=x\left(x+1\right)+2\left(x+1\right)\)
\(=\left(x+1\right)\left(x+2\right)\)
\(x^2+2x+1\)
\(=x^2+2.x.1+1^2\)
\(=\left(x+1\right)^2\)
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x2 - 3x + 2
= x2 - x - 2x + 2
= x.(x - 1) - 2.(x - 1)
= (x - 1).(x - 2)
Ủng hộ mk nha ^-^
\(x^2-3x+2\)
\(=x^2-x-2x+2\)
\(=x\left(x-1\right)-2\left(x-1\right)\)
\(=\left(x-1\right)\left(x-2\right)\)
y2 + 3y + 2
= y2 + y + 2y + 2
= (y2 + y) + (2y + 2)
= y(y + 1) + 2(y + 1)
= (y + 1) (y + 2)
t i c k nha!! 64564645645676576876879798707896473762463464576576876689
\(y^2+y+2y+2\)
\(=y\left(y+1\right)+2\left(y+1\right)\)
\(=\left(y+1\right)\left(y+2\right)\)
đa thức <=> x4-x+2017x^2+2017x+2017=x(x^3-1)+2017(x^2+x+1)=x(x-1)(x^2+x+1)+2017(x^2+x+1)=(x^2+x+1)(x^2-x+2017)
Ta có:\(x^2-4\)
\(=x^2-2^2\)
\(=\left(x-2\right)\left(x+2\right)\)
\(x^2-4\)
\(=x^2-2^2\)
\(=\left(x-2\right)\left(x+2\right)\)