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4 tháng 2 2022
b: \(=x\left(x^4-y^4\right)+y\left(x^4-y^4\right)\)
\(=\left(x+y\right)\left(x^4-y^4\right)\)
\(=\left(x+y\right)\left(x^2-y^2\right)\left(x^2+y^2\right)\)
\(=\left(x^2+y^2\right)\left(x+y\right)^2\cdot\left(x-y\right)\)
18 tháng 8 2020
a)
\(=x^2\left(2x+3\right)+\left(2x+3\right)\)
\(=\left(x^2+1\right)\left(2x+3\right)\)
b)
\(=a\left(a-b\right)+a-b\)
\(=\left(a+1\right)\left(a-b\right)\)
c)
\(=2\left(x^2+2x+1-y^2\right)\)
\(=2\left(x+1-y\right)\left(x+1+y\right)\)
d)
\(=x^3\left(x-2\right)+10x\left(x-2\right)\)
\(=x\left(x^2+10\right)\left(x-2\right)\)
e)
\(=x\left(x^2+2x+1\right)\)
\(=x\left(x+1\right)^2\)
f)
\(=y\left(x+y\right)-\left(x+y\right)\)
\(=\left(y-1\right)\left(x+y\right)\)
F
18 tháng 8 2020
a,2x3+3x2+2x+3
=(2x3+2x)+(3x2+3)
=2x(x2+1)+3(x2+1)
=(x2+1)(2x+3)
b,a2-ab+a-b
=(a2-ab)+(a-b)
=a(a-b)+(a-b)
=(a-b)(a+1)
c,2x2+4x+2-2y2
=2(x2+2x+1-y2)
=2[(x2+2x+1)-y2 ]
=2[(x+1)2-y2 ]
=2(x+1-y)(x+1+y)
d,x4-2x3+10x2-20x
=(x4-2x3)+(10x2-20x)
=x3(x-2)+10x(x-2)
=(x-2)(x3+10x)
=(x-2)[x(x2+10)]
e,x3+2x2+x
=x(x2+2x+1)
=x(x+1)2
f,xy+y2-x-y
=(xy+y2)-(x-y)
=y(x+y)-(x+y)
=(x+y)(y-1)
1 tháng 9 2020
3x( y + 2 ) - 3( 1 - 2x ) ( như này đúng k -..- )
= 3( xy + 2x ) - 3( 1 - 2x )
= 3[ xy + 2x - ( 1 - 2x ) ]
= 3( xy + 2x - 1 + 2x )
= 3( xy + 4x - 1 )
x2 - y2 - 2x + 2y
= ( x2 - y2 ) - 2( x - y )
= ( x - y )( x + y ) - 2( x - y )
= ( x - y )( x + y - 2 )
2x + 2y - x2 - xy
= 2( x + y ) - x( x + y )
= ( x + y )( 2 - x )
TN
15 tháng 8 2016
x^2 + 3xy+2y^2 = x^2 +2xy+y^2+xy+y^2=(x+y)^2 + y(x+y)=(x+y)(x+2y)
HD
7
20 tháng 7 2016
c) = \(x^4+4x^2+4-x^2-2x-1\)
= \(\left(x^2+2\right)^2-\left(x+1\right)^2\)
= \(\left(x^2+x+3\right)\left(x^2-x+1\right)\)
Chúc bạn làm bài tốt
9 tháng 12 2018
a) \(2x\left(x-3\right)^2+5x\left(3-x\right)\)
\(=2x\left(x-3\right)^2-5x\left(x-3\right)\)
\(=\left(x-3\right)\left[2x\left(x-3\right)-5x\right]\)
\(=\left(x-3\right)\left(2x^2-6x-5x\right)\)
\(=\left(x-3\right)\left(2x^2-11x\right)\)
\(=x\left(x-3\right)\left(2x-11\right)\)
b) \(\left(x+3\right)^2-4\left(y^2-2y+1\right)\)
\(=\left(x+3\right)^2-2^2\left(y-1\right)^2\)
\(=\left(x+3\right)^2-\left[2\left(y-1\right)\right]^2\)
\(=\left[\left(x+3\right)-2\left(y-1\right)\right]\left[\left(x+3\right)+2\left(y-1\right)\right]\)
\(=\left(x+3-2y+2\right)\left(x+3+2y-2\right)\)
\(=\left(x-2y+5\right)\left(x+2y+1\right)\)
N
9 tháng 12 2018
a) \(2x.\left(x-3\right)^2+5x.\left(-x+3\right)=2x.\left(x-3\right)^2-5x.\left(x-3\right)\)
\(=\left(x-3\right).\left(2x^2-11x\right)=\left(x-3\right).x.\left(2x-11\right)\)
b) \(\left(x+3\right)^2-4.\left(y^2-2y+1\right)=\left(x+3\right)^2-2^2.\left(y-1\right)^2\)
\(=\left(x+3\right)^2-\left[2.\left(y-1\right)\right]^2=\left(x-2y+1\right).\left(x+2y+5\right)\)
11 tháng 10 2020
a) \(4x^3y-12x^2y^3-8x^4y^3\)
\(=4x^2y\left(x-3y^2-2x^2y^2\right)\)
b) \(2x^2+4x+2-2y^2\)
\(=2\left(x^2+2x+1-y^2\right)\)
\(=2\left[\left(x+1\right)^2-y^2\right]\)
\(=2\left(x-y+1\right)\left(x+y+1\right)\)
c) \(x^3-2x^2+x-xy^2\)
\(=x\left(x^2-2x+1-y^2\right)\)
\(=x\left[\left(x-1\right)^2-y^2\right]\)
\(=x\left(x-y-1\right)\left(x+y-1\right)\)
d) \(x\left(x-2y\right)+3\left(2y-x\right)\)
\(=x\left(x-2y\right)-3\left(x-2y\right)\)
\(=\left(x-3\right)\left(x-2y\right)\)
e) \(x^2+4\)
\(=\left(x^4+4x^2+4\right)-4x^2\)
\(=\left(x^2+2\right)^2-\left(2x\right)^2\)
\(=\left(x^2-2x+2\right)\left(x^2+2x+2\right)\)
f) \(5x^2-7x-6\)
\(=\left(5x^2-10x\right)+\left(3x-6\right)\)
\(=5x\left(x-2\right)+3\left(x-2\right)\)
\(=\left(5x+3\right)\left(x-2\right)\)
vô tkhđ xem hình nhé ( nguồn : mạng )
2x4-x3y+3x2y2-xy3+2y4=2x4-2x3y+x3y+2x2y2+2x2y2-x2y2+xy3-2xy3+2y4
=(2x4-2x3y+2x2y2)+(x3y+x2y2+xy3)+(2x2y2-2xy3+2y4)
=2x2(x2-xy+y2)+xy(x2-xy+y2)+2y2(x2-xy+y2)
=(x2-xy+y2)(2x2+xy+2y2)
vậy 2x4-x3y+3x2y2-xy3+2y4=(x2-xy+y2)(2x2+xy+2y2)