K
Khách

Hãy nhập câu hỏi của bạn vào đây, nếu là tài khoản VIP, bạn sẽ được ưu tiên trả lời.

29 tháng 7 2018

a) ax - 2x - a2 + 2a

= ( ax - 2x ) - ( a2 - 2a )

= x ( a - 2 ) - a ( a - 2 )

= ( a - 2 ) ( x - a )

b) x2 + x - ax - a

= ( x2 + x ) - ( ax + a )

= x ( x + 1 ) - a ( x + 1 )

= ( x + 1 ) ( x - a )

Hok Tốt!!!

29 tháng 7 2018

a) ax -2x- a2+ 2a

= (ax -2x ) -(a2 -2a )

= x(a-2) -a ( a-2 )

= (x-a) (a-2)

b) x2 +x -ax -a

=( x2 +x ) - ( ax +a )

= x( x+1 ) -a ( x+1 )

= ( x-a ) (x+ 1)

c) 2x2 +4ax +x +2a

=( 2x2 + 4ax )  + ( x+ 2a )

= 2x ( x+ 2a ) + ( x+2a )

= ( 2x +1 ) (x+2a )

d) 2xy -ax +x2 - 2ay

= (2xy -2ay ) + (  -ax + x2 )

= 2y( x-a ) + x ( x-a)

= ( 2y +x ) ( x -a )

13 tháng 8 2018

\(x\cdot\left(a-2\right)-a\left(a-2\right)\)

\(\left(x-a\right)\cdot\left(a-2\right)\)

b ,\(x\left(x+1\right)-a\left(x+1\right)\)

\(\left(x-a\right)\cdot\left(x+1\right)\)

c ,\(2x\left(x+2a\right)+x+2a\)

(2x+1)(x+2a)

d, 2xy+x^2-ax-2ay

x(2y+x)-a(x+2y)

(x-a)(x+2y)

e, x^2(x+a)+x+a

(x^2+1)(x+a)

f, y^2(y+x^2)+z(x^2+y)

(y^2+z)(y+x^2)

29 tháng 7 2018

d) ax+ ay - bx2 - by

= ( ax2 + ay ) - ( bx2 + by )

= a ( x2 + y ) - b ( x2 + y )

=  ( x2 + y )( a - b )

29 tháng 7 2018

c) x2y + xy2 - x - y

= ( x2y + xy2 ) - ( x + y )

= xy ( x + y ) - ( x+ y )

= ( x + y ) ( xy - 1 )

6 tháng 8 2020

a/ \(ax-2x-a^2+2a\)

\(=x\left(a-2\right)-a\left(a-2\right)\)

\(=\left(x-a\right)\left(a-2\right)\)

Vậy....

b/ \(x^2+x-ax-a\)

\(=x\left(x+1\right)-a\left(x+1\right)\)

\(=\left(x+1\right)\left(x-a\right)\)

Vậy...

d/ \(2xy-ax+x^2-2ay\)

\(=2y\left(x-a\right)+x\left(x-a\right)\)

\(=\left(x-a\right)\left(2y+x\right)\)

e/ \(x^3+ax^2+x+a\)

\(=x^2\left(x+a\right)+\left(x+a\right)\)

\(=\left(x^2+1\right)\left(x+a\right)\)

Vậy...

17 tháng 7 2019

\(a,xy+1-x-y\)

\(=\left(xy-y\right)+\left(1-x\right)\)

\(=y\left(x-1\right)- \left(x-1\right)\)

\(=\left(x-1\right)\left(y-1\right)\)

\(b,ax+ay-3x-3y\)

\(=a\left(x+y\right)-3\left(x+y\right)\)

\(=\left(x+y\right)\left(a-3\right)\)

\(c,x^3-2x^2+2x-4\)

\(=x^2\left(x-2\right)+2\left(x-2\right)\)

\(=\left(x^2+2\right)\left(x-2\right)\)

\(d,x^2+ab+ax+bx\)

\(=\left(x^2+ax\right)+\left(ab+bx\right)\)

\(=x\left(a+x\right)+b\left(a+x\right)\)

\(=\left(a+x\right)\left(b+x\right)\)

\(e,16-x^2+2xy-y^2\)

\(=4^2-\left(x^2-2xy+y^2\right)\)

\(=4^2-\left(x-y\right)^2\)

\(=\left(4-x+y\right)\left(4+x-y\right)\)

17 tháng 7 2019

\(f,ax^2+ax-bx^2-bx-a+b\)

\(=\left(ax^2-bx^2\right)+\left(ax-bx\right)-\left(a-b\right)\)

\(=x^2\left(a-b\right)+x\left(a-b\right)-\left(a-b\right)\)

\(=\left(a-b\right)\left(x^2+x-1\right)\)

16 tháng 7 2017

a) \(x^2+2x-4y^2-4y=\left(x^2-4y^2\right)+\left(2x-4y\right)=\left(x+2y\right)\left(x-2y\right)+2\left(x-2y\right)\)

\(=\left(x-2y\right).\left(x+2y+2\right)\)

b)  \(x^4-6x^3+54x-81=\left(x^4-81\right)-\left(6x^3-54x\right)=\left(x^2-9\right)\left(x^2+9\right)-6x.\left(x^2-9\right)\)

\(=\left(x^2-9\right).\left(x^2+9-6x\right)=\left(x+3\right).\left(x-3\right).\left(x-3\right)^2=\left(x+3\right).\left(x-3\right)^3\)

c)  \(ax^2+ax-bx^2-bx-a+b=\left(ax^2-bx^2\right)+\left(ax-bx\right)-\left(a-b\right)\)

\(=x^2.\left(a-b\right)+x.\left(a-b\right)-\left(a-b\right)=\left(a-b\right).\left(x^2+x-1\right)\)

d)  \(\left(x^2+y^2-2\right)^2-\left(2xy-2\right)^2=\left(x^2+y^2-2+2xy-2\right).\left(x^2+y^2-2-2xy+2\right)\)

\(=\left(x^2+2xy+y^2-4\right).\left(x^2+y^2-2xy\right)=\left[\left(x+y\right)^2-4\right].\left(x-y\right)^2\)

\(=\left(x+y+2\right).\left(x+y-2\right).\left(x-y\right)^2\)

15 tháng 10 2017

a) ko bt làm

1 tháng 7 2018

a) \(x^3-2x^2+2x-1^3\)

\(=x\left(x^2-2x+1\right)+x-1\)

\(=x\left(x-1\right)+\left(x-1\right)\)

\(=\left(x+1\right)\left(x-1\right)\)

b) \(x^2y+xy+x+1\)

\(=xy\left(x+1\right)+\left(x+1\right)\)

\(=\left(xy+1\right)\left(x+1\right)\)

c) \(ax+by+ay+bx\)

\(=a\left(x+y\right)+b\left(x+y\right)\)

\(=\left(a+b\right)\left(x+y\right)\)

d) \(x^2-\left(a+b\right)x+ab\)

\(=x^2-ax-bx+ab\)

\(=\left(x^2-ax\right)-\left(bx-ab\right)\)

\(=x\left(x-a\right)-b\left(x-a\right)\)

\(=\left(x-b\right)\left(x-a\right)\)

e) Ko biết làm

f) \(ax^2+ay-bx^2-by\)

\(=\left(ax^2+ay\right)-\left(bx^2+by\right)\)

\(=a\left(x^2+y\right)-b\left(x^2+y\right)\)

\(=\left(a-b\right)\left(x^2+y\right)\)

1 tháng 7 2018

a, x3 - 2x2 + 2x - 13

= x3 - 2x2 . 1+ 2x.12 - 13

= (x - 3 )3

12 tháng 10 2018

\(a,ax+by+ay+bx=\left(ax+ay\right)+\left(by+bx\right)=a\left(x+y\right)+b\left(x+y\right)=\left(a+b\right)\left(x+y\right)\)

\(b,x^2y+xy+x+1=xy\left(x+1\right)+\left(x+1\right)=\left(xy+1\right)\left(x+1\right)\)

\(c,x^2-ax-bx+ab=x\left(x-a\right)-b\left(x-a\right)=\left(x-b\right)\left(x-2\right)\)

\(d,x^2y+xy^2-x-y=xy\left(x+y\right)-\left(x+y\right)=\left(xy-1\right)\left(x+y\right)\)

12 tháng 10 2018

\(e,a\left(x^2+y\right)-b\left(x^2+y\right)=\left(a-b\right)\left(x^2+y\right)\)

\(f,x\left(a-2\right)-a\left(a-2\right)=\left(x-a\right)\left(a-2\right)\)