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a, x4 - 5x2 + 4
= x4 - 4x2 - x2 + 4
= x2 . (x2 - 4) - (x2 - 4)
= (x2 - 4) . (x2 - 1)
= (x - 2) . (x + 2) . (x - 1) . (x + 1)
a)x4-5x2+4=x4-x2-4x2+4
=(x4-x2)-(4x2-4)
=x2(x2-1)-4(x2-1)
=(x2-1)(x2-4)
PHÂN TÍCH ĐA THỨC THÀNH NHÂN TỬ ? (x+y)^4+x^4+y^4? | Yahoo Hỏi & Đáp
x6+3x4y2-8x3y3+3x2y4+y6= x6+3x4y2+3x2y4+y6-8x3y3=(x2+y2)3-(2xy)3
= (x2+y2-2xy)[(x2+y2)2+2xy(x2+y2)+(2xy)2]= (x-y)2(x4+6x2y2+y4+2x3y+2xy3)
(x2+y2-5)2-4x2y2-16xy-16=(x2+y2-5)2-(4x2y2+16xy+16)=(x2+y2-5)2-(2xy+4)2
=(x2+y2-5+2xy+4)(x2+y2-5-2xy-4)=(x2+2xy+y2-1)(x2-2xy+y2-9)=[(x+y)2-1][(x-y)2-32]=(x+y-1)(x+y+1)(x-y-3)(x-y+3)
x4+324=x4+36x2+324-36x2=(x2+18)2-(6x)2=(x2+18-6x)(x2+18+6x)
\(\left(x-y\right)\left(z-x\right)\left(z-y\right)\left(z^2+yz+xz+y^2+xy+x^2\right)\)vay ms dung
\(x^4+3x^2y^2+4y^4\)
\(x^4+4y^4-2xy^3+2xy^3+2x^2y^2+2x^2y^2-x^2y^2\)
\(+x^3y-x^3y\)
\(=\left(4y^4-2xy^3+2x^2y^2\right)+\left(2xy^3-x^2y^2+x^3y\right)\)
\(+\left(2x^2y^2-x^3y+x^4\right)\)
\(=2y^2\left(2y^2-xy+x^2\right)+xy\left(2y^2-xy+x^2\right)\)
\(+x^2\left(2y^2-xy+x^2\right)\)
\(=\left(2y^2+xy+x^2\right)\left(2y^2-xy+x^2\right)\)
Ta có \(x^4+y^4+\left(x+y\right)^4=\left(x^2+y^2\right)^2-2x^2.y^2+\left(x+y\right)^4\)
\(=\left[\left(x+y\right)^2-2xy\right]^2-2x^2.y^2+\left(x+y\right)^4\)\(=\left(x+y\right)^4-4xy\left(x+y\right)^2+4x^2y^2-2x^2y^2+\left(x+y\right)^4\)
\(=2\left(x+y\right)^4-4xy\left(x+y\right)^2+2x^2y^2\)\(=2\left[\left(x+y\right)^4-2.xy.\left(x+y\right)^2+\left(xy\right)^2\right]\)
\(=2\left[\left(x+y\right)^2-xy\right]^2\)