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a)27x2.(y-1)9x3.(1-y)
=27x2.(y-1)+9x3.(y-1)
=9x2(y-1)[3+x]
b)8x3 + 1/27
=(2x)3 + (\(\frac{1}{3}\))3
= (2x+\(\frac{1}{3}\))(\(\left(2x\right)^2-\frac{2}{3}x+\left(\frac{1}{3}\right)^2\)
= (2x+\(\frac{1}{3}\))(\(\left(2x\right)^2-\frac{2}{3}x+\left(\frac{1}{3}\right)^2\)
a) 27x2 ( y - 1) - 9x3 ( 1 - y)
=27x2 (y-1) + 9x3 ( y - 1 )
= (27x2 + 9x3) ( y -1 )
=9x2 ( x + 3) ( y - 1)
b)8x3+1/27
\(=\left(2x\right)^3+\left(\frac{1}{3}\right)^3\)
\(=\left(\frac{2x}{9}+\frac{1}{27}\right)\left(36x^2-6x+1\right)\)
c)49 ( y - 4 )2 - 9 ( y + 2)2
= [7(y - 4)]2 - [3(y + 2)]2
= (7y - 28 + 3y + 6)(7y - 28 - 3y - 6)
= (10y - 22)(4y - 34)
= 4(5y - 11)(2y - 34)
a. 27x2 . ( y - 1 ) - 9x3 . ( 1 - y )
= 27x2 ( y - 1 ) + 9x3 ( y - 1 )
= 9x2 ( y - 1 ) ( 3 + x )
b. 8x3 + 1/27
= (2x )3 + ( 1/3 )3
= ( 2x + 1/3 ) ( 4x2 - 2/3x + 9 )
tớ lm câu a thui nha , tại khó quá ^^
a/ \(=3x^6+3x^5+6x^4+3x^3+3x^2-7x^5-7x^4-14x^3-7x^2-7x+3x^4+3x^3+6x^2+3x+1\)
\(=3x^2\left(x^4+x^3+2x^2+x+1\right)-7x\left(x^4+x^3+2x^2+x+1\right)+3\left(x^4+x^3+2x^2+x+1\right)\)
\(=\left(3x^2-7x+3\right)\left(x^4+x^3+x^2+x^2+x+1\right)\)
\(=\left(3x^2-7x+3\right)\left[x^2\left(x^2+x+1\right)+\left(x^2+x+1\right)\right]\)
\(=\left(3x^2-7x+3\right)\left(x^2+1\right)\left(x^2+x+1\right)\)
a) \(4x^2-8x+4-9\left(x-y\right)^2\)
\(=4\left(x^2-2x+1\right)-9\left(x-y\right)^2\)
\(=\left[2\left(x-1\right)\right]^2-\left[3\left(x-y\right)\right]^2\)
\(=\left(2x-2+3x-3y\right)\left(2x-2-3x+3y\right)\)
\(=\left(5x-3y-2\right)\left(3y-x-2\right)\)
b) \(x^3-4x^2+12x-27\)
\(=\left(x^3-27\right)-\left(4x^2-12x\right)\)
\(=\left(x-3\right)\left(x^2+3x+9\right)-4x\left(x-3\right)\)
\(=\left(x-3\right)\left(x^2-x+9\right)\)
b) \(64x^3+1=\left(4x+1\right)\left(16x^2-4x+1\right)\)\
c) \(x^3y^6z^9-125=\left(xy^2z^3-5\right)\left(x^2y^4z^6+5xy^2z+25\right)\)
d) \(27x^6-8x^3=x^3\left(27x^3-8\right)=x^3\left(3x-2\right)\left(9x^2+6x+4\right)\)
e) \(x^6-y^6=\left(x^3-y^3\right)\left(x^3+y^3\right)=\left(x-y\right)\left(x^2+xy+y^2\right)\left(x+y\right)\left(x^2-xy+y^2\right)\)
64x3 + 1
= ( 4x )3 + 1
= ( 4x + 1 ) ( 16x2 - 4x + 1 )
Hằng đẳng thức 6 : A3 + B3
27x6 - 8x3
= ( 3x2)3 + ( 2x )3
= ( 3x + 2x ) ( 9x2 - 6x + 4x2 )
HĐT 6
x6 - y6
= ( x2 )3 - ( y2 )3
= ( x2 - y2 ) ( x4 + x2y2 + y4 )
HĐT 7 : A3 - B3
x3y6z9 + 1
= ( xy2z3)3 + 1
= ( xy2z3 + 1 ) ( x2y4z6 + zy2z3 + 1 )
HĐT 6
a. \(\left(x-5\right)^2-16=x^2-10x+25-16=x\left(x-1\right)-9\left(x-1\right)=\left(x-9\right)\left(x-1\right)\)
b. \(25-\left(3-x\right)^2=25-9+6x-x^2=-x^2-2x+8x+16=-x\left(x+2\right)+8\left(x+2\right)\)
\(=-\left(x-8\right)\left(x+2\right)\)
c. \(\left(7x-4\right)^2-\left(2x+1\right)^2=49x^2-56x+16-4x^2-4x-1=45x^2-60x+15\)
\(=15\left(3x^2-4x+1\right)=15\left(3x-1\right)\left(x-1\right)\)
a) ( x - 5 )2 - 16 = ( x - 5 )2 - 42 = ( x - 5 - 4 )( x - 5 + 4 ) = ( x - 9 )( x - 1 )
b) 25 - ( 3 - x )2 = 52 - ( 3 - x )2 = [ 5 - ( 3 - x ) ][ 5 + ( 3 - x ] = [ 2 + x ][ 8 - x ]
c) ( 7x - 4 )2 - ( 2x + 1 )2 = [ 7x - 4 - ( 2x + 1 ) ][ 7x - 4 + ( 2x + 1 ) ] = [ 5x - 5 ][ 9x - 3 ]
d) 49( y - 4 )2 - 9( y + 2 )2 = 72( y - 4 )2 - 32( y + 2 )2
= [ 7( y - 4 ) ]2 - [ 3( y + 2 ) ]2
= [ 7y - 28 ]2 - [ 3y + 6 ]2
= [ 7y - 28 - ( 3y + 6 ) ][ 7y - 28 + ( 3y + 6 ) ]
= [ 4y - 34 ][ 10y - 22 ]
e) 8x3 + 1/27 = ( 2x )3 + ( 1/3 )3 = ( 2x + 1/3 )( 4x2 - 2/3x + 1/9 )
f) 125 - x6 = 53 - ( x2 )3 = ( 5 - x2 )( 25 + 5x2 + x4 )
a) \(8x^2-12xy+4y^2-2x-1\)
\(=4y^2-8xy-2y-4xy+8x^2+2x+2y-4x-1\)
\(=\left(4y^2-8xy-2y\right)-\left(4xy-8x^2-2x\right)+\left(2y-4x-1\right)\)
\(=2y\left(2y-4x-1\right)-2x\left(2y-4x-1\right)+\left(2y-4x-1\right)\)
\(=\left(2y-2x+1\right)\left(2y-4x-1\right)\)
b) \(4x^4+16\)
\(=4x^4+16x^2+16-16x^2\)
\(=\left(2x^2+4\right)^2-\left(4x\right)^2\)
\(=\left(2x^2+4x+4\right)\left(2x^2-4x+4\right)\)
\(=4\left(x^2+2x+2\right)\left(x^2-2x+2\right)\)
a)49(y-4)2-9(y+2)2
=[7(y-4)]2-[3(y+2)]2
=(7y-28+3y+6)(7y-28-3y-6)
=(10y-22)(4y-34)
=4(5y-11)(2y-34)
b)8x3+1/27
=(2x)3+(1/3)3
=(2x+1/3)[(2x)2-2x.1/3+(1/3)2]
=(2x+1/3)(4x2-2/3x+1/9)
c)125-x6
=53-(x2)3
=(5-x2)(52+5.x2+x4)
=(5-x)(25+5x2+x4)
49(y-4)2-9(y+2)2 = [7(y-4)]2-[3(y+2)]2=[7(y-4)-3(y+2)].[7(y-4)+3(y+2)] = (7y-28-3y-6)(7y-28+3y+6) = (4y-34)(10y-22)=4(2y-17)(5y-11)