Câu hỏi của Uzumaki Naruto

Question

Ko tính kết quả, so sánh A với 3

A = 32/31 + 38/39 + 48/49

Mashiro Shiina · Accepted Answer

$A=\dfrac{32}{31}+\dfrac{38}{39}+\dfrac{48}{49}$

$A=1+\dfrac{1}{31}+1-\dfrac{1}{39}+1-\dfrac{1}{49}$

$A=\left(1+1+1\right)+\left(\dfrac{1}{31}-\dfrac{1}{39}-\dfrac{1}{49}\right)$

$A=3+\left(\dfrac{1}{31}-\dfrac{1}{39}-\dfrac{1}{49}\right)$

$A< 3$

Câu trả lời:

$A=\dfrac{32}{31}+\dfrac{38}{39}+\dfrac{48}{49}$

$A=1+\dfrac{1}{31}+1-\dfrac{1}{39}+1-\dfrac{1}{49}$

$A=\left(1+1+1\right)+\left(\dfrac{1}{31}-\dfrac{1}{39}-\dfrac{1}{49}\right)$

$A=3+\left(\dfrac{1}{31}-\dfrac{1}{39}-\dfrac{1}{49}\right)$

$A< 3$