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Bài làm
a) 6x3 + x2yy + 23xy2 + 12y3
= ( 2x + y ) ( 3x2 - xy + 12y2 )
# Học tốt #
\(\text{a) }x^8+x^6+x^4+x^2\)
\(=\left(x^8+x^6\right)+\left(x^4+x^2\right)\)
\(=x^6\left(x^2+1\right)+x^2\left(x^2+1\right)\)
\(=\left(x^2+1\right)\left(x^6+x^2\right)\)
\(=x^2\left(x^2+1\right)\left(x^3+1\right)\)
\(=x^2\left(x^2+1\right)\left(x+1\right)\left(x^2-x+1\right)\)
Bạn phát ơi bạn làm lại đc ko mk ghi thiếu đề
X8+X6+X4+X2+1
b: \(=\left(x^4-x^3+x^2-x+1\right)\left(x^4+x^3+x^2+x+1\right)\)
a: \(=x^4-5x^3+5x^3-25x^2-5x^2+25x+6x-30\)
\(=\left(x-5\right)\left(x^3+5x^2-5x+6\right)\)
\(=\left(x-5\right)\left(x^3+6x^2-x^2-6x+x+6\right)\)
\(=\left(x-5\right)\left(x+6\right)\left(x^2-x+1\right)\)
a) x2 + 6x + 9 = x2 + 2 . x . 3 + 32 = (x + 3)2
b) 10x – 25 – x2 = -(-10x + 25 +x2) = -(25 – 10x + x2)
= -(52 – 2 . 5 . x – x2) = -(5 – x)2
c) 8x3 - 1/8 = (2x)3 – (1/2)3 = (2x - 1/2)[(2x)2 + 2x . 12 + (1/2)2]
= (2x - 1/2)(4x2 + x + 1/4)
d)1/25x2 – 64y2 = (1/5x)2(1/5x)2- (8y)2 = (1/5x + 8y)(1/5x - 8y)
a) \(x^2-x-2=x^2+x-2x-2=x\left(x+1\right)-2\left(x+1\right)\)
\(=\left(x+1\right)\left(x-2\right)\)
a) \(x^2-x-2=x^2-2x+x-2=x\left(x-2\right)+\left(x-2\right)=\left(x-2\right)\left(x+1\right)\)
b) \(x^3-19x-30==x^3+2x^2-2x^2-4x-15x-30=x^2\left(x+2\right)-2x\left(x+2\right)-15\left(x+2\right)\)
\(=\left(x+2\right)\left(x^2+2x-15\right)=\left(x+2\right)\left(x-3\right)\left(x+5\right)\)
c) \(x^3-6x^2+11x-6=x^3-x^2-5x^2+5x+6x-6=x^2\left(x-1\right)-5x\left(x-1\right)+6\left(x-1\right)=\left(x-1\right)\left(x-2\right)\left(x-3\right)\)
1a/ x3+x2+x+1=0
x2(x+1).(x+1)=0
=> x2(x+1)=0 x =1
hoặc =>[
x+1=0 x=-1
b/(x+2)2=x+2
x2+2.x.2+22 =x+2
x+x+4x+4=x+2
6x+4=x+2
....
c/(x+1)(6x2+2x)+(x-1)(6x2+2x)=0
x2-12 + (6x2+2x)2=0
=> x2-1 = 0 x=1
hoặc => [
(6x2+2x)2=0 x= 0
a) \(x^4-30x+31x-30\)
= \(x^4+x-30x^2+30x-30\)
=\(x\left(x^3+1\right)-30\left(x^2-x+1\right)\)
= \(x\left(x+1\right)\left(x^2-x+1\right)-30\left(x^2-x+1\right)\)
= \(\left(x^2-x+1\right)\left(x^2+x-30\right)\)
=